ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿ÏÂÁйØÓÚŨÁòËáµÄÐðÊöÕýÈ·µÄÊÇ

A£®Å¨H2SO4ʹÕáÌÇÌ¿»¯±äºÚ£¬ÌåÏÖÁËŨH2SO4µÄÑõ»¯ÐÔ

B£®Å¨H2SO4ʹÀ¶É«µ¨·¯±ä³É°×É«£¬ÌåÏÖÁËŨH2SO4µÄÍÑË®ÐÔ

C£®Å¨H2SO4µÎÔÚÈóʪµÄÀ¶É«Ê¯ÈïÊÔÖ½£¬ÊÔÖ½Ïȱäºì£¬È»ºóÍÊÉ«£¬×îºó±äºÚ£¬ËµÃ÷ŨH2SO4¾ßÓÐËáÐÔ¡¢Ñõ»¯ÐÔºÍÍÑË®ÐÔ

D£®100 mL 18 mol/LµÄŨH2SO4ÖмÓÈë×ãÁ¿µÄCu²¢¼ÓÈÈ£¬±»»¹Ô­µÄH2SO4µÄÎïÖʵÄÁ¿Îª0.9 mol

¡¾´ð°¸¡¿C

¡¾½âÎö¡¿

ÊÔÌâ·ÖÎö£ºA£®Å¨H2SO4ʹÕáÌÇÌ¿»¯±äºÚ£¬ÌåÏÖÁËŨH2SO4µÄÍÑË®ÐÔ£¬A´íÎó£»B£®Å¨H2SO4ʹÀ¶É«µ¨·¯±ä³É°×É«£¬ÌåÏÖÁËŨH2SO4µÄÎüË®ÐÔ£¬B´íÎó£»C£®Å¨H2SO4µÎÔÚÈóʪµÄÀ¶É«Ê¯ÈïÊÔÖ½£¬ÊÔÖ½Ïȱäºì£¬È»ºóÍÊÉ«£¬×îºó±äºÚ£¬ËµÃ÷ŨH2SO4¾ßÓÐËáÐÔ¡¢Ñõ»¯ÐÔºÍÍÑË®ÐÔ£¬CÕýÈ·£»D£®100 mL 18 mol/LµÄŨH2SO4ÖмÓÈë×ãÁ¿µÄCu²¢¼ÓÈÈ£¬Ëæ×Å·´Ó¦µÄ½øÐÐÁòËáŨ¶È¼õС£¬Ï¡ÁòËáÓëÍ­²»·´Ó¦£¬±»»¹Ô­µÄH2SO4µÄÎïÖʵÄÁ¿Ð¡ÓÚ0.9 mol£¬D´íÎó¡£´ð°¸Ñ¡C¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿Ò×»ìÒ×´íÌâ×飺Àë×Ó·½³ÌʽµÄÊéд

£¨1£©Á¿±äÒýÆðÀë×Ó·½³ÌʽµÄ±ä»¯

½«ÉÙÁ¿NaHSO4ÈÜÒºµÎ¼Óµ½Ba(OH)2ÈÜÒºÖУ¬µ±Ç¡ºÃ³Áµíʱ£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ______________¡£

ÏòCa(HCO3)2ÈÜÒºÖеμӹýÁ¿NaOHÈÜÒº£¬·´Ó¦µÄÀë×Ó·½³Ìʽ__________________¡£

(ѧ·¨Ìâ)Êéд´ËÀàÀë×Ó·½³ÌʽµÄ¹Ø¼üÊÇ£¬×¥×¡ Á¿ÎïÖÊ¡£

£¨2£©·´Ó¦Ë³ÐòÒýÆðµÄ±ä»¯

ÏòNH4HCO3ÈÜÒºÖУ¬µÎ¼Ó¹ýÁ¿µÄNaOHÈÜÒº£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ______ ¡£

ÔÚFeI2ÈÜÒºÖУ¬µÎ¼ÓÉÙÁ¿Ï¡ÏõËá¡£¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ£º ¡£

(ѧ·¨Ìâ)Êéд´ËÀàÀë×Ó·½³ÌʽµÄ¹Ø¼üÊÇ£¬×¥×¡·´Ó¦ÎïÖÐÀë×ÓµÄ Ë³Ðò¡£

£¨3£©·´Ó¦½éÖʵÄÓ°Ïì

¢ÙÔÚËáÐÔÌõ¼þÏ£¬Ïòº¬¸õ·ÏË®ÖмÓÈëFeSO4£¬¿É½«Cr2O72-»¹Ô­ÎªCr3+£¬¸Ã¹ý³ÌµÄÀë×Ó·´Ó¦·½³ÌʽΪ ¡£

¢ÚÔÚµí·Ûµâ»¯¼ØÈÜÒºÖУ¬µÎ¼ÓÉÙÁ¿´ÎÂÈËáÄƼîÐÔÈÜÒº£¬Á¢¼´»á¿´µ½ÈÜÒº±äÀ¶É«£¬Àë×Ó·½³ÌʽΪ___________________________¡£

¢ÛÔÚµâºÍµí·ÛÐγɵÄÀ¶É«ÈÜÒºÖУ¬µÎ¼ÓÑÇÁòËáÄƼîÐÔÈÜÒº£¬·¢ÏÖÀ¶É«Öð½¥Ïûʧ£¬Àë×Ó·½³ÌʽÊÇ_______________¡£

¢Ü¶Ô±È¢ÚºÍ¢ÛʵÑéËùµÃµÄ½á¹û£¬½«I2¡¢ClO£­¡¢SO42-°´Ñõ»¯ÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòÅÅÁÐΪ___________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø