题目内容
已知:
(1)2Fe(s)+O2(g)=2FeO(s)△H=-544kJ?mol-1
(2)2Al(s)+
O2(g)=Al2O3(s)△H=-1675kJ?mol-1
则2Al(s)+3FeO(s)=Al2O3(s)+3Fe(s)的△H为( )
(1)2Fe(s)+O2(g)=2FeO(s)△H=-544kJ?mol-1
(2)2Al(s)+
3 |
2 |
则2Al(s)+3FeO(s)=Al2O3(s)+3Fe(s)的△H为( )
A.-2491kJ?mol-1 | B.+859kJ?mol-1 |
C.-1403kJ?mol-1 | D.-859kJ?mol-1 |
已知:(1)2Fe(s)+O2(g)=2FeO(s)△H=-544kJ?mol-1
(2)2Al(s)+
O2(g)=Al2O3(s)△H=-1675kJ?mol-1
据盖斯定律,(2)-(1)×
得:2Al(s)+3FeO(s)=Al2O3(s)+3Fe(s)△H=-859KJ/mol
故选:D
(2)2Al(s)+
3 |
2 |
据盖斯定律,(2)-(1)×
3 |
2 |
故选:D
练习册系列答案
相关题目