ÌâÄ¿ÄÚÈÝ

¸ù¾ÝÔ­×ӽṹ¡¢ÔªËØÖÜÆÚ±íºÍÔªËØÖÜÆÚÂɵÄ֪ʶ»Ø´ðÏÂÁÐÎÊÌ⣺
(1)BÊÇ1¡«36ºÅÔªËØÔ­×ÓºËÍâµç×ÓÅŲ¼ÖÐδ³É¶Ôµç×ÓÊý×î¶àµÄÔªËØ£¬BÔªËصÄÃû³ÆÊÇ____£¬ÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃÊÇ____________________¡£
(2)CÔªËØ»ù̬ԭ×ӵĵç×ÓÅŲ¼Í¼ÊÇÏÂͼÖеÄ_______(ÌîÐòºÅ)£¬ÁíÒ»µç×ÓÅŲ¼Í¼²»ÄÜ×÷Ϊ»ù̬ԭ×ӵĵç×ÓÅŲ¼Í¼ÊÇÒòΪËü²»·ûºÏ_______(´ÓA B CÖÐÑ¡Ôñ)¡£

A.ÄÜÁ¿×îµÍÔ­Àí    B.ÅÝÀûÔ­Àí   C.ºéÌعæÔò
£¨3£©ÒÀ¾ÝÕý¸º»¯ºÏ¼Û´úÊýºÍµÈÓÚ0£¬HÔªËØ¿ÉÒÔ·ÅÔÚÖÜÆÚ±íÖеĠ       ×å
(4)ÂÈ»¯ï§µÄµç×Óʽ        
£¨10·Ö£© (1) ¸õ µÚËÄÖÜÆÚ¡¢µÚ¢öB×å, (2) ¢Ú¡¡C (3) ¢ôA £¨4£©

ÊÔÌâ·ÖÎö£º(1)¸ù¾ÝºËÍâµç×ÓµÄÅŲ¼Ê½¿ÉÖª£¬1¡«36ºÅÔªËØÔ­×ÓºËÍâµç×ÓÅŲ¼ÖÐδ³É¶Ôµç×ÓÊý×î¶àµÄÔªËØÊǸõ£¬Î»ÓÚµÚËÄÖÜÆÚµÚ¢öB×å¡£
£¨2£©Ôڵȼ۹ìµÀ(Ö¸Ïàͬµç×Ӳ㡢µç×ÓÑDzãÉϵĸ÷¸ö¹ìµÀ)ÉÏÅŲ¼µÄµç×Ó½«¾¡¿ÉÄÜ·ÖÕ¼²»Í¬µÄ¹ìµÀ,ÇÒ×ÔÐý·½ÏòÏàͬ£¬Õâ¾ÍÊǺéÌعæÔò£¬ÏÔÈ»¢Ù²»·ûºÏºéÌعæÔò£¬ÕýÈ·µÚÅŲ¼Í¼ÊÇ¢Ú¡£
£¨3£©ÒÀ¾ÝÕý¸º»¯ºÏ¼Û´úÊýºÍµÈÓÚ0¿ÉÖª£¬HÔªËصÄ×î¸ß¼ÛÊÇ£«1¼Û¡¢×îµÍ¼ÛÊÇ£­1¼Û£¬ËùÒÔÇâÔªËØ¿ÉÒÔ·ÅÔÚÖÜÆÚ±íÖеĢôA×å¡£
£¨4£©ÂÈ»¯ï§ÊǺ¬ÓÐÀë×Ó¼üµÄÀë×Ó»¯ºÏÎµç×ÓʽÊÇ¡£
µãÆÀ£º¸ÃÌâÊÇ»ù´¡ÐÔÊÔÌâµÄ¿¼²é£¬Ò²ÊǸ߿¼Öеij£¼û¿¼µã£¬ÄѶȲ»´ó£¬ÊÔÌâ»ù´¡ÐÔÇ¿£¬²àÖضÔѧÉú»ù´¡ÖªÊ¶µÄ¹®¹ÌºÍѵÁ·£¬Ö¼ÔÚ¿¼²éѧÉúÁé»îÔËÓûù´¡ÐÔ֪ʶ½â¾öʵ¼ÊÎÊÌâµÄÄÜÁ¦£¬ÓÐÀûÓÚÅàÑøѧÉúµÄÂß¼­ÍÆÀíÄÜÁ¦ºÍ·¢É¢Ë¼Î¬ÄÜÁ¦¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÔªËØÖÜÆÚ±íÓëÔªËØÖÜÆÚÂÉÔÚѧϰ¡¢Ñо¿ºÍÉú²úʵ¼ùÖÐÓкÜÖØÒªµÄ×÷Óá£Ï±íÁгöÁË¢Ù¡«¢á¾ÅÖÖÔªËØÔÚÖÜÆÚ±íÖеÄλÖá£Çë»Ø´ð£º
×å
ÖÜÆÚ
¢ñA
¢òA
¢óA
¢ôA
¢õA
¢öA
¢÷A
0
2
 
 
 
¢Ý
 
¢Þ
 
 
3
¢Ù
¢Û
¢Ü
 
 
 
¢ß
¢á
4
¢Ú
 
 
 
 
 
¢à
 
(1)Õâ¾ÅÖÖÔªËØÖÐ(ÌîÔªËØ·ûºÅ)¢ÝÊÇ       £¬ÆäÖл¯Ñ§ÐÔÖÊ×î²»»îÆõÄÊÇ      ¡£
¢ÝºÍ¢ÞÐγɻ¯ºÏÎïµÄµç×Óʽ                         
(2)ÔÚÕâЩԪËصÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïÖУ¬¼îÐÔ×îÇ¿µÄÊÇ(Ìѧʽ)¡£         
ËáÐÔ×îÇ¿µÄÊÇ            ³ÊÁ½ÐÔµÄÊÇ            £¬Ð´³öÈýÕßÖ®¼äÏ໥·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                                                 £»
                                                             
                                                              
(3)¢Ù¡¢¢Ú¡¢¢ÛÈýÖÖÔªËØ°´Ô­×Ӱ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòÒÀ´ÎΪ          (ÌîÔªËØ·ûºÅ)¡£
(4) Óõç×Óʽ±íʾ¢àÔªËØÓë¢ÛÔªËØÐγɻ¯ºÏÎïµÄ¹ý³Ì                            ¡£
(5) Ôڢٺ͢ÚÖл¯Ñ§ÐÔÖÊ×î»îÆõÄÊÇ    
(6)Ôڢߺ͢àÖл¯Ñ§ÐÔÖÊ×î»îÆõÄÊÇ      £¬Óû¯Ñ§ÊµÑéÖ¤Ã÷µÄ·½·¨ºÍÀë×Ó·½³Ìʽ£º
·½·¨                                           
Àë×Ó·½³Ìʽ                                          
¢ñ µªÔªËØ¿ÉÒÔÐγɶàÖÖ»¯ºÏÎï¡£»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©»ù̬µªÔ­×ӵļ۵ç×ÓÅŲ¼Í¼ÊÇ_________________¡£
£¨2£©C¡¢N¡¢O ÈýÖÖÔªËصÚÒ»µçÀëÄÜ´Ó´óµ½Ð¡µÄ˳ÐòÊÇ____________¡£
£¨3£©ëÂ(N2H4)·Ö×Ó¿ÉÊÓΪNH3·Ö×ÓÖеÄÒ»¸öÇâÔ­×Ó±»£­NH2£¨°±»ù£©È¡´úÐγɵÄÁíÒ»ÖÖµªµÄÇ⻯Îï¡£
¢ÙNH3·Ö×ӵĿռ乹ÐÍÊÇ_______________£»N2H4·Ö×ÓÖеªÔ­×Ó¹ìµÀµÄÔÓ»¯ÀàÐÍÊÇ___________¡£
¢Úë¿ÉÓÃ×÷»ð¼ýȼÁÏ£¬È¼ÉÕʱ·¢ÉúµÄ·´Ó¦ÊÇ£º
N2O4(l)£«2N2H4(l)===3N2(g)£«4H2O(g)   ¡÷H=£­1038.7kJ¡¤mol£­1
Èô¸Ã·´Ó¦ÖÐÓÐ4mol N£­H ¼ü¶ÏÁÑ£¬ÔòÐγɵĦР¼üÓÐ________mol¡£
¢ò ½ðÊôÄøÔÚµç³Ø¡¢ºÏ½ð¡¢´ß»¯¼ÁµÈ·½ÃæÓ¦Óù㷺¡£
£¨4£©µÚ¶þÖÜÆÚ»ù̬ԭ×Óδ³É¶Ôµç×ÓÊýÓëNiÏàͬÇҵ縺ÐÔ×îСµÄÔªËØÊÇ______¡£
£¨5£©¼×È©£¨H2C£½O£©ÔÚNi ´ß»¯×÷ÓÃϼÓÇâ¿ÉµÃ¼×´¼£¨CH3OH£©¡£¼×È©·Ö×ÓÄÚC Ô­×ÓµÄÔÓ»¯·½Ê½Îª________¡£
¢ó µª¿ÉÒÔÐγɶàÖÖÀë×Ó£¬ÈçN3£­£¬NH2£­£¬N3£­£¬NH4+£¬N2H5+£¬N2H62+µÈ£¬ÒÑÖªN2H5+ÓëN2H62+ÊÇÓÉÖÐÐÔ·Ö×Ó½áºÏÖÊ×ÓÐγɵģ¬ÀàËÆÓÚNH4+£¬Òò´ËÓÐÀàËÆÓÚ NH4+µÄÐÔÖÊ¡£
£¨6£©Ð´³öN2H62+Óë¼îÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ                                            £»
£¨7£©Ð´³öN3£­µÈµç×ÓÌåÎïÖʵĻ¯Ñ§Ê½                                      £»£¨Ò»ÖÖ£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø