ÌâÄ¿ÄÚÈÝ
¢ñ.ÈôÓÃÏÂͼËùʾװÖÃÀ´ÖÆÈ¡NO2ÆøÌ壬ʵÑé²½ÖèÈçÏ£º£¨1£©ÆøÃÜÐÔ¼ì²é£ºÇë»Ø´ð¸Ã×°ÖÃÆøÃÜÐÔ¼ì²éµÄ×î¼òµ¥µÄ·½·¨£º
_____________________________________________________________________¡£
£¨2£©¼ÓÈë¹ÌÌåÊÔ¼ÁCuƬ£¬´ò¿ª·§ÃÅK£¬°Î³ö×¢ÉäÆ÷»îÈû£¬¼ÓÈëһСƬCuƬ½«×¢ÉäÆ÷»îÈû×°Éϲ¢Ñ¹ÖÁµ×²¿£¬ÅųöÀïÃæµÄ¿ÕÆø¡£
£¨3£©ÎüȡŨHNO3£¬½«×¢ÉäÆ÷¼â×ìµ¼¹Ü²åÈëŨHNO3ÖУ¬²¢ÏòÉÏÀ×¢ÉäÆ÷»îÈûÎüÈ¡ÉÙÁ¿µÄŨHNO3£¬È»ºóѸËٹرշ§ÃÅK£¬Çë»Ø´ð´Ëʱ¿ÉÄܹ۲쵽µÄʵÑéÏÖÏó£º______________________________________________________________£¬µ±Éú³ÉµÄNO2ÆøÌåÌå»ý½Ó½ü×î´ó¿Ì¶Èʱ£¬Ñ¸ËÙ´ò¿ª·§ÃÅK£¬½«·´Ó¦Òº·ÅÈëNaOHÈÜÒºÖкó¹Ø±ÕK¡£
¢ò.NO2ÐÔÖÊʵÑé
£¨1£©¹Û²ìÊÕ¼¯µ½µÄÆøÌå³Ê____________É«£¬ÈôÏòÏÂÓÃÁ¦Ñ¹»îÈû£¬·¢ÏÖÆøÌåµÄÑÕÉ«ÏȱäÉºó±ädz£¬ÔÒòÊÇ__________________________________________________________________¡£
£¨2£©ÎªÁËÑéÖ¤½øÐÐʵÑ飨2£©ºó×¢ÉäÆ÷ÖеÄÆøÌ壬ÇëÉè¼ÆһʵÑé·½°¸¼ÓÒÔÑéÖ¤£º
______________________________________________________________¡£
¢ó.½«Ê¢ÓÐa mol NO2ºÍb mol NO»ìºÏÆøÌåµÄÊԹܵ¹Á¢ÓÚË®²ÛÖУ¬ÔÙͨÈëc mol O2£¬³ä·Ö·´Ó¦ºó£¬ÊÔ¹ÜÀïÊ£ÓàÆøÌåµÄ³É·Ö¼°ÎïÖʵÄÁ¿¾ö¶¨ÓÚa¡¢bºÍcµÄ¹Øϵ£¬ÇëÍê³ÉÏÂÃæ±í¸ñ¡£
a¡¢bºÍcµÄ¹Øϵ | Ê£ÓàÆøÌåµÄ³É·Ö | Ê£ÓàÆøÌåµÄÎïÖʵÄÁ¿ |
4c=a+3b |
|
|
|
| (a+3b-4c)/3 |
| O2 |
|
¢ñ.£¨1£©ÏÈ´ò¿ª»îÈûK£¬ÎüÈ벿·Ö¿ÕÆø¹Øϵ»îÈûK£¬¼ÇÏ¿̶ȣ¬È»ºóÍÆ»òÀ×¢ÉäÆ÷»îÈû£¬ËÉÊÖºó¿´×¢ÉäÆ÷»îÈûÊÇ·ñ¸´Ô£¨»òÏÈ´ò¿ª»îÈûK£¬ÎüÈ벿·Ö¿ÕÆø£¬¹Ø±Õ»îÈûK¡£È»ºóÓÃÊÖÎÕסעÉäÆ÷ÓпÕÆøµÄ²¿·Ö£¬¿´»îÈûÊÇ·ñÉÏÒÆ£¬ËÉÊÖƬ¿Ìºó£¬ÔÙ¿´»îÈûÊÇ·ñ¸´Ô£©
£¨3£©Å¨HNO3ÓëCuƬ¾çÁÒ·´Ó¦²¢Öð½¥Èܽ⣬²úÉú´óÁ¿ºì×ØÉ«ÆøÌ壬ÈÜÒºµÄÑÕÉ«³ÊÂÌÉ«£¨À¶É«£©£¬×¢ÉäÆ÷»îÈû²»¶ÏÉÏÒÆ
¢ò.£¨1£©ºì×Ø ¿ªÊ¼Ê±Ìå»ýËõС£¬NO2Ũ¶ÈÔö´ó£¬ÑÕÉ«±äÉºóÓÉÓÚ¿ÉÄæ·´Ó¦2NO2N2O4£¬¼ÓѹºóƽºâÏòÕý·´Ó¦·½ÏòÒƶ¯£¬¹ÊÑÕÉ«ÓÖ±ädz£¬µ«ÈÔ±ÈÔÀ´Éî
£¨2£©´ò¿ª»îÈûK£¬·Å³ö×¢ÉäÆ÷ÄÚË®ÈÜÒº£¬È»ºóÀ×¢ÉäÆ÷»îÈûÎüÈ벿·Ö¿ÕÆø£¬Èô×¢ÉäÆ÷ÄÚµÄÆøÌåѸËÙ±äΪºì×ØÉ«£¬ÔòÖ¤Ã÷NO2ÓëË®·´Ó¦Éú³ÉµÄÆøÌåΪNO
¢ó.¼ûϱí
a¡¢bºÍcµÄ¹Øϵ | Ê£ÓàÆøÌåµÄ³É·Ö | Ê£ÓàÆøÌåµÄÎïÖʵÄÁ¿ |
| ÎÞ | 0 |
4c£¼a+3b | NO |
|
4c£¾a+3b |
| £¨4c-a-3b£©/4 |
½âÎö£º±¾ÌâÖ÷Òª¿¼²éÁËNO2µÄÖÆÈ¡£¬NO2µÄÐÔÖʼ°NOxµÄÓйؼÆËã¡£¢ñ.ŨHNO3ÓëCu·´Ó¦µÄʵÑéÏÖÏóÊÇ£ºCuƬÖð½¥Èܽ⣬²úÉú´óÁ¿ºì×ØÉ«ÆøÌ壬ÈÜÒºµÄÑÕÉ«³ÊÂÌÉ«£¨À¶É«£©£¬×¢ÉäÆ÷»îÈû²»¶ÏÉÏÒÆ¡£¢ò.ѹËõNO2ÆøÌ壬NO2Ũ¶ÈÔö´ó£¬ÑÕɫͻȻ±äÉºóÓÉÓÚ¿ÉÄæ·´Ó¦2NO2N2O4£¬¼ÓѹºóƽºâÏòÕý·´Ó¦·½ÏòÒƶ¯£¬¹ÊÑÕÉ«ÓÖ±ädz£¬µ«ÈÔ±ÈÔÀ´Éî¡£¢ó.¸ù¾Ý4NO2+O2+2H2O====4HNO3£¬4NO+3O2+2H2O====4HNO3 a mol NO2¡¢b mol NO£¬Í¨Èëc mol O2»ìºÏ£¬Èô4c=a+3b£¬ÎÞÊ£ÓàÆøÌ壻Èô4c£¼a+3b£¬Ê£ÓàNO£¬n£¨NO£©=£»Èô4c£¾a+3b£¬Ê£ÓàO2£¬n£¨O2£©=¡£