ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Åð¼°Æ仯ºÏÎïÔÚ¹¤ÒµÉÏÓÐÐí¶àÓÃ;¡£¹¤ÒµÉÏÒÔÌúÅð¿óΪÔÁÏÖƱ¸ÅðËᣬÌúÅð¿óº¬ÓÐMg¡¢Fe¡¢Ca¡¢Al¡¢B¡¢OµÈ¶àÖÖÔªËØ£¬ËüµÄÖ÷Òª³É·ÖΪMg2B2O5¡¤H2OºÍFe3O4¡£
£¨1£©ÌúÔªËØλÓÚÔªËØÖÜÆÚ±íÖÐµÄµÚ ×壬ÔÚË®ÈÜÒºÖг£ÒÔFe2+¡¢Fe3+µÄÐÎʽ´æÔÚ£¬ÆäÖÐ ¸üÎȶ¨¡£
£¨2£©ÒÔÅðËáΪÔÁÏ¿ÉÖƵÃNaBH4 ,BÔ×ÓµÄÔÓ»¯·½Ê½Îª ¡£
£¨3£©¹¤ÒµÉÏÒ±Á¶ÂÁ²»ÓÃÂÈ»¯ÂÁ£¬ÒòΪÂÈ»¯ÂÁÒ×Éý»ª£¬ÆäË«¾ÛÎïAl2Cl6½á¹¹ÈçͼËùʾ¡£1mol¸Ã·Ö×ÓÖк¬ ¸öÅäλ¼ü£¬¸Ã·Ö×Ó £¨Ìî¡°ÊÇ¡±»ò¡°·ñ¡±£©Æ½ÃæÐÍ·Ö×Ó¡£
£¨4£©Alµ¥ÖÊΪÃæÐÄÁ¢·½¾§Ì壬Æ侧°ûµÄ±ß³¤a=0.405nm£¬ÁÐʽ±íʾAlµ¥ÖʵÄÃܶȣº____g¡¤cm£3¡£
¡¾´ð°¸¡¿
£¨1£© ¢ø Fe3+
£¨2£© sp3
£¨3£©2NA ·ñ
£¨4£© ¦Ñ£½
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º£¨1£©FeÔªËØÔ×ÓºËÍâµç×ÓÊýΪ26£¬Î»ÓÚÔªËØÖÜÆÚ±íÖеĵڢø×壻Fe3+Àë×Ó3dΪ°ëÂúÎȶ¨×´Ì¬£¬ÄÜÁ¿½ÏµÍ£¬±È½ÏÎȶ¨£»
£¨2£©NaBH4ÖÐBÔ×Ó¼Û²ãµç×Ó¶ÔÊýΪ4+=4£¬ÔÓ»¯¹ìµÀÊýĿΪ4£¬ÆäÔÓ»¯·½Ê½Îªsp3£»
£¨3£©Al2Cl6½á¹¹ÖкÚÉ«ÇòΪAlÔ×Ó¡¢°×É«ÇòΪClÔ×Ó£¬AlÔ×ÓÓëClÔ×ÓÖ®¼äÐγÉ3¸ö¹²¼Û¼ü¡¢1¸öÅäλ¼ü£¬AlÔ×ÓÔÓ»¯¹ìµÀÊýĿΪ4£¬1mol¸Ã·Ö×ÓÖк¬2NA¸öÅäλ¼ü£¬¸Ã·Ö×Ó²»ÊÇƽÃæÐÍ·Ö×Ó£»
£¨4£©Alµ¥ÖÊΪÃæÐÄÁ¢·½¾§Ì壬¾§°ûÖÐAlÔ×ÓÊýĿΪ8¡Á+6¡Á=4£¬¾§°ûÖÊÁ¿Îª4¡Ág£¬Æ侧Ìå²ÎÊýa=0.405nm£¬Ôò¾§°ûÃܶȦѣ½¡£