ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Ò»¶¨Î¶ÈÏ£¬ÔÚ2 LµÄÃܱÕÈÝÆ÷ÖУ¬X¡¢Y¡¢ZÈýÖÖÆøÌåµÄÁ¿Ëæʱ¼ä±ä»¯µÄÇúÏßÈçÈçͼËùʾ£º
£¨1£©´Ó·´Ó¦¿ªÊ¼µ½10 sʱ£¬ÓÃZ±íʾµÄ·´Ó¦ËÙÂÊΪ________£¬XµÄÎïÖʵÄÁ¿Å¨¶È¼õÉÙÁË______£¬YµÄת»¯ÂÊΪ________¡£
£¨2£©¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_______________________________________________¡£
£¨3£©10 sºóµÄijһʱ¿Ì(t1)¸Ä±äÁËÍâ½çÌõ¼þ£¬ÆäËÙÂÊËæʱ¼äµÄ±ä»¯Í¼ÏñÈçÈçͼËùʾ¡£ÔòÏÂÁÐ˵·¨·ûºÏ¸ÃͼÏñµÄÊÇ________¡£
A£®t1ʱ¿Ì£¬Ôö´óÁËXµÄŨ¶È
B£®t1ʱ¿Ì£¬Éý¸ßÁËÌåϵζÈ
C£®t1ʱ¿Ì£¬ËõСÁËÈÝÆ÷Ìå»ý
D£®t1ʱ¿Ì£¬Ê¹ÓÃÁË´ß»¯¼Á
¡¾´ð°¸¡¿
£¨1£© 0.079 mol/(L¡¤s)£»0.395 mol/L£»79.0%
£¨2£© X(g)£«Y(g) 2Z(g)£»
£¨3£© CD
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£ºÍ¼Ïó·ÖÎö¿ÉÖªÆðʼÁ¿Îª£ºX=1.2mol£¬Y=1.00mol£¬Z=1.58mol£¬10s´ïµ½Æ½ºâ״̬xyzµÄÎïÖʵÄÁ¿Îª£º0.41mol£¬0.21mol£¬1.58mol£¬¡÷X=1.2mol-0.41mol=0.79mol£¬¡÷Y=1.00mol-0.21mol=0.79mol£¬¡÷Z=1.58mol¡£
£¨1£©·´Ó¦ËÙÂÊv(Z)===0.079mol/(Ls)£¬XµÄŨ¶È¼õСc== =0.395mol/L£¬Yת»¯ÂÊ=¡Á100%=¡Á100%=79%£»¹Ê´ð°¸Îª£º0.079mol/(Ls)£»0.395mol/L£»79%£»
£¨2£©n(X)£ºn(Y)£ºn(Z)=0.79£º0.79£º1.58=1£º1£º2£¬·´Ó¦µÄ»¯Ñ§·½³Ìʽ¼ÆÁ¿ÊýÖ®±ÈµÈÓÚÎïÖʲμӷ´Ó¦µÄÎïÖʵÄÁ¿Ö®±È£¬¿ÉÖª»¯Ñ§·½³ÌʽΪ£ºX+Y2Z£¬¹Ê´ð°¸Îª£ºX+Y2Z
£¨3£©ÓÉͼÏó¿ÉÖªÕýÄæ·´Ó¦ËÙÂÊÔö´ó£¬Æ½ºâûÒƶ¯£»A£®t1ʱ¿Ì£¬Ôö´óÁËXµÄŨ¶È£¬Æ½ºâÕýÒÆ£¬²»·ûºÏÌâÒ⣬¹ÊA´íÎó£»B£®t1ʱ¿Ì£¬Éý¸ßÁËÌåϵζȣ¬Æ½ºâÒƶ¯£¬²»·ûºÏÌâÒ⣬¹ÊB´íÎó£»C£®t1ʱ¿Ì£¬ËõСÁËÈÝÆ÷Ìå»ý£¬ËÙÂÊÔö´ó£¬ÓÉÓÚ·´Ó¦Ç°ºó¼ÆÁ¿ÊýÏàµÈ£¬Æ½ºâ²»Òƶ¯£¬·ûºÏÌâÒ⣬¹ÊCÕýÈ·£»D£®t1ʱ¿Ì£¬Ê¹ÓÃÁË´ß»¯¼Á£¬ËÙÂÊÔö´ó£¬Æ½ºâ²»Òƶ¯£¬·ûºÏÌâÒ⣬¹ÊDÕýÈ·£»¹Ê´ð°¸Îª£ºCD¡£
¡¾ÌâÄ¿¡¿ÏÖÓÐһƿÎïÖʼ׺ÍÒҵĻìºÏÎÒÑÖª¼×ºÍÒÒµÄijЩÐÔÖÊÈç±íËùʾ£º
ÎïÖÊ | ·Ö×Óʽ | ÈÛµã(¡æ) | ·Ðµã(¡æ) | ÃÜ¶È (g¡¤cm£3) | Ë®ÖеÄÈܽâÐÔ |
¼× | C3H6O2 | £98 | 57.5 | 0.93 | ¿ÉÈÜ |
ÒÒ | C4H8O2 | £84 | 77 | 0.90 | ¿ÉÈÜ |
¾Ý´Ë£¬½«¼×ºÍÒÒ·ÖÀëµÄ×î¼Ñ·½·¨ÊÇ
A£®ÝÍÈ¡·¨ B£®Éý»ª·¨ C£®ÕôÁó·¨ D£®·ÖÒº·¨