ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿´×ÏõÏ㶹ËØΪ¿¹ÄýѪҩ£¬ÁÙ´²ÉÏÖ÷ÒªÓÃÓÚÔ¤·ÀºÍÖÎÁÆѪ¹ÜÄÚѪ˨ÐÔ¼²²¡£¬Í¨¹ýÒÔÏ·½·¨ºÏ³É(²¿·Ö·´Ó¦Ìõ¼þÊ¡ÂÔ)´×ÏõÏ㶹ËØ¡£
ÒÑÖª£º+H2O
£¨1£©EºÍG·´Ó¦µÄÀàÐÍÊÇ_______£»DµÄ»¯Ñ§Ãû³ÆΪ_______£¬´×ÏõÏ㶹ËØÖк¬ÓеĹÙÄÜÍÅÃû³ÆΪ_______¡££¨2£©C¡úDµÄ»¯Ñ§·½³ÌʽΪ_____________________________¡£
£¨3£©Ð´³öGµÄ½á¹¹¼òʽ________________¡£
£¨4£©·Ö×ӽṹÖÐÖ»º¬ÓÐÒ»¸ö»·£¬ÇÒͬʱ·ûºÏÏÂÁÐÌõ¼þµÄGµÄͬ·ÖÒì¹¹Ìå¹²ÓÐ_______ÖÖ¡£
¢Ù¿ÉÓëÂÈ»¯ÌúÈÜÒº·¢ÉúÏÔÉ«·´Ó¦
¢Ú¿ÉÓë̼ËáÇâÄÆÈÜÒº·´Ó¦Éú³É¶þÑõ»¯Ì¼ÆøÌå
ÆäÖУ¬±½»·ÉϵÄÒ»ÂÈ´úÎïÖ»ÓÐÁ½ÖÖµÄͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽΪ_______¡£
£¨5£©²ÎÕÕÉÏÊöºÏ³É·Ïߣ¬Éè¼ÆÒÔCH3CH3ºÍºÏ³ÉµÄ·ÏßÁ÷³Ìͼ(ÎÞ»úÊÔ¼ÁÈÎÑ¡)¡£____________
¡¾´ð°¸¡¿ ¼Ó³É·´Ó¦ 4-Ïõ»ù±½¼×È©(¶ÔÏõ»ù±½¼×)È© õ¥»ù¡¢ôÊ»ù(ͪ»ù)¡¢Ïõ»ù +O2+2H2O 13 CH3CH3CH3CH2ClCH3CH2OHCH3CHO
¡¾½âÎö¡¿ÊÔÌâ·ÖÎö£º ÔÚŨÏõËᡢŨÁòËá×÷ÓÃÏ·¢ÉúÏõ»¯Éú³ÉA£¬½áºÏDµÄ½á¹¹¼òʽ£¬¿ÉÖªAÊÇ£»CÒ»¶¨Ìõ¼þÏÂÉú³É£¬¸ù¾ÝCµÄÏà¶Ô·Ö×ÓÖÊÁ¿ÊÇ153£¬¿ÉÖªCÊÇ£¬ ÓëäåÔÚ¹âÕÕÌõ¼þÏÂÉú³ÉB£»¿ÉÖªBÊÇ£»£¬¸ù¾Ý+H2O£¬¿ÉÖªEÊÇ£¬¸ù¾Ý´×ÏõÏ㶹ËصĽṹ¼òʽ£¬ÄæÍÆGÊÇ¡£
½âÎö£º¸ù¾ÝÒÔÉÏ·ÖÎö, £¨1£©ºÍ·´Ó¦Éú³ÉµÄÀàÐÍÊǼӳɷ´Ó¦£»µÄ»¯Ñ§Ãû³ÆΪ¶ÔÏõ»ù±½¼×È©£¬Öк¬ÓеĹÙÄÜÍÅÃû³ÆΪõ¥»ù¡¢ôÊ»ù¡¢Ïõ»ù¡££¨2£©ÔÚÍ´ß»¯Ìõ¼þÏÂÑõ»¯Îª£¬»¯Ñ§·½³ÌʽΪ+O2+2H2O¡£
£¨3£©GµÄ½á¹¹¼òʽ¡££¨4£©¢ÙÓëÂÈ»¯ÌúÈÜÒº·¢ÉúÏÔÉ«·´Ó¦£¬ËµÃ÷º¬ÓзÓôÇ»ù£»
¢ÚÓë̼ËáÇâÄÆÈÜÒº·´Ó¦Éú³É¶þÑõ»¯Ì¼ÆøÌ壬˵Ã÷º¬ÓÐôÈ»ù£»¸ù¾Ý²»±¥ºÍ¶È£¬²àÁ´»¹ÓÐÒ»¸ö̼̼Èþ¼ü£¬Èô±½»·ÉÏ2¸ö²àÁ´£¬ÓÐÁÚ¡¢¼ä¡¢¶Ô3Öֽṹ £¬Èô±½»·ÉÏ3¸ö²àÁ´£¬ÓÐ10Öֽṹ£¬ËùÒÔ·ûºÏÌõ¼þµÄGµÄͬ·ÖÒì¹¹Ìå¹²13ÖÖ£»±½»·ÉϵÄÒ»ÂÈ´úÎïÖ»ÓÐÁ½ÖÖ£¬ËµÃ÷±½»·ÓÐÁ½¸ö¶Ôλȡ´ú»ù£¬½á¹¹¼òʽΪ£»£¨5£©ÒªÖƱ¸£¬ÏÈÓÃÒÒÍéÓëÂÈÆø·¢ÉúÈ¡´ú·´Ó¦Éú³ÉÂÈÒÒÍ飬ÂÈÒÒÍéË®½âΪÒÒ´¼£¬ÒÒ´¼´ß»¯Ñõ»¯ÎªÒÒÈ©£¬ÒÒÈ©ÓëÒ»¶¨Ìõ¼þÏÂÉú³É£»Ò»¶¨Ìõ¼þÏ·¢Éú¼Ó¾Û·´Ó¦Éú³É£»ºÏ³É·ÏßΪCH3CH3CH3CH2ClCH3CH2OHCH3CHO¡£
¡¾ÌâÄ¿¡¿Æû³µÎ²ÆøÖ÷Òªº¬ÓÐCO2 ¡¢CO¡¢SO2¡¢NOx µÈÎïÖÊ£¬Î²ÆøÖÐCO¡¢ÇâÑõ»¯Îï(NOx) ÑÏÖØÓ°ÏìÈËÃǵÄÉú»îºÍ½¡¿µ£¬»¯Ñ§¹¤×÷Õ߶ԵªÑõ»¯ÎïµÄ´¦Àí×öÁ˹㷺¶øÉîÈëµÄÑо¿¡£
£¨1£©ÀûÓü×Í黹ÔNOx
¢ÙCH4(g)+4NO2(g)=4NO(g)+CO2(g)+2H2O(g)¡÷H1=-574kJ/mo l£»
¢ÚCH4(g)+4NO(g)=2N2(g)+CO2(g)+H2O(g) ¡÷H2=-1160kJ/mo l,
¼×ÍéÖ±½Ó½«NO2»¹ÔΪN2µÄÈÈ»¯Ñ§·½³ÌʽΪ________________________________¡£
£¨2£©½«²»Í¬Á¿µÄCO(g)»ýH2O(g)·Ö±ðͨÈëÌå»ýΪ2LµÄºãÈÝÃܱÕÈÝÆ÷ÖУ¬½øÐз´Ó¦CO(g)+H2O(g)CO2(g)+H2(g)£¬µÃµ½ÈçÏÂÈý×éÊý¾Ý£º
ʵÑé×é | ζȡæ | ÆðʼÁ¿/mol | ƽºâÁ¿/mol | ´ïµ½Æ½ºâËùÐèʱ¼ä/min | ||
CO | H2O | H2 | CO | |||
1 | 650 | 4 | 2 | 1.6 | 2.4 | 6 |
2 | 900 | 2 | 1 | 0.4 | 1.6 | 4 |
3 | 900 | a | b | c | d | t |
¢ÙʵÑé1ÖÐÒÔv(CO2) ±íʾµÄ·´Ó¦ËÙÂÊΪ/span>_________(±£ÁôÁ½Î»ÓÐЧÊý×Ö£¬ÏÂͬ)¡£
¢Ú¸Ã·´Ó¦Îª________(Ìî¡°ÎüÈÈ¡±»ò¡°·ÅÈÈ¡±) ·´Ó¦£¬ÊµÑé2Ìõ¼þϵÄƽºâ³£ÊýK=________¡£
¢ÛÈô´ïƽºâ״̬ʱ£¬ÊµÑé2 ÓëʵÑé3Öи÷ÎïÖʵÄÖÊÁ¿·ÖÊý·Ö±ðÏàµÈ£¬ÇÒt£¼4min,Ôòa¡¢bÓ¦Âú×ãµÄ¹ØϵÊÇ_________________________(Óú¬a¡¢bµÄÊýѧʽ±íʾ)¡£
£¨3£©CO·ÖÎöÒǵĴ«¸ÐÆ÷¿É²â¶¨Æû³µÎ²ÆøÊÇ·ñ·ûºÏÅŷűê×¼¡£¸Ã·ÖÎöÒǵŤ×÷ÔÀíÀàËÆÓÚȼÁϵç³Ø£¬ÆäÖеç½âÖÊÊÇÑõ»¯îÆ(Y2O3) ºÍÑõ»¯ï¯(ZrO2) ¾§Ì壬ÄÜ´«µ¼O2-£¬Ôò¸º¼«µÄµç¼«·´Ó¦Ê½Îª____________¡£
£¨4£©SO2¿ÉÓøƻù¹ÌÁò·´Ó¦³ýÈ¥£¬·´Ó¦Éú³ÉµÄCaSO4ÊÇÒ»ÖÖ΢ÈÜÎïÖÊ£¬ÆäKsp=9.0¡Á10-6¡£Èô½«Å¨¶ÈΪ2¡Á10-3mol/LµÄNa2SO4ÈÜÒºÓëµÈÌå»ýµÄCaCl2ÈÜÒº»ìºÏ£¬ÔòÉú³É³ÁµíËùÐèCaCl2ÈÜÒºµÄ×îСŨ¶ÈΪ_____________¡£