ÌâÄ¿ÄÚÈÝ

ÔªËØÖÜÆÚ±íÓëÔªËØÖÜÆÚÂÉÔÚѧϰ¡¢Ñо¿ºÍÉú²úʵ¼ùÖÐÓкÜÖØÒªµÄ×÷Óá£Ï±íÁгöÁË¢Ù¡«¢á¾ÅÖÖÔªËØÔÚÖÜÆÚ±íÖеÄλÖá£Çë»Ø´ð£º
×å
ÖÜÆÚ
¢ñA
¢òA
¢óA
¢ôA
¢õA
¢öA
¢÷A
0
2
 
 
 
¢Ý
 
¢Þ
 
 
3
¢Ù
¢Û
¢Ü
 
 
 
¢ß
¢á
4
¢Ú
 
 
 
 
 
¢à
 
(1)Õâ¾ÅÖÖÔªËØÖÐ(ÌîÔªËØ·ûºÅ)¢ÝÊÇ       £¬ÆäÖл¯Ñ§ÐÔÖÊ×î²»»îÆõÄÊÇ      ¡£
¢ÝºÍ¢ÞÐγɻ¯ºÏÎïµÄµç×Óʽ                         
(2)ÔÚÕâЩԪËصÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïÖУ¬¼îÐÔ×îÇ¿µÄÊÇ(Ìѧʽ)¡£         
ËáÐÔ×îÇ¿µÄÊÇ            ³ÊÁ½ÐÔµÄÊÇ            £¬Ð´³öÈýÕßÖ®¼äÏ໥·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                                                 £»
                                                             
                                                              
(3)¢Ù¡¢¢Ú¡¢¢ÛÈýÖÖÔªËØ°´Ô­×Ӱ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòÒÀ´ÎΪ          (ÌîÔªËØ·ûºÅ)¡£
(4) Óõç×Óʽ±íʾ¢àÔªËØÓë¢ÛÔªËØÐγɻ¯ºÏÎïµÄ¹ý³Ì                            ¡£
(5) Ôڢٺ͢ÚÖл¯Ñ§ÐÔÖÊ×î»îÆõÄÊÇ    
(6)Ôڢߺ͢àÖл¯Ñ§ÐÔÖÊ×î»îÆõÄÊÇ      £¬Óû¯Ñ§ÊµÑéÖ¤Ã÷µÄ·½·¨ºÍÀë×Ó·½³Ìʽ£º
·½·¨                                           
Àë×Ó·½³Ìʽ                                          
£¨1£©C    Ar   
£¨2£© KOH    HClO4   Al(OH)3         KOH +HClO4£½KClO4 +H2O   KOH + Al(OH)3£½KAlO2 +2H2O
(3) K£¾Na£¾Mg    (4)£¨5£©K 
(6)  Cl  È¡ÊÊÁ¿ä廯ÄÆÈÜÒºµÎÈëÂÈË®£¬ÈÜÒº±äΪ³È»ÆÉ«£¬Ôò·Ç½ðÊôÐÔCl£¾Br   Cl2 + 2Br-£½ 2Cl- + Br2

ÊÔÌâ·ÖÎö£º£¨1£©¸ù¾ÝÔªËØÔÚÖÜÆÚ±íÖеÄÏà¶ÔλÖÿÉÖª¢Ù¡«¢á¾ÅÖÖÔªËØ·Ö±ðÊÇNa¡¢K¡¢Mg¡¢Al¡¢C¡¢O¡¢Cl¡¢Br¡¢Ar¡£ArÊÇÏ¡ÓÐÆøÌåÔªËØ£¬»¯Ñ§ÐÔÖÊ×î²»»îÆᣢݺ͢ÞÐγɻ¯ºÏÎïÊÇCO2£¬º¬Óй²¼Û¼üµÄ¹²¼Û»¯ºÏÎÆäµç×ÓʽÊÇ¡£
£¨2£©½ðÊôÐÔ»ò·Ç½ðÊôÐÔԽǿ£¬×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄ¼îÐÔ»òËáÐÔԽǿ£¬ÔòKOHµÄ¼îÐÔ×îÇ¿£¬HClO4µÄËáÐÔ×îÇ¿£¬ Al(OH)3ÊÇÁ½ÐÔÇâÑõ»¯Îï¡£
£¨3£©Í¬ÖÜÆÚ×Ô×óÏòÓÒÔ­×Ӱ뾶Öð½¥¼õС£¬Í¬Ö÷×å×ÔÉ϶øÏÂÔ­×Ӱ뾶Öð½¥Ôö´ó£¬ÔòÈýÖÖÔªËصÄÔ­×Ӱ뾶´óС˳ÐòÊÇK£¾Na£¾Mg¡£
£¨4£©Ê¾¢àÔªËØÓë¢ÛÔªËØÐγɻ¯ºÏÎïÊÇä廯þ£¬º¬ÓÐÀë×Ó¼ü£¬ÆäÐγɹý³Ì¿É±íʾΪ¡£
£¨5£©Í¬Ö÷×å×ÔÉ϶øÏ£¬½ðÊôÐÔÖð½¥ÔöÇ¿£¬ËùÒÔKµÄ½ðÊôÐÔÇ¿ÓÚNaµÄ½ðÊôÐÔ¡£
£¨6£©Í¬Ö÷×å×ÔÉ϶øÏ£¬·Ç½ðÊôÐÔÖð½¥¼õÈõ£¬ËùÒÔClµÄ·Ç½ðÊôÐÔÇ¿ÓÚBrµÄ·Ç½ðÊôÐÔ¡£¿É¸ù¾Ý·Ç½ðÊôÐÔÇ¿µÄµ¥ÖÊת»»Èõ£¬¼´È¡ÊÊÁ¿ä廯ÄÆÈÜÒºµÎÈëÂÈË®£¬ÈÜÒº±äΪ³È»ÆÉ«£¬Ôò·Ç½ðÊôÐÔCl£¾Br£¬ËùÒÔµÄÀë×Ó·½³ÌʽÊÇCl2 + 2Br-£½2Cl- + Br2¡£
µãÆÀ£º¸ÃÌâÊÇ»ù´¡ÐÔÊÔÌâµÄ¿¼²é£¬²àÖضÔѧÉú»ù´¡ÖªÊ¶¹®¹ÌºÍѵÁ·µÄͬʱ£¬Ö¼ÔÚ¿¼²éѧÉúÁé»îÔËÓûù´¡ÖªÊ¶½â¾öʵ¼ÊÎÊÌâµÄÄÜÁ¦£¬ÓÐÀûÓÚÅàÑøѧÉúµÄÂß¼­ÍÆÀíÄÜÁ¦ºÍ¹æ·¶´ðÌâÄÜÁ¦¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

A
 
 
B
 
 
 
C
D
E
F
 
G
 
H
 
 
 
I
 

a

 

 
 
 
 
 

b

 

 
 
 
 
 
 
 

c

 

 

d

 

 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
£¨1£©ÔÚÉÏÃæÔªËØÖÜÆÚ±íÖÐÈ«²¿ÊǽðÊôÔªËصÄÇøÓòΪ            ¡£
£¨A£©a £¨B£©b £¨C£©c £¨D£©d
£¨2£©GÔªËØÓë EÔªËØÐγɵĻ¯ºÏÎïÖÐÒõÑôÀë×Ó¸öÊý±ÈΪ1:1µÄÎïÖʵĻ¯Ñ§Ê½ÊÇ         £¬
±í¸ñÖоÅÖÖÔªËصÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïÖУ¬¼îÐÔ×îÇ¿µÄ»¯ºÏÎïµÄµç×ÓʽÊÇ       £¬ËáÐÔ×îÇ¿µÄÊÇ         £¨Óû¯ºÏÎïµÄ»¯Ñ§Ê½±íʾ£¬ÏÂͬ£©£¬ÊôÓÚÁ½ÐÔÇâÑõ»¯ÎïµÄÊÇ         ¡£
£¨3£©C¡¢D¡¢E¡¢FËÄÖÖÔªËØÖУ¬Æø̬Ç⻯ÎïÎȶ¨ÐÔ×î²îµÄÎïÖʵĿռä½á¹¹Îª           ¡£
£¨4£©G¡¢HÁ½ÔªËØÏà±È½Ï£¬½ðÊôÐÔ½ÏÇ¿µÄÊÇ         £¨ÌîÃû³Æ£©£¬¿ÉÒÔÑéÖ¤¸Ã½áÂÛµÄʵÑéÊÇ      ¡££¨Ìî±àºÅ£©
£¨a£©¿´ÄÇÖÖÔ­×ÓʧȥµÄµç×ÓÔ½¶à£¬½ðÊôÐÔԽǿ¡£
£¨b£©½«ÕâÁ½ÖÖÔªËصĵ¥ÖÊ·ÛÄ©·Ö±ðºÍͬŨ¶ÈµÄÑÎËá·´Ó¦
£¨c£©½«ÕâÁ½ÖÖÔªËصĵ¥ÖÊ·ÛÄ©·Ö±ðºÍÈÈË®×÷Ó㬲¢µÎÈë·Ó̪ÈÜÒº
£¨d£©±È½ÏÕâÁ½ÖÖÔªËصÄÆø̬Ç⻯ÎïµÄÎȶ¨ÐÔ
ϱíΪԪËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬Çë²ÎÕÕÔªËآ٣­¢áÔÚ±íÖеÄλÖã¬Óû¯Ñ§ÓÃÓï»Ø´ðÏÂÁÐÎÊÌ⣺
×å
ÖÜÆÚ
IA
 
0
1
¢Ù
¢òA
¢óA
¢ôA
¢õA
¢öA
¢÷A
 
2
 
 
 
¢Ú
¢Û
¢Ü
 
 
3
¢Ý
 
¢Þ
 
 
¢ß
¢à
¢á
£¨1£©ÔªËØ¢ÚÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ                 
£¨2£©ÔÚ¢Ù¡«¢áÔªËØÖУ¬½ðÊôÐÔ×îÇ¿µÄÔªËØÊÇ       £¬·Ç½ðÊôÐÔ×îÇ¿µÄÔªËØÊÇ        ¡££¨¾ùÌîÔªËØ·ûºÅ£©
£¨3£©ÔªËØ¢ßÓëÔªËØ¢àÏà±È£¬¢àµÄ·Ç½ðÊôÐÔ½ÏÇ¿£¬ÏÂÁбíÊöÖÐÄÜÖ¤Ã÷ÕâÒ»ÊÂʵµÄÊÇ   ¡¡¡¡
a£®³£ÎÂÏ¢ߵĵ¥Öʺ͢àµÄµ¥ÖÊ״̬²»Í¬¡¡¡¡
b£®¢àµÄÇ⻯Îï±È¢ßµÄÇ⻯ÎïÎȶ¨
c£®Ò»¶¨Ìõ¼þÏ¢ߺ͢àµÄµ¥Öʶ¼ÄÜÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦
d£®¢ßµÄÑõ»¯ÎïµÄË®»¯Îï±È¢àµÄÑõ»¯ÎïµÄË®»¯ÎïËáÐÔÈõ
Éè¼ÆÒ»¸ö¼òµ¥ÊµÑ飬֤Ã÷ÔªËØ¢ßÓëÔªËØ¢àµÄ·Ç½ðÊôÐÔÇ¿Èõ£¬Çëд³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ__________
£¨4£©¢ÝÓë¢ÞÁ½ÔªËØ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÏ໥·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____________________
£¨5£©¢ÛµÄÇ⻯ÎïµÄµç×ÓʽΪ__________________
¢Ù¢Ü¢ÝÈýÖÖÔªËØÐγɵÄ×î¼òµ¥Ò»ÖÖ»¯ºÏÎﺬÓеĻ¯Ñ§¼üÀàÐÍÓР             

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø