ÌâÄ¿ÄÚÈÝ

£¨10·Ö£©ÊµÑéÊÒÖƵõÄÂÈÆøͨ³£º¬ÓÐË®ÕôÆøºÍÑÎËá»Ó·¢µÄÂÈ»¯Ç⣬ҪÖÆÈ¡¸ÉÔï´¿¾»µÄÂÈÆø£¬¿ÉÓÃÈçͼËùʾµÄ×°Ö㬽øÐиÉÔï¡¢¾»»¯¡¢ÊÕ¼¯ºÍβÆø´¦Àí£¨CÆ¿ÓÃÓÚÊÕ¼¯ÂÈÆø£¬DÆ¿ÓÃÓÚβÆø´¦Àí£©¡£

¾Ý´ËÍê³ÉÏÂÁи÷Ì⣺
£¨1£©ÊµÑéÊÒͨ³£Óñ¥ºÍʳÑÎË®ÎüÊÕÔÓÖÊHCl£¬Ôòͼ£¨1£©ÖÐAÆ¿ºÍBÆ¿ÒÀ´Î·Ö±ðÊ¢×°µÄÊÔ¼ÁÊÇ£º_____________________________________£»
£¨2£©Í¼£¨2£©ÊÇÂÈÆøµÄÊÕ¼¯×°Ö㬽«Ëü°²ÖÃÔÚͼ£¨1£©ÖеÄÐéÏß¿òÄÚ£¬Æäµ¼¹ÜµÄÁ¬½Ó˳ÐòÊÇ£º______________________________£»
£¨3£©¼ì²é×îÖÕβÆøÅÅ·Å£¨µ¼¹Ü¿Úc´¦£©ÊÇ·ñº¬ÓÐÂÈÆø£¬¿ÉÓÃʪÈóµÄµí·Û-KIÊÔÖ½²âÊÔ£¬ÈçÓÐÂÈÆøй©£¬¿É¹Û²ìµ½__________________________________£¬²úÉú´ËÏÖÏóµÄÖ±½ÓÔ­ÒòÊÇ__________________________________£»´Ë·½·¨¼ì²âÂÈÆø£¬ÊÔÖ½±ØÐëÓÃË®ÈóʪÊÇÒòΪ________________________________________¡£
£¨10·Ö£¬Ã¿¿Õ2·Ö£©£¨1£©±¥ºÍʳÑÎË®¡¢Å¨ÁòË᣻£¨2£©aÁ¬e£¬dÁ¬b£»£¨3£©µí·Û-KIÊÔÖ½±äÀ¶£»Cl2½«I-Ñõ»¯³ÉI2£¬I2Óöµí·Û±äÀ¶£»Ë®ÈóʪÐγÉKIÈÜÒº£¬KIÔÚÈÜÒºÖвÅÄܵçÀë³öI-¡£
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨17·Ö£©ÊµÑéÊÒÐèÒª0£®1 mol/L NaOHÈÜÒº450 mL,ÐèÒª0£®5 mol/LÁòËáÈÜÒº500 mL£®¸ù¾ÝÕâÁ½ÖÖÈÜÒºµÄÅäÖÆÇé¿ö»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÈçͼËùʾµÄÒÇÆ÷ÖÐÅäÖÆÈÜÒº¿Ï¶¨²»ÐèÒªµÄÊÇ¡¡¡¡¡¡¡¡£¨ÌîÐòºÅ£©£¬ÅäÖÆÉÏÊöÈÜÒº»¹ÐèÓõ½µÄ²£Á§ÒÇÆ÷ÊÇ¡¡¡¡¡¡¡¡£¨ÌîÒÇÆ÷Ãû³Æ£©£®
£¨2£©¸ù¾Ý¼ÆËãÓÃÍÐÅÌÌìƽ³ÆÈ¡NaOHµÄÖÊÁ¿Îª¡¡¡¡¡¡¡¡ g£®
£¨3£©¸ù¾Ý¼ÆËãµÃÖª£¬ËùÐèÖÊÁ¿·ÖÊýΪ98%¡¢ÃܶÈΪ1£®84 g/cm3µÄŨÁòËáµÄÌå»ýΪ
¡¡¡¡¡¡ mL£¨¼ÆËã½á¹û±£ÁôһλСÊý£©£®Èç¹ûʵÑéÊÒÓÐ15 mL¡¢20 mL¡¢50 mLÁ¿Í²£¬Ó¦Ñ¡Óá¡¡¡¡¡¡¡¡¡ mLµÄÁ¿Í²×îºÃ£®ÅäÖƹý³ÌÖÐÐèÏÈÔÚÉÕ±­Öн«Å¨ÁòËá½øÐÐÏ¡ÊÍ£¬Ï¡ÊÍʱ²Ù×÷·½·¨ÊÇ           ¡£
£¨4£©È¡ÓÃÈÎÒâÌå»ýµÄËùÅä0£®5 mol/LÁòËáÈÜҺʱ£¬ÏÂÁÐÎïÀíÁ¿Öв»ËæËùÈ¡Ìå»ýµÄ¶àÉÙ¶ø±ä»¯µÄÊÇ£¨Ìî×Öĸ£©
A£®ÈÜÒºÖÐH2SO4µÄÎïÖʵÄÁ¿                  B£®ÈÜÒºµÄŨ¶È
C£®ÈÜÒºÖÐSO42-µÄÊýÄ¿                       D£®ÈÜÒºµÄÃܶÈ
£¨5£©½«ËùÅäÖƵÄÏ¡H2SO4½øÐвⶨ£¬·¢ÏÖŨ¶È´óÓÚ0£®5mol£¯L¡£ÇëÄã·ÖÎöÏÂÁÐÄÄЩ²Ù×÷»áÒýÆðËùÅäŨ¶ÈÆ«´ó£¨Ìîд×Öĸ£©                             ¡£
A£®ÉÕ±­Î´½øÐÐÏ´µÓ
B£®ÅäÖÆÇ°£¬ÈÝÁ¿Æ¿ÖÐÓÐÉÙÁ¿ÕôÁóË®
C£®Å¨ÁòËáÔÚÉÕ±­ÖÐÏ¡Êͺó£¬Î´ÀäÈ´¾ÍÁ¢¼´×ªÒƵ½ÈÝÁ¿Æ¿ÖУ¬²¢½øÐж¨ÈÝ£»
D£®ÍùÈÝÁ¿Æ¿×ªÒÆʱ£¬ÓÐÉÙÁ¿ÒºÌ彦³ö
E£®ÓÃÁ¿Í²Á¿È¡Å¨ÁòËáʱ£¬ÑöÊÓÁ¿Í²µÄ¿Ì¶È
F£®ÔÚÈÝÁ¿Æ¿Öж¨ÈÝʱ¸©ÊÓÈÝÁ¿Æ¿¿Ì¶ÈÏß
G£®¶¨ÈݺóÈûÉÏÆ¿Èû·´¸´Ò¡ÔÈ£¬¾²Öúó£¬ÒºÃæ²»µ½¿Ì¶ÈÏߣ¬ÔÙ¼ÓË®ÖÁ¿Ì¶ÈÏß¡£
£¨12·Ö£©´¿¾»µÄ¹ýÑõ»¯¸Æ£¨CaO2£©ÄÑÈÜÓÚË®¡¢ÒÒ´¼£¬³£ÎÂϽÏΪÎȶ¨¡£CaO2¡¤8H2OÔÚ0¡æʱÎȶ¨£¬¼ÓÈÈÖÁ130¡æʱÖð½¥±äΪÎÞË®CaO2¡£ÔÚʵÑéÊÒ¿ÉÓøÆÑÎÖÆÈ¡CaO2¡¤8H2O£¬ÔÙ¾­ÍÑË®ÖƵÃCaO2¡£ÆäÖƱ¸¹ý³ÌÈçÏ£º

¸ù¾ÝÒÔÉÏÐÅÏ¢£¬Í¬´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÓÃÉÏÊö·½·¨ÖÆÈ¡CaO2¡¤8H2OµÄ»¯Ñ§·½³ÌʽÊÇ           £»
£¨2£©²Ù×÷AµÄ²½ÖèΪ               £»
£¨3£©¼ìÑ顰ˮϴ¡±ÒѾ­Ï´¾»µÄ·½·¨ÊÇ                        £»
£¨4£©²â¶¨²úÆ·ÖÐCaO2µÄº¬Á¿µÄʵÑé²½ÖèÊÇ£¨¼ºÖª£ºI2+2S2O32-=2I-+S4O62-£©£º
µÚÒ»²½£º×¼È·³ÆÈ¡a g²úÆ·ÓÚ׶ÐÎÆ¿ÖУ¬¼ÓÈëÊÊÁ¿ÕôÁóË®ºÍ¹ýÁ¿µÄb g KIÆ·Ì壬ÔÙµÎÈëÊÊÁ¿2 mol¡¤L-1µÄH2SO4ÈÜÒº£¬³ä·Ö·´Ó¦£º
µÚ¶þ²½£ºÏòÉÏÊö׶ÐÎÆ¿ÖмÓÈ뼸µÎµí·ÛÈÜÒº£º
µÚÈý²½£ºÖðµÎ¼ÓÈëŨ¶ÈΪc mol¡¤L-1µÄNa2S2O3ÈÜÒºÖÁ·´Ó¦ÍêÈ«£¬ÏûºÄNa2S2O3ÈÜÒºVmL¡£
¢ÙµÚÈý²½·´Ó¦ÍêȫʱµÄÏÖÏóΪ           £»
¢Ú²úÆ·ÖÐCaO2µÄÖÊÁ¿·ÖÊýΪ            £¨ÓÃ×Öĸ±íʾ£©£»
¢Ûijͬѧ¾­ÊµÑé²âµÃ²úÆ·ÖÐCaO2µÄÖÊÁ¿·ÖÊýÆ«¸ß£¬Ôì³ÉÆ«¸ßµÄÔ­ÒòÊÇ£¨²â¶¨¹ý³ÌÖÐÓɲÙ×÷²úÉúµÄÎó²îºöÂÔ²»¼Æ£¬ÓÃÀë×Ó·½³Ìʽ±íʾ£©                  ¡£
£¨8·Ö£©ÅäÖÆ500mL 0.5mol¡¤L-1µÄNaOHÈÜÒº£¬ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©¼ÆË㣺ÐèÒªNaOH¹ÌÌåµÄÖÊÁ¿Îª              ¡£
£¨2£©Ä³Ñ§ÉúÓÃÍÐÅÌÌìƽ³ÆÁ¿Ò»¸öСÉÕ±­µÄÖÊÁ¿£¬³ÆÁ¿Ç°°ÑÓÎÂë·ÅÔÚ±ê³ßµÄÁã¿Ì¶È´¦£¬Ììƽ¾²Ö¹Ê±·¢ÏÖÖ¸ÕëÔÚ·Ö¶ÈÅ̵ÄÆ«ÓÒλÖ㬴Ëʱ×ó±ßµÄÍÐÅ̽«           £¨Ìî¡°¸ßÓÚ¡±»ò¡°µÍÓÚ¡±£©ÓұߵÄÍÐÅÌ¡£
£¨3£©ÅäÖÆ·½·¨£ºÉè¼ÆÎå¸ö²Ù×÷²½Ö裺
¢ÙÏòÊ¢ÓÐNaOHµÄÉÕ±­ÖмÓÈë200mLÕôÁóˮʹÆäÈܽ⣬²¢ÀäÈ´ÖÁÊÒΡ£
¢Ú¼ÌÐøÍùÈÝÁ¿Æ¿ÖмÓÕôÁóË®ÖÁÒºÃæ½Ó½ü¿Ì¶ÈÏß1cm¡«2cm¡£
¢Û½«NaOHÈÜÒºÑز£Á§°ô×¢Èë500mLÈÝÁ¿Æ¿ÖС£
¢ÜÔÚÉÕ±­ÖмÓÈëÉÙÁ¿µÄÕôÁóË®£¬Ð¡ÐÄÏ´µÓ2¡«3´ÎºóÒÆÈëÈÝÁ¿Æ¿¡£
¢Ý¸ÄÓýºÍ·µÎ¹Ü¼ÓÕôÁóË®ÖÁ¿Ì¶ÈÏߣ¬¼Ó¸ÇÒ¡ÔÈ¡£
ÊÔ½«ÒÔÉÏ˳Ðò±à³öÕýÈ·³ÌÐò                    ¡£
£¨4£©Ä³Ñ§Éúʵ¼ÊÅäÖÆNaOHÈÜÒºµÄŨ¶ÈΪ0.48mol¡¤L-1£¬²»¿ÉÄܵÄÔ­ÒòÊÇ              
A£®Ê¹ÓÃÂËÖ½³ÆÁ¿ÇâÑõ»¯ÄƹÌÌå
B£®ÈÝÁ¿Æ¿ÖÐÔ­À´´æÓÐÉÙÁ¿ÕôÁóË®
C£®×ªÒÆÈÜÒººóµÄÉÕ±­Î´¾­¶à´ÎÏ´µÓ
D£®½ºÍ·µÎ¹Ü¼ÓË®ºó¶¨ÈÝʱÑöÊӿ̶È
(14·Ö)¶þÑõ»¯ÂÈ(ClO2)×÷ΪһÖÖ¸ßЧǿÑõ»¯¼ÁÒѱ»ÁªºÏ¹úÊÀ½çÎÀÉú×éÖ¯(WHO)ÁÐΪAI¼¶°²È«Ïû¶¾¼Á¡£³£ÎÂ϶þÑõ»¯ÂÈΪ»ÆÂÌÉ«»òéÙ»ÆÉ«ÆøÌ壬ÐÔÖʷdz£²»Îȶ¨£¬Î¶ȹý¸ß»òË®ÈÜÒºÖÐClO2µÄÖÊÁ¿·ÖÊý¸ßÓÚ30£¥µÈ¾ùÓпÉÄÜÒýÆð±¬Õ¨£¬Ò×Óë¼îÒº·´Ó¦Éú³ÉÑκÍË®¡£

(1)ijÑо¿Ð¡×éÉè¼ÆÈçͼËùʾʵÑéÖƱ¸ClO2ÈÜÒº£¬Æä·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ

¢ÙÔÚ·´Ó¦¿ªÊ¼Ö®Ç°½«ÉÕ±­ÖеÄË®¼ÓÈȵ½80¡æ£¬È»ºóÍ£Ö¹¼ÓÈÈ£¬²¢Ê¹Æäζȱ£³ÖÔÚ60¡«80¡æÖ®¼ä¡£¿ØÖÆζȵÄÄ¿µÄÊÇ                 £¬Í¼Ê¾×°ÖÃÖÐȱÉÙµÄÒ»ÖÖ±ØÐëµÄ²£Á§ÒÇÆ÷ÊÇ    
¢Ú×°ÖÃAÓÃÓÚÈܽâ²úÉúµÄ¶þÑõ»¯ÂÈÆøÌ壬ÆäÖÐ×îºÃÊ¢·Å      (Ìî×Öĸ)¡£
A£®20mL 60¡æµÄÎÂË®B£®100mL±ùË®
C£®100mL±¥ºÍʳÑÎË®D£®100mL·ÐË®
¢ÛÔÚÉÕÆ¿ÖмÓÈë12.25g KClO3ºÍ9g²ÝËá(H2C2O4)£¬È»ºóÔÙ¼ÓÈë×ãÁ¿µÄÏ¡ÁòËᣬˮԡ¼ÓÈÈ£¬·´Ó¦ºóÉú³ÉClO2µÄÖÊÁ¿Îª                 
(2)ÓÃClO2´¦Àí¹ýµÄÒûÓÃË®(pHΪ5.5¡«6.5)³£º¬ÓÐÒ»¶¨Á¿¶ÔÈËÌå²»ÀûµÄÑÇÂÈËá¸ùÀë×Ó()¡£ÒûÓÃË®ÖÐClO2¡¢µÄº¬Á¿¿ÉÓÃÁ¬ÐøµâÁ¿·¨½øÐвⶨ£¬ÊµÑé²½ÖèÈçÏ£º
²½Öè1£º×¼È·Á¿È¡Ò»¶¨Ìå»ýµÄË®Ñù¼ÓÈë׶ÐÎÆ¿ÖУ»
²½Öè2£ºµ÷½ÚË®ÑùµÄpHÖÁ7.0¡«8.0£»
²½Öè3£º¼ÓÈë×ãÁ¿µÄKI¾§Ì壻
²½Öè4£º¼ÓÈëÉÙÁ¿Ö¸Ê¾¼Á£¬ÓÃÒ»¶¨Å¨¶ÈµÄNa2S2O3ÈÜÒºµÎ¶¨ÖÁÖյ㣻
²½Öè5£ºÔÙµ÷½ÚÈÜÒºµÄpH¡Ü2.0£»
²½Öè6£º¼ÌÐøÓÃÏàͬŨ¶ÈµÄNa2S2O3ÈÜÒºµÎ¶¨ÖÁÖյ㡣
¢Ù²½Öè1ÖÐÈôÒªÁ¿È¡20.00mLË®Ñù£¬ÔòӦѡÓõÄÒÇÆ÷ÊÇ              
¢Ú²½Öè1¡«4µÄÄ¿µÄÊDzⶨˮÑùÖÐClO2µÄº¬Á¿£¬Æä·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ:
£¬Ôò²½Öè4ÖмÓÈëµÄָʾ¼ÁΪ            £¬µÎ¶¨´ïµ½ÖÕµãʱÈÜÒºµÄÑÕÉ«±ä»¯Îª                   
¢Û²½Öè5µÄÄ¿µÄÊÇʹ½«ÈÜÒºÖеĻ¹Ô­ÎªÒԲⶨÆ京Á¿£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º
                                            
¢ÜÈôÒûÓÃË®Öеĺ¬Á¿³¬±ê£¬¿ÉÏòÆäÖмÓÈëÊÊÁ¿µÄ½«»¹Ô­Îª£¬Ôò¸Ã·´Ó¦µÄÑõ»¯²úÎïΪ              (Ìѧʽ)

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø