ÌâÄ¿ÄÚÈÝ
£¨12·Ö£©A¡¢B¡¢C¡¢D¡¢EÎåÖÖ¶ÌÖÜÆÚÔªËØ£¬ËüÃǵÄÔ×ÓÐòÊýÒÀ´ÎÔö´ó¡£BÔ×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇÆä´ÎÍâ²ãµç×ÓÊýµÄ2±¶£»AµÄÒ»ÖÖÔ×ÓÖУ¬ÖÊÁ¿ÊýÓëÖÊ×ÓÊýÖ®²îΪÁã¡£DÔªËصÄÔ×Ó×îÍâ²ãµç×ÓÊýΪm£¬´ÎÍâ²ãµç×ÓÊýΪn£»EÔªËصÄÔ×ÓL²ãµç×ÓÊýΪm+n£¬M²ãµç×ÓÊýΪ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©DÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ_____________________£»
£¨2£©Ð´³öÒ»¸öEºÍDÐγɵĻ¯ºÏÎïÓëË®·´Ó¦µÄÀë×Ó·½³Ìʽ_______________________£»
£¨3£©ÒÑÖª£º¼× + H2O ¡ú ±û + ¶¡¡£Èô¼×ÊÇÓÉNºÍClÔªËØ×é³ÉµÄ»¯ºÏÎÆä·Ö×ӽṹģÐÍÈçÓÒͼËùʾ£¬±û¾ßÓÐƯ°×ÐÔ¡£Ôò¼×ÖÐClÔªËصĻ¯ºÏ¼ÛÊÇ ¡¡£¬¶¡ÓëH2OÓÐÏàͬµÄµç×Ó×ÜÊý£¬Ôò¶¡µÄ»¯Ñ§Ê½Îª ¡£ ¡¡¡¡
£¨4£©ÓëDͬÖ÷×åÉÏÏÂÏàÁÚµÄÔªËØM¡¢N£¬Ô×Óµç×Ó²ãÊýM>N>D£¬ÈýÖÖÔªËØÇ⻯Îï·ÐµãÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ(Ìîд»¯Ñ§Ê½) ¡£
£¨5£©Ð´³öBÓëDÔÚ¸ßÎÂÏÂÍêÈ«·´Ó¦ºóÉú³ÉÎïµÄµç×Óʽ___ __ £¬½á¹¹Ê½___
£¨1£©¡¡µÚ¶þÖÜÆÚVIA×壨2·Ö£©
£¨2£©Na2O+H2O=2Na++2OH?»ò2Na2O2+2H2O=4Na++4OH?+O2¡ü £¨2·Ö£©
£¨3£©+1£¨1·Ö£©£¬NH3£¨1·Ö£©
£¨4£©H2O>H2Se>H2S£¨2·Ö£©£¨5£© £¨2·Ö£©£¬O£½C£½O(2·Ö)
½âÎö