ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿¡¾ºþ±±Ê¡»ªÖÐʦ·¶´óѧµÚÒ»¸½ÊôÖÐѧ2017½ì¸ßÈý5ÔÂѺÌ⿼ÊÔÀí×Û»¯Ñ§ÊÔÌâ¡¿2011Ä꣬ÂéÊ¡Àí¹¤Ñ§Ôº¿ÆÑÐÍŶÓÑз¢³öÒ»ÖÖÈËÔìÊ÷Ò¶£¬Ëü½«Ò»Æ¬°ëµ¼Ìå²ÄÁϼÐÔÚÁ½²ãÌØÊâµÄ´ß»¯¼ÁµÄÖм䡣Èô½«ÈËÔìÊ÷Ò¶ÕûÌå½þÅÝÔÚÈÜÒºÖУ¬µ±¹âÕÕÔÚÈËÔìÊ÷Ò¶ÉÏ£¬¾Í»á·Ö½âË®Éú³ÉH2ºÍO2£¬½á¹¹ÈçͼËùʾ¡£ÏÂÁÐÓйØÈËÔìÊ÷Ҷ˵·¨ÕýÈ·µÄÊÇ
A. ¸Ã×°ÖÃ×îÖÕ½«Ì«ÑôÄÜת±äΪµçÄÜ
B. Ni¡¢Mo¡¢Zn»ù´ß»¯¼Á¼«ÎªÑô¼«£¬·¢ÉúÑõ»¯·´Ó¦
C. ¿ÉÒÔ½«ÈËÔìÊ÷Ò¶½þÅÝÔÚ¼îÐÔÈÜÒºÖÐ
D. îÜ»ù´ß»¯¼ÁÉÏ·¢Éú·´Ó¦£º2H2O-4e-=4H++O2¡ü
¡¾´ð°¸¡¿D
¡¾½âÎö¡¿A. ¸Ã×°ÖÃ×îÖÕ½«Ì«ÑôÄÜת±äΪµçÄÜ£¬ÔÙת»¯Îª»¯Ñ§ÄÜ£¬¹ÊA´íÎó£»B. Ni¡¢Mo¡¢Zn»ù´ß»¯¼Á¼«ÎªÕý¼«£¬±¾Éí²»·´Ó¦£¬H£« µÃµç×Ó£¬·¢Éú»¹Ô·´Ó¦£¬¹ÊB´íÎó£»C. ²»¿ÉÒÔ½«ÈËÔìÊ÷Ò¶½þÅÝÔÚ¼îÐÔÈÜÒºÖУ¬¼îÐÔÌõ¼þÏ£¬¸º¼«²»ÄܲúÉúH£« £¬¹ÊC´íÎó£»D. îÜ»ù´ß»¯¼ÁÔÚ¸º¼«£¬¸º¼«·¢ÉúÑõ»¯·´Ó¦£¬·¢Éú·´Ó¦£º2H2O-4e-=4H++O2¡ü£¬¹ÊDÕýÈ·£»¹ÊÑ¡D¡£
¡¾ÌâÄ¿¡¿ÎåÂÈ»¯Á×(PCl5)ÊÇÓлúºÏ³ÉÖÐÖØÒªµÄÂÈ»¯¼Á,¿ÉÒÔÓÉÈýÂÈ»¯Á×(PCl3)ÂÈ»¯µÃµ½:
PCl3(g)+Cl2(g)PCl5(g)¡¡¦¤H=-93.0 kJ¡¤mol-1¡£Ä³Î¶ÈÏÂ,ÔÚÈÝ»ýºã¶¨Îª2.0 LµÄÃܱÕÈÝÆ÷ÖгäÈë2.0 mol PCl3ºÍ1.0 mol Cl2,Ò»¶Îʱ¼äºó·´Ó¦´ïƽºâ״̬,ʵÑéÊý¾ÝÈçϱíËùʾ:
t/s | 0 | 50 | 150 | 250 | 350 |
n(PCl5)/mol | 0 | 0.24 | 0.36 | 0.40 | 0.40 |
(1)0¡«150 sÄÚµÄƽ¾ù·´Ó¦ËÙÂÊv(PCl3)=________mol¡¤L-1¡¤s-1¡£
(2)¸ÃζÈÏÂ,´Ë·´Ó¦µÄ»¯Ñ§Æ½ºâ³£ÊýµÄÊýֵΪ____(¿ÉÓ÷ÖÊý±íʾ)¡£
(3)·´Ó¦ÖÁ250 sʱ,¸Ã·´Ó¦·Å³öµÄÈÈÁ¿Îª________kJ¡£
(4)ÏÂÁйØÓÚÉÏÊö·´Ó¦µÄ˵·¨ÖÐ,ÕýÈ·µÄÊÇ______(Ìî×Öĸ)¡£
a.ÎÞÂÛÊÇ·ñ´ïƽºâ״̬,»ìºÏÆøÌåµÄÃܶÈʼÖÕ²»±ä
b.300 sʱ,Éý¸ßζÈ,Õý¡¢Äæ·´Ó¦ËÙÂÊͬʱÔö´ó
c.350 sʱ,Ïò¸ÃÃܱÕÈÝÆ÷ÖгäÈ뵪Æø,ƽºâÏòÕý·´Ó¦·½ÏòÒƶ¯
d.ÏàͬÌõ¼þÏÂ,ÈôÆðʼÏò¸ÃÃܱÕÈÝÆ÷ÖгäÈë1.0 mol PCl3ºÍ0.2 mol Cl2,´ïµ½»¯Ñ§Æ½ºâ״̬ʱ,n(PCl5)<0.20 mol
(5)ζÈT1ʱ,»ìºÏÆøÌåÖÐPCl5µÄÌå»ý·ÖÊýËæʱ¼ät±ä»¯µÄʾÒâͼÈçÉÏ¡£ÆäËûÌõ¼þÏàͬ,ÇëÔÚÉÏͼÖл³öζÈΪT2(T2>T1)ʱ,PCl5µÄÌå»ý·ÖÊýËæʱ¼ä±ä»¯µÄÇúÏß________¡£