ÌâÄ¿ÄÚÈÝ

(15·Ö)
´¿¼îÒ»Ö±ÒÔÀ´¶¼Êǹ¤ÒµÉú²úµÄÖØÒªÔ­ÁÏ£¬ºÜ³¤Ò»¶Îʱ¼äÀ´´¿¼îµÄÖÆ·¨¶¼±»Å·ÃÀ¹ú¼ÒËù¢¶Ï¡£ÉϸöÊÀ¼Í³õÎÒ¹úÖøÃûµÄ¹¤Òµ»¯Ñ§¼ÒºîµÂ°ñÏÈÉú£¬¾­¹ýÊýÄêµÄ·´¸´Ñо¿ÖÕÓÚ·¢Ã÷ÁËÓÅÓÚÅ·ÃÀÖƼÊõµÄÁªºÏÖƼ(ÓֳƺîÊÏÖƼ)¡£²¢ÔÚÌì½ò½¨ÔìÁËÎÒ¹ú¶ÀÁ¢Ñз¢µÄµÚÒ»¼ÒÖƼ¡£ÆäÖƼîÔ­ÀíµÄÁ÷³ÌÈçÏ£º

¢ÅºîµÂ°ñÑ¡ÔñÌì½ò×÷ΪÖƼµÄ³§Ö·ÓкαãÀûÌõ¼þ(¾Ù¶þÀý˵Ã÷)       ¡¢      ¡£
¢ÆºÏ³É°±¹¤³§ÐèÒªÏòÖƼÌṩÁ½ÖÖÔ­ÁÏÆøÌ壬ËüÃÇ·Ö±ðÊÇ£º      ¡¢       ¡£(Ìѧʽ)ÕâÁ½ÖÖÆøÌåÔÚʹÓùý³ÌÖÐÊÇ·ñÐèÒª¿¼ÂÇÌí¼ÓµÄ˳Ðò£º       (Ìî¡°ÊÇ¡±»ò¡°·ñ¡±)£¬Ô­ÒòÊÇ£º                                                    ¡£
¢ÇÔÚ³Áµí³ØÖз¢ÉúµÄ·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ£º                                 ¡£
¢ÈʹԭÁÏË®ÖÐÈÜÖʵÄÀûÓÃÂÊ´Ó70%Ìá¸ßµ½90%ÒÔÉÏ£¬Ö÷ÒªÊÇÉè¼ÆÁË         £¨ÌîÉÏÊöÁ÷³ÌÖеıàºÅ£©µÄÑ­»·¡£´ÓĸҺÖпÉÒÔÌáÈ¡µÄ¸±²úÆ·µÄÓ¦ÓÃÊÇ                    (¾ÙÒ»Àý)¡£

¢ÅÔ­ÁϷḻ¡¢ÔËÊä±ãÀû                             ¸÷1·Ö(ÆäËüºÏÀí´ð°¸¾ù¿É)
¢ÆCO2¡¢NH3                                                      ¸÷2·Ö
ÊÇ                                                                1·Ö
°±ÆøÔÚË®ÖÐÈܽâ¶È´ó£¬ÏÈͨ°±ÆøºóͨCO2²úÉú̼ËáÇâ臨࣬ÓÐÀûÓÚ̼ËáÇâÄÆÎö³ö2·Ö
¢ÇNaCl+CO2+NH3+H2O=NaHCO3¡ý+NH4Cl                              2·Ö
¢ÈÑ­»·I                                                           2·Ö
×÷»¯·Ê                                             2·Ö(ÆäËüºÏÀí´ð°¸¾ù¿É)
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨12·Ö£©¸ßÌúËá¼ØÊÇÒ»ÖÖ¸ßЧµÄ¶à¹¦ÄܵÄË®´¦Àí¼Á¡£¹¤ÒµÉϳ£²ÉÓÃNaClOÑõ»¯·¨Éú²ú£¬Ô­ÀíΪ£º
3NaClO + 2Fe(NO3)3 + 10NaOH£½2Na2FeO4¡ý+ 3NaCl + 6NaNO3 + 5H2O
Na2FeO4£«2KOH£½K2FeO4£«2NaOH
Ö÷ÒªµÄÉú²úÁ÷³ÌÈçÏ£º

£¨1£©Ð´³ö·´Ó¦¢ÙµÄÀë×Ó·½³Ìʽ_____________________________¡£
£¨2£©Á÷³ÌͼÖС°×ª»¯¡±ÊÇÔÚijµÍÎÂϽøÐеģ¬ËµÃ÷´ËζÈÏÂKsp(K2FeO4) _________ Ksp(Na2FeO4)£¨Ìî¡°£¾¡±»ò¡°£¼¡±»ò¡°£½¡±£©¡£
£¨3£©·´Ó¦µÄζȡ¢Ô­ÁϵÄŨ¶ÈºÍÅä±È¶Ô¸ßÌúËá¼ØµÄ²úÂʶ¼ÓÐÓ°Ïì¡£
ͼ1Ϊ²»Í¬µÄζÈÏ£¬Fe(NO3)3²»Í¬ÖÊÁ¿Å¨¶È¶ÔK2FeO4Éú³ÉÂʵÄÓ°Ï죻
ͼ2Ϊһ¶¨Î¶ÈÏ£¬Fe(NO3)3ÖÊÁ¿Å¨¶È×î¼Ñʱ£¬NaClOŨ¶È¶ÔK2FeO4Éú³ÉÂʵÄÓ°Ïì¡£

¢Ù¹¤ÒµÉú²úÖÐ×î¼ÑζÈΪ_______¡æ£¬´ËʱFe(NO3)3ÓëNaClOÁ½ÖÖÈÜÒº×î¼ÑÖÊÁ¿Å¨¶ÈÖ®±ÈΪ_______¡£
¢ÚÈôNaClO¼ÓÈë¹ýÁ¿£¬Ñõ»¯¹ý³ÌÖлáÉú³ÉFe(OH)3£¬Ð´³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£º
____________________________________________________¡£
ÈôFe(NO3)3¼ÓÈë¹ýÁ¿£¬ÔÚ¼îÐÔ½éÖÊÖÐK2FeO4ÓëFe3+·¢ÉúÑõ»¯»¹Ô­·´Ó¦Éú³ÉK3FeO4£¬´Ë·´Ó¦µÄÀë×Ó·½³Ìʽ£º____________________________________¡£
£¨4£©K2FeO4 ÔÚË®ÈÜÒºÖÐÒ×Ë®½â£º4FeO42¡ª+10H2O4Fe(OH)3+8OH¡ª+3O2¡ü¡£ÔÚ¡°Ìá´¿¡±K2FeO4ÖвÉÓÃÖؽᾧ¡¢Ï´µÓ¡¢µÍκæ¸ÉµÄ·½·¨£¬ÔòÏ´µÓ¼Á×îºÃÑ¡ÓÃ_______ÈÜÒº£¨ÌîÐòºÅ£©¡£
A£®H2OB£®CH3COONa¡¢Òì±û´¼C£®NH4Cl¡¢Òì±û´¼D£®Fe(NO3)3¡¢Òì±û´¼
»¯·ÊÔÚÅ©ÒµÉú²úÖÐÕ¼ÓÐÖØҪλÖ᣹úÄÚÍâũѧר¼ÒÆÕ±éÈÏΪ£¬ÔÚÆäËûÉú²úÒòËز»±äµÄÇé¿öÏ£¬Å©×÷ÎïÊ©Óû¯·Ê¿ÉÔö²ú40£¥£­60£¥¡£ºÏ³É°±¹¤Òµ¿ÉÒÔÌṩ´óÁ¿µÄµª·Ê£¬ÊÇÂú×ãÈËÀà¶ÔÁ¸Ê³Ôö³¤ÐèÇóµÄ·Ç³£ÖØÒªµÄ»¯Ñ§¹¤Òµ¡£
£¨1£©ÔÚ¹¤ÒµºÏ³É°±µÄ·´Ó¦ÖУ¬ÓÉÓڸ÷´Ó¦ÔÚ³£Î³£Ñ¹Ï£¬ÂýµÃ¼¸ºõ²»Äܾõ²ì£¬ÒªÊµÏÖ¹¤Òµ»¯·Ç³£À§ÄÑ£¬Ðí¶à»¯Ñ§¼ÒΪ´Ë½øÐÐÁ˲»Ð¸µÄŬÁ¦¡£ËûÃÇÏÈ´ÓζȺÍѹǿ×ÅÊÖ£¬Î¶ÈÉý¸ß¶ÔÌá¸ß»¯Ñ§·´Ó¦ËÙÂÊ         £¨ÌîÓÐÀû¡¢²»Àû»òÎ޹أ©£¬Ôö¼Óѹǿ¶ÔÌá¸ß»¯Ñ§·´Ó¦ËÙÂÊ      £¨ÌîÓÐÀû¡¢²»Àû»òÎ޹أ©£¬¿Æѧ¼ÒÃÇËäȻѡÔñÁ˺ÏÊʵÄζȺÍѹǿ£¬µ«Ð§¹û²»¼Ñ£¬ÈÔÎÞ·¨Í¶È빤ҵ»¯Éú²ú¡£µÂ¹ú»¯Ñ§¼Ò¹þ²®£¨Fritz Haber£¬1868£­1934£©Í¨¹ýŬÁ¦£¬ÔÚʹÓúÏÊÊ´ß»¯¼ÁµÄÇé¿öÏÂÖÕÓÚ½â¾öÁËÕâ¸öÎÊÌ⣬ʵÏÖÁ˺ϳɰ±µÄ¹¤Òµ»¯Éú²ú¡£ÄãÈÏΪ¸Ã·´Ó¦Äܹ¤Òµ»¯Éú²úµÄ¹Ø¼üÊÇ       
£¨2£©ºÏ³É°±ÊÇÖØÒªµÄÈ˹¤¹Ìµª·½·¨£¬³ýÈ˹¤¹ÌµªÍ⣬»¹ÓÐ×ÔÈ»¹Ìµª£¬ÉÁµç¹Ìµª¾ÍÊÇ×ÔÈ»¹ÌµªµÄÒ»ÖÖ·½Ê½£¬¿ÎÌÃÉÏ¿ÉÓøßѹ·¢ÉúÆ÷Ä£ÄâÕâÒ»¹ý³Ì£¬×°ÖÃÈçͼËùʾ£º

ʵÑ鿪ʼºó£¬¿ÉÒÔ¿´µ½ÊªÈóµÄÀ¶É«Ê¯ÈïÊÔÖ½±äºìÉ«£¬Çë½âÊÍÔ­Òò£¨Ó÷´Ó¦µÄ»¯Ñ§·½³Ìʽ±íʾ£©
                                             
                                              
                                              

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø