ÌâÄ¿ÄÚÈÝ

ÒÑÖª¶ÌÖÜÆÚµÄÖ÷×åÔªËØX¡¢Y¡¢Z¡¢W¡¢MµÄÔ­×ÓÐòÊýÒÀ´ÎÔö´ó£¬XÊÇ¿ÕÆøÖк¬Á¿×î
¶àµÄÔªËØ£¬Æäµ¥ÖʵĻ¯Ñ§ÐÔÖʷdz£Îȶ¨£¬YÔ­×ÓµÄ×îÍâ²ãÖ»ÓÐ2¸öµç×Ó£¬Zµ¥ÖÊ¿ÉÖƳɰ뵼Ìå²ÄÁÏ£¬WÔªËØÐγɵĵ¥ÖÊΪµ­»ÆÉ«µÄ¹ÌÌ壬MÔªËØÐγɵĵ¥ÖÊΪ»ÆÂÌÉ«ÆøÌ壮Çë»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©XÔªËصķûºÅÊÇ        ,ËüÔÚÖÜÆÚ±íµÄλÖÃΪ              £»
£¨2£©ZµÄÑõ»¯ÎᄃÌåÀàÐÍΪ         ,»¯Ñ§Ê½ÊÇ:                £»
£¨3£©XÓëYÄÜÐγÉÀë×Ó»¯ºÏÎ¸Ã»¯ºÏÎïµÄµç×ÓʽΪ                  £»
£¨4£©XµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÓëYµÄÑõ»¯Îï·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ           £»
£¨5£©X¡¢WÐγɵÄÇ⻯Îï·Ö±ðΪ¼×ºÍÒÒ£¬ÇҼס¢ÒÒËùº¬µÄµç×ÓÊýÏàµÈ£¬Ôò¼×µÄ½á¹¹Ê½Îª                   £»
£¨6£©WºÍM¶¼ÊǽϻîÆõķǽðÊôÔªËØ£¬ÓÃʵÑéÊÂʵ±íÃ÷ÕâÁ½ÖÖÔªËصķǽðÊôÐÔÇ¿Èõ£¨Ó÷½³ÌʽÊéд»òÎÄ×Ö˵Ã÷£©                         ¡£
£¨1£©N£¬µÚ¶þÖÜÆÚµÚ¢õA×壨2£©Ô­×Ó¾§Ìå £¬SiO2
£¨3£©
£¨4£©2HNO3+MgO=Mg(NO3)2+2H2O     
£¨5£© 
£¨6£©Cl2+H2S=2HCl+S£¬

ÊÔÌâ·ÖÎö£ºXÊÇ¿ÕÆøÖк¬Á¿×î¶àµÄÔªËØ£¬XΪµªÔªËØ£»Zµ¥ÖÊ¿ÉÖƳɰ뵼Ìå²ÄÁÏ£¬ZΪ¹èÔªËØ£»ÔòYÊÇþԪËØ£»WÔªËØÐγɵĵ¥ÖÊΪµ­»ÆÉ«µÄ¹ÌÌ壬MÔªËØÐγɵĵ¥ÖÊΪ»ÆÂÌÉ«ÆøÌ壬ÔòW¡¢MΪÁò¡¢ÂÈ¡£
£¨1£©XÔªËØ·ûºÅÊÇN£¬ÊǵÚÈýÖÜÆÚµÚ¢õA×åÔªËØ£»
£¨2£©ZµÄÑõ»¯ÎïÊÇSiO2£¬ÊôÓÚÔ­×Ó¾§Ì壻
£¨3£©XÓëYÐγɵÄÀë×Ó»¯ºÏÎïΪMg3N2µç×ÓʽΪ
£¨4£©XµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÊÇHNO3£¬YµÄÑõ»¯ÎïÊÇMgO£¬¶þÕß·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2HNO3+MgO=Mg(NO3)2+2H20£»
£¨5£©X¡¢WÐγɵÄÇ⻯Îï·Ö±ðΪ¼×ºÍÒÒ£¬ÇҼס¢ÒÒËùº¬µÄµç×ÓÊýÏàµÈ£¬¼×ΪN2H4£¬ÒÒΪH2S, N2H4µÄ½á¹¹Ê½Îª£»
£¨6£©SµÄ·Ç½ðÊôÐÔ±ÈClµÄÈõ£¬¿ÉÓÃCl2ºÍH2S·´Ó¦Öû»S¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
¿ª·¢ÐÂÐÍ´¢Çâ²ÄÁÏÊÇÇâÄÜÀûÓõÄÖØÒªÑо¿·½Ïò¡£
£¨1£©Ti(BH4)3ÊÇÒ»ÖÖ´¢Çâ²ÄÁÏ£¬¿ÉÓÉTiCl4ºÍLiBH4·´Ó¦ÖƵá£
¢Ù»ù̬Ti3+µÄδ³É¶Ôµç×ÓÊýÓÐ______¸ö¡£
¢ÚLiBH4ÓÉLi+ºÍBH4-¹¹³É£¬BH4-µÄµÈµç×ÓÌåÊÇ   £¨Ð´Ò»ÖÖ£©¡£LiBH4Öв»´æÔÚµÄ×÷ÓÃÁ¦ÓÐ___(Ìî±êºÅ)¡£
A£®Àë×Ó¼ü      B£®¹²¼Û¼ü  C£®½ðÊô¼ü     D£®Åäλ¼ü
¢ÛLi¡¢B¡¢HÔªËصĵ縺ÐÔÓÉ´óµ½Ð¡ÅÅÁÐ˳ÐòΪ_          _____¡£
£¨2£©½ðÊôÇ⻯ÎïÊǾßÓÐÁ¼ºÃ·¢Õ¹Ç°¾°µÄ´¢Çâ²ÄÁÏ¡£
¢ÙLiHÖУ¬Àë×Ӱ뾶£ºLi+______H£­(Ìî¡°£¾¡±¡¢¡°£½¡±»ò¡°£¼¡±£©¡£
¢Úij´¢Çâ²ÄÁÏÊǶÌÖÜÆÚ½ðÊôÔªËØMµÄÇ⻯Îï¡£MµÄ²¿·ÖµçÀëÄÜÈçϱíËùʾ£º
I1/KJ¡¤mol-1
I2/KJ¡¤mol-1
I3/KJ¡¤mol-1
I4/KJ¡¤mol-1
I5/KJ¡¤mol-1
738
1451
7733
10540
13630
 
MÊÇ______(ÌîÔªËØ·ûºÅ£©¡£
£¨3£©Ä³ÖÖÐÂÐÍ´¢Ñõ²ÄÁϵÄÀíÂ۽ṹģÐÍÈçÏÂͼËùʾ£¬Í¼ÖÐÐéÏß¿òÄÚ̼ԭ×ÓµÄÔÓ»¯¹ìµÀÀàÐÍÓÐ____ÖÖ¡£

£¨4£©ÈôÒÑÖªÔªËص縺ÐÔ·ú´óÓÚÑõ£¬ÊÔ½âÊͷеãH2O¸ßÓÚHF            ¡£
·Ö×ÓX¿ÉÒÔͨ¹ýÇâ¼üÐγɡ°Áý×´½á¹¹¡±¶ø³ÉΪDZÔڵĴ¢Çâ²ÄÁÏ¡£X¡ª¶¨²»ÊÇ______(Ìî±êºÅ)¡£
A£®H2O   B£®CH4   C£®HF      D£®CO(NH2)2
£¨5£©ÄÉÃײÄÁϵıíÃæÁ£×ÓÊýÕ¼×ÜÁ£×ÓÊýµÄ±ÈÀý¼«´ó£¬ÕâÊÇËü¾ßÓÐÐí¶àÌØÊâÐÔÖʵÄÔ­Òò¡£¼ÙÉèijÂÈ»¯ÄÆÄÉÃ׿ÅÁ£µÄ´óСºÍÐÎ×´Ç¡ºÃÓëÂÈ»¯Äƾ§°ûµÄ´óСºÍÐÎ×´Ïàͬ¡£ÔòÕâÖÖÄÉÃ׿ÅÁ£µÄ±íÃæÁ£×ÓÊýÕ¼×ÜÁ£×ÓÊýµÄ°Ù·ÖÊýΪ     ¡£

A£®87£®5£¥         B£®92£®9£¥       C£®96£®3£¥        D£®100£¥
A¡¢B¡¢C¡¢E¡¢FΪԭ×ÓÐòÊýÒÀ´ÎÔö´óµÄÁùÖÖÔªËØ£¬ÆäÖÐA¡¢B¡¢C¡¢D¡¢EΪ¶ÌÖÜÆÚÔªËØ£¬FΪµÚËÄÖÜÆÚÔªËØ£¬F»¹ÊÇÇ°ËÄÖÜÆÚÖе縺¼«×îСµÄÔªËØ¡£
ÒÑÖª£º
AÔ­×ӵĺËÍâµç×ÓÊýÓëµç×Ó²ãÊýÏàµÈ£»
BÔªËØÔ­×ӵĺËÍâpµç×ÓÊý±Èsµç×ÓÊýÉÙ1¸ö£»
CÔ­×ӵĵÚÒ»ÖÁµÚËĵçÀëÄÜΪI1£½738 kJ/mol£¬I2£½1451 kJ/mol£¬I3£½7733 kJ/mol£¬I4£½10540 kJ/mol£»
DÔ­×ÓºËÍâËùÓÐp¹ìµÀΪȫ³äÂú»ò°ë³äÂú£»
EÔªËصÄ×åÐòÊýÓëÖÜÆÚÐòÊýµÄ²îΪ4£»
(1)д³öEÔªËØÔÚÖÜÆÚ±íλÖãº________£»DÔªËصÄÔ­×ӵĺËÍâµç×ÓÅŲ¼Ê½£º____________________¡£
(2)ijͬѧ¸ù¾ÝÌâÄ¿ÐÅÏ¢ºÍÕÆÎÕµÄ֪ʶ·ÖÎöCµÄºËÍâµç×ÓÅŲ¼Îª

¸ÃͬѧËù»­µÄ¹ìµÀʽΥ±³ÁË________¡£

(3)ÒÑÖªBA5ΪÀë×Ó»¯ºÏÎд³öÆäµç×Óʽ£º______________¡£
(4)DE3ÖÐÐÄÔ­×ÓÔÓ»¯·½Ê½Îª__________________£¬Æä¿Õ¼ä¹¹ÐÍΪ______________¡£
(5)ij½ðÊô¾§ÌåÖÐÔ­×Ӷѻý·½Ê½Èçͼ¼×£¬¾§°ûÌØÕ÷ÈçͼÒÒ£¬Ô­×ÓÏà¶ÔλÖùØϵÈçͼ±û£¬Ôò¾§°ûÖиÃÔ­×ÓÅäλÊýΪ________£»¿Õ¼äÀûÓÃÂÊΪ________£»¸Ã¾§ÌåµÄÃܶÈΪ________¡£(ÒÑÖª¸Ã½ðÊôÏà¶ÔÔ­×ÓÖÊÁ¿Îªm£¬Ô­×Ӱ뾶Ϊa cm)
A¡¢B¡¢C¡¢DÊÇÔªËØÖÜÆÚ±íÖÐÇ°36ºÅÔªËØ£¬ËüÃǵĺ˵çºÉÊýÒÀ´ÎÔö´ó¡£µÚ¶þÖÜÆÚÔªËØAÔ­×ӵĺËÍâ³É¶Ôµç×ÓÊýÊÇδ³É¶Ôµç×ÓÊýµÄ2±¶ÇÒÓÐ3¸öÄܼ¶£¬BÔ­×ÓµÄ×îÍâ²ãp¹ìµÀµÄµç×ÓΪ°ë³äÂú½á¹¹£¬CÊǵؿÇÖк¬Á¿×î¶àµÄÔªËØ¡£DÊǵÚËÄÖÜÆÚÔªËØ£¬ÆäÔ­×ÓºËÍâ×îÍâ²ãµç×ÓÊýÓëÇâÔ­×ÓÏàͬ£¬ÆäÓà¸÷²ãµç×Ó¾ù³äÂú¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)A¡¢B¡¢CµÄµÚÒ»µçÀëÄÜÓÉСµ½´óµÄ˳ÐòÊÇ________(ÓöÔÓ¦µÄÔªËØ·ûºÅ±íʾ)£»DÔ­×ӵĻù̬µç×ÓÅŲ¼Ê½Îª____________________________________________________¡£
(2)AµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯Îï·Ö×ÓÖУ¬ÆäÖÐÐÄÔ­×Ó²ÉÈ¡________ÔÓ»¯£»BCµÄ¿Õ¼ä¹¹ÐÍΪ________(ÓÃÎÄ×ÖÃèÊö)¡£
(3)1 mol AB£­Öк¬ÓеĦмü¸öÊýΪ________¡£
(4)ÈçͼÊǽðÊôCaºÍDËùÐγɵÄijÖֺϽðµÄ¾§°û½á¹¹Ê¾Òâͼ£¬Ôò¸ÃºÏ½ðÖÐCaºÍDµÄÔ­×Ó¸öÊý±ÈÊÇ________¡£

(5)ïçÄøºÏ½ðÓëÉÏÊöºÏ½ð¶¼¾ßÓÐÏàͬÀàÐ͵ľ§°û½á¹¹XYn£¬ËüÃÇÓкÜÇ¿µÄ´¢ÇâÄÜÁ¦¡£ÒÑÖªïçÄøºÏ½ðLaNin¾§°ûÌå»ýΪ9.0¡Á10£­23 cm3£¬´¢ÇâºóÐγÉLaNinH4.5ºÏ½ð(Çâ½øÈ뾧°û¿Õ϶£¬Ìå»ý²»±ä)£¬ÔòLaNinÖÐn£½________(ÌîÊýÖµ)£»ÇâÔںϽðÖеÄÃܶÈΪ________¡£
ÔªËØÖÜÆÚ±íµÚ¢õA×åÔªËØ°üÀ¨µª¡¢Áס¢É飨As£©¡¢ÌࣨSb£©µÈ¡£ÕâЩԪËØÎÞÂÛÔÚÑÐÖÆÐÂÐͲÄÁÏ£¬»¹ÊÇÔÚÖÆ×÷´«Í³»¯·Ê¡¢Å©Ò©µÈ·½Ã涼·¢»ÓÁËÖØÒªµÄ×÷Óá£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©N4·Ö×ÓÊÇÒ»ÖÖ²»Îȶ¨µÄ¶àµª·Ö×Ó£¬ÕâÖÖÎïÖÊ·Ö½âºóÄܲúÉúÎÞ¶¾µÄµªÆø²¢Êͷųö´óÁ¿ÄÜÁ¿£¬Äܱ»Ó¦ÓÃÓÚÖÆÔìÍƽø¼Á»òÕ¨Ò©¡£N4ÊÇÓÉËĸöµªÔ­×Ó×é³ÉµÄµªµ¥ÖÊ£¬ÆäÖеªÔ­×Ó²ÉÓõĹìµÀÔÓ»¯·½Ê½Îªsp3£¬¸Ã·Ö×ӵĿռ乹ÐÍΪ________£¬N¡ªN¼üµÄ¼ü½ÇΪ________¡£
£¨2£©»ù̬ÉéÔ­×ÓµÄ×îÍâ²ãµç×ÓÅŲ¼Ê½Îª________¡£
£¨3£©µç¸ºÐÔÊÇÓÃÀ´±íʾÁ½¸ö²»Í¬Ô­×ÓÐγɻ¯Ñ§¼üʱÎüÒý¼üºÏµç×ÓÄÜÁ¦µÄÏà¶ÔÇ¿Èõ£¬ÊÇÔªËصÄÔ­×ÓÔÚ·Ö×ÓÖÐÎüÒý¹²Óõç×Ó¶ÔµÄÄÜÁ¦¡£ÓÉ´ËÅжÏN¡¢P¡¢As¡¢SbµÄµç¸ºÐÔ´Ó´óµ½Ð¡µÄ˳ÐòÊÇ______________¡£
£¨4£©Áª°±£¨N2H4£©¿ÉÒÔ±íʾΪH2N¡ªNH2£¬ÆäÖеªÔ­×Ó²ÉÓõĹìµÀÔÓ»¯·½Ê½Îª________£¬Áª°±µÄ¼îÐԱȰ±µÄ¼îÐÔ________£¨Ìî¡°Ç¿¡±»ò¡°Èõ¡±£©£¬ÆäÔ­ÒòÊÇ________________________________________________________________¡£
д³öN2H4ÓëN2O4·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º____________________¡£
£¨5£©ÔªËØXÓëNͬÖÜÆÚ£¬ÇÒXµÄÔ­×Ӱ뾶ÊǸÃÖÜÆÚÖ÷×åÔªËØÔ­×Ӱ뾶ÖÐ×îСµÄ£¬XÓëCaÐγɵĻ¯ºÏÎïCaX2µÄ¾§°û½á¹¹ÈçͼËùʾ£º

CaX2µÄ¾§ÌåÀàÐÍÊÇ________£¬Ò»¸ö¾§°ûÖк¬ÓÐCaµÄÀë×ÓÊýΪ________£¬º¬ÓÐXµÄÀë×ÓÊýΪ________¡£
ÓÐλÓÚÖÜÆÚ±íÇ°ËÄÖÜÆÚµÄA¡¢B¡¢C¡¢D¡¢E¡¢FÁùÖÖÔªËØ£¬ÆäÔ­×ÓÐòÊýÒÀ´ÎÔö´ó¡£ÒÑÖªAÔ­×ÓºËÍâÓÐÈý¸öδ³É¶Ôµç×Ó£»AÓëBÐγɵÄÒ»ÖÖ»¯ºÏÎï³£ÎÂÏÂÊǺì×ØÉ«ÆøÌ壻»¯ºÏÎïC2EµÄ¾§ÌåΪÀë×Ó¾§Ì壻Dµ¥ÖʵÄÈÛµãÔÚͬÖÜÆÚµ¥ÖÊÖÐ×î¸ß£»EÔ­×ÓºËÍâµÄM²ãÖÐÖ»ÓÐÁ½¶Ô³É¶Ôµç×Ó£»FÔ­×ÓºËÍâ×îÍâ²ãµç×ÓÊýÓëCÏàͬ£¬ÆäÓà¸÷²ã¾ù³äÂú¡£Çë¸ù¾ÝÒÔÉÏÐÅÏ¢£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©A¡¢B¡¢C¡¢DËÄÖÖÔ­×ӵĵÚÒ»µçÀëÄÜÓÉСµ½´óµÄ˳ÐòΪ______£¨ÓÃÔªËØ·ûºÅ±íʾ£©¡£
£¨2£©CµÄÂÈ»¯ÎïµÄÈÛµã±ÈDµÄÂÈ»¯ÎïµÄÈ۵㠠 £¨Ìî¡°¸ß¡±»ò¡°µÍ¡±£©£¬ÀíÓÉÊÇ        ¡£
£¨3£©EµÄ×î¸ß¼ÛÑõ»¯Îï·Ö×ӵĿռ乹ÐÍÊÇ                  ¡£
£¨4£©»ù̬F+Àë×ӵĺËÍâµç×ÓÅŲ¼Ê½ÊÇ                          £¬FµÄ¸ß¼ÛÀë×ÓÓëAµÄ×î³£¼ûÇ⻯ÎïÐγɵÄÅäÀë×ӵĻ¯Ñ§Ê½Îª                ¡£
£¨5£©Q·Ö×ÓÊÇA2BµÄµÈµç×ÓÌ壬QµÄ½á¹¹Ê½Îª                   £¬Q·Ö×ÓµÄÖÐÐÄÔ­×ÓµÄÔÓ»¯ÀàÐÍÊÇ                ¡£
£¨6£©ÏÂͼÊÇB¡¢FÁ½ÔªËØ×é³ÉµÄÒ»ÖÖ»¯ºÏÎïµÄ¾§°û£¬Æ仯ѧʽΪ              ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø