题目内容
已知: 3/2CO2(g)+2Fe(s) = Fe2O3(s)+3/2C(s) △H=-234.1kJ·mol-1
CO2(g) = C(s)+O2(g) △H=+393.4kJ·mol-1。
则2Fe(s)+3/2O2(g)=Fe2O3(s)的△H是
CO2(g) = C(s)+O2(g) △H=+393.4kJ·mol-1。
则2Fe(s)+3/2O2(g)=Fe2O3(s)的△H是
A.-824.2kJ·mol-1 | B.-627.5kJ·mol-1 |
C.+861.6kJ·mol-1 | D.+159.3kJ·mol-1 |
A
CO2(g) = C(s)+O2(g) △H=+393.4kJ·mol-1知C(s)+O2(g)= CO2(g) △H=-393.4kJ·mol-1则3/2C(s)+3/2O2(g)="3/2" CO2(g) △H=-393.4kJ·mol-1*3/2=-590.1kJ·mol-1该式与所给一式相加得2Fe(s)+3/2O2(g)=Fe2O3(s) △H=-824.2kJ·mol-1故选A。
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