ÌâÄ¿ÄÚÈÝ
ÄÜÔ´ÎÊÌâÊǵ±Ç°ÊÀ½ç¸÷¹úËùÃæÁÙµÄÑÏÖØÎÊÌ⣬ͬʱȫÇòÆøºò±äů£¬Éú̬»·¾³ÎÊÌâÈÕÒæÍ»³ö£¬¿ª·¢ÇâÄÜ¡¢ÑÐÖÆÈ¼ÁÏµç³Ø¡¢·¢Õ¹µÍ̼¾¼ÃÊÇ»¯Ñ§¹¤×÷ÕßµÄÑо¿·½Ïò¡£
I£®ÇâÆøÍ¨³£ÓÃÉú²úË®ÃºÆøµÄ·½·¨ÖƵá£ÆäÖÐCO(g)+H2O(g)
CO2(g)+H2(g)
¡÷H<0¡£ÔÚ850¡æÊ±£¬Æ½ºâ³£ÊýK=1¡£
£¨1£©Èô½µµÍζȵ½750¡æÊ±£¬´ïµ½Æ½ºâʱK 1£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©
£¨2£©850¡æÊ±£¬ÈôÏòÒ»ÈÝ»ý¿É±äµÄÃܱÕÈÝÆ÷ÖÐͬʱ³äÈë1.0molCO¡¢3molH2O¡¢1.0molCO2
ºÍx molH2£¬Ôò£º
¢Ùµ±x=5.0ʱ£¬ÉÏÊö·´Ó¦Ïò £¨Ìî¡°Õý·´Ó¦¡±»ò¡°Äæ·´Ó¦¡±£©·½Ïò½øÐС£
¢ÚÈôҪʹÉÏÊö·´Ó¦¿ªÊ¼Ê±ÏòÕý·´Ó¦·½Ïò½øÐУ¬ÔòxÓ¦Âú×ãµÄÌõ¼þÊÇ ¡£
¢ÛÔÚ850¡æÊ±£¬ÈôÉèx=5.0ºÍx=6.0£¬ÆäËüÎïÖʵÄͶÁϲ»±ä£¬µ±ÉÏÊö·´Ó¦´ïµ½Æ½ºâºó£¬
²âµÃH2µÄÌå»ý·ÖÊý·Ö±ðΪa%¡¢b%£¬Ôòa b£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©
II£®ÒÑÖª4.6gҺ̬ÒÒ´¼ÍêȫȼÉÕÉú³É¶þÑõ»¯Ì¼ºÍҺ̬ˮ·Å³öÈÈÁ¿136kJ¡¤molҺ̬ˮת
»¯ÎªÆøÌåË®ÎüÊÕ44kJµÄÈÈÁ¿¡£
£¨3£©Çëд³öÒÒ´¼È¼ÉÕÉú³ÉÆøÌ¬Ë®µÄÈÈ»¯Ñ§·½³Ìʽ
¡£
£¨4£©½«0.1molÒÒ´¼ÔÚ×ãÁ¿ÑõÆøÖÐȼÉÕ£¬µÃµ½µÄÆøÌåÈ«²¿Í¨Èëµ½100mL3mol/LNaOHÈÜÒºÖУ¬ºöÂÔHCO-3µÄµçÀ룬ÔòËùµÃÈÜÒºÖÐc(CO2-3) c(HCO-3)£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£¬£©ÔÒòÊÇ £¨ÓÃÎÄ×ÖÐðÊö£©¡£
£¨1£©´óÓÚ£¨2·Ö£©
£¨2£©¢ÙÄæ·´Ó¦£¨2·Ö£© ¢Úx<3£¨2·Ö£© ¢ÛСÓÚ£¨2·Ö£©
£¨3£©C2H5OH£¨l£©+3C2£¨g£©=2CO2£¨g£©+3H2O£¨g£© ¡÷H=-1228kJ/mol£¨2·Ö£©
£¨4£©Ð¡ÓÚ£¨2·Ö£© CO32- Ë®½â³Ì¶È´óÓÚHCO3-Ë®½â³Ì¶È£¨2·Ö£©
½âÎö