ÌâÄ¿ÄÚÈÝ

(08Õã½­Ê¡¿ª»¯ÖÐѧģÄâ)ÏÂÁÐÊÂʵÖУ¬ÄÜÖ¤Ã÷NH3?H2OÊÇÈõµç½âÖʵÄÊÇ£¨ £©   

A£®³£ÎÂʱ£¬Ï¡°±Ë®µÄµ¼µçÐÔ±ÈÏ¡NaOHÈÜÒºµÄµ¼µçÐÔÈõ

B£®³£ÎÂʱ£¬µÈŨ¶ÈµÈÌå»ýµÄ°±Ë®ºÍÑÎËá»ìºÏ£¬»ìºÏÒºpHСÓÚ7

C£®1mol?L£­1µÄ°±Ë®¿ÉÒÔʹ·Ó̪ÊÔÒº±äºìÉ«                  

D£®Òº°±²»µ¼µç

´ð°¸;B
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

2(08Õã½­Ê¡¿ª»¯ÖÐѧģÄâ)ʵÑéÊÒÖиù¾Ý2SO2£«O22SO3£»¦¤H=-393.2 kJ?mol-1Éè¼ÆÈçÏÂͼËùʾʵÑé×°ÖÃÀ´ÖƱ¸SO3¹ÌÌå¡£Çë»Ø´ðÏÂÁÐÎÊÌâ¡£  

 
 

 


£¨1£©ÊµÑéÇ°£¬±ØÐë½øÐеIJÙ×÷ÊÇ£¨Ìî²Ù×÷Ãû³Æ£¬²»±Øд¾ßÌå¹ý³Ì£©¡¡¡¡¡¡¡¡¡¡¡¡

£¨2£©ÔÚA×°ÖÃÖмÓÈëNa2SO3¹ÌÌåµÄͬʱ£¬»¹Ðè¼Ó¼¸µÎË®£¬È»ºóÔٵμÓŨÁòËá¡£¼Ó¼¸µÎË®µÄ×÷ÓÃÊÇ                           ¡¡                            

£¨3£©Ð¡ÊÔ¹ÜCµÄ×÷ÓÃÊÇ                                                   

£¨4£©¹ã¿ÚÆ¿DÄÚÊ¢µÄÊÔ¼ÁÊÇ                ¡£×°ÖÃDµÄÈý¸ö×÷ÓÃÊÇ       ¢Ù¡¡¡¡ ¡¡¡¡

            ¢Ú                   ¢Û                      

£¨5£©ÊµÑéÖе±Cr2O3±íÃæºìÈÈʱ£¬Ó¦½«¾Æ¾«µÆÒÆ¿ªÒ»»á¶ùÔÙ¼ÓÈÈ£¬ÒÔ·Àζȹý¸ß£¬ÕâÑù×öµÄÔ­ÒòÊÇ                          ¡¡                                   ¡¡

£¨6£©×°ÖÃFÖÐUÐ͹ÜÄÚÊÕ¼¯µ½µÄÎïÖʵÄÑÕÉ«¡¢×´Ì¬ÊÇ                         

£¨7£©×°ÖÃGµÄ×÷ÓÃÊÇ                                                      

£¨8£©´ÓG×°Öõ¼³öµÄβÆø´¦Àí·½·¨ÊÇ                                        

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø