ÌâÄ¿ÄÚÈÝ

£¨12·Ö£©£¨1£©H+¿ÉÓëH2OÐγÉH3O+£¬H3O+ÖÐOÔ­×Ó²ÉÓà         ÔÓ»¯£¬Æä¼ü½Ç±ÈË®·Ö×Ó     £¨Ìî¡°´ó¡±»ò¡°Ð¡¡±£©¡£
£¨2£©ÏÂÁÐÊÇÄÆ¡¢µâ¡¢½ð¸Õʯ¡¢¸É±ù¡¢ÂÈ»¯Äƾ§ÌåµÄ¾§°ûʾÒâͼ£¨Î´°´Ë³ÐòÅÅÐò£©¡£ÉÏÊöÎåÖÖ¾§ÌåÖо§ÌåÀàÐÍÏàͬµÄÊÇ                    £»£¨Ìîд±àºÅ£©¡£

£¨3£©ÔÚ±ùµÄ¾§ÌåÖУ¬Ã¿¸öË®·Ö×ÓÓëÏàÁÚµÄ 4 ¸öË®·Ö×ÓÐγÉÇâ¼ü£¨ÈçͼËùʾ£©£¬ÒÑÖª±ùµÄÉý»ªÈÈ£¨¼´ 1 mol Ë®Óɱùת»¯ÎªË®ÕôÆûËùÐèÄÜÁ¿£©ÊÇ51KJ/mol£¬³ýÇâ¼üÍ⣬ˮ·Ö×Ӽ仹´æÔÚ·¶µÂ»ªÁ¦£¨11 kJ / mol £© , Ôò±ù¾§ÌåÖÐÇâ¼üµÄ¡°¼üÄÜ¡±£¨ÆÆ»µ lmol Çâ¼üËùÐèµÄÄÜÁ¿¼´ÎªÇâ¼üµÄ¡°¼üÄÜ¡±£©ÊÇ                kJ / mol ¡£

£¨4£©CaOÓëNaClµÄ¾§°ûͬΪÃæÐÄÁ¢·½½á¹¹£¬ÒÑÖªCaO¾§ÌåÃܶÈΪag¡¤cm-3£¬±íʾ°¢·ü¼ÓµÂÂÞ³£Êý£¬ÔòCaO¾§°ûÌå»ýΪ       cm3¡£
£¨5£©ÔÚËáÐÔÈÜÒºÖÐ,·¢ÉúµÄÑõ»¯»¹Ô­·´Ó¦Öб»Ñõ»¯Óë±»»¹Ô­µÄµÄÔªËصÄÎïÖʵÄÁ¿Ö®±ÈΪ2:5,
¡õKBiO3+¡õMnSO4+¡õH2SO4==¡õBi2(SO4)3+¡õ    +¡õ    +¡õ                                
д³öBiͬÖ÷×åµÚËÄÖÜÆÚÔªËصĵç×ÓÅŲ¼Ê½£º                           
£¨12·Ö£©£¨1£©SP3    ´ó £¨¸÷1·Ö£©    £¨2£©BC £¨2·Ö£© 
£¨3£©20 £¨2·Ö£©£¨4£©      £¨2·Ö£©
£¨5£©10KBiO3+4MnSO4+14H2SO4==5Bi2(SO4)3+4KMnO4+14H2O+3K2SO4  (2·Ö)
1s22s22p63s23p63d104s24p3   (2·Ö)
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨14·Ö£©ÒÑÖªA¡¢B¡¢C¡¢D¡¢E¶¼ÊÇÖÜÆÚ±íÖÐÇ°ËÄÖÜÆÚµÄÔªËØ£¬ËüÃǵĺ˵çºÉÊýÒÀ´ÎÔö¼Ó¡£ÆäÖÐAÓëB ¡¢AÓëDÔÚÖÜÆÚ±íÖÐλÖÃÏàÁÚ£¬AÔ­×ÓºËÍâÓÐÁ½¸öδ³É¶Ôµç×Ó£¬BÔªËصĵÚÒ»µçÀëÄܱÈͬÖÜÆÚÏàÁÚÁ½¸öÔªËض¼´ó£¬CÔ­×ÓÔÚͬÖÜÆÚÔ­×ÓÖа뾶×î´ó£¨Ï¡ÓÐÆøÌå³ýÍ⣩£»EÓëCλÓÚ²»Í¬ÖÜÆÚ£¬EÔ­×ÓºËÍâ×îÍâ²ãµç×ÓÊýÓëCÏàͬ£¬ÆäÓà¸÷²ãµç×Ó¾ù³äÂú¡£Çë¸ù¾ÝÒÔÉÏÐÅÏ¢£¬»Ø´ðÏÂÁÐÎÊÌ⣺£¨´ðÌâʱA¡¢B¡¢C¡¢D¡¢EÓÃËù¶ÔÓ¦µÄÔªËØ·ûºÅ±íʾ£©

£¨1£©A¡¢B¡¢C¡¢DËÄÖÖÔªËص縺ÐÔÓÉ´óµ½Ð¡ÅÅÁÐ˳ÐòΪ                              
£¨2£©CÐγɵľ§ÌåÖУ¬Æä΢Á£¶Ñ»ý·½Ê½Îª          ;
£¨3£©Dµ¥ÖʵÄÈÛµãºÜ¸ß£¬¿ÉÓÃ×÷¼ÆËã»úµÄºËÐIJ¿¼þ£¬µ«»á±»ÇâÑõ»¯ÄÆÈÜÒº¸¯Ê´£¬Æ丯ʴµÄÀë×Ó·½³ÌʽΪ£º                                     £»DµÄÑõ»¯ÎïÔÚͨѶ·½ÃæÓÐÖØÒªÓÃ;£¬90¿ËDµÄÑõ»¯ÎïÖк¬¹²¼Û¼üµÄÊýĿΪ             ¡£
£¨4£©EºËÍâµç×ÓÅŲ¼Ê½ÊÇ                                £¬EµÄijÖÖ»¯ºÏÎïµÄ½á¹¹ÈçͼËùʾ£¬Ôò´Ë»¯ºÏÎïÖи÷ÖÖÁ£×Ó¼äµÄÏ໥×÷ÓÃÁ¦ÓР                                   
£¨I£©¶àÏîÑ¡ÔñÌâ
ÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ       ¡£
A£®±ûÏ©·Ö×ÓÖÐÓÐ8¸ö¦Ò¼ü£¬1¸ö¦Ð¼ü
B£®ÔÚSiO2¾§ÌåÖУ¬1¸öSiÔ­×ÓºÍ2¸öOÔ­×ÓÐγÉ2¸ö¹²¼Û¼ü
C£®NF3µÄ·Ðµã±ÈNH3µÄ·ÐµãµÍµÃ¶à£¬ÊÇÒòΪNH3·Ö×Ó¼äÓÐÇâ¼ü£¬NF3Ö»Óз¶µÂ»ªÁ¦
D£®NCl3ºÍBC13·Ö×ÓÖУ¬ÖÐÐÄÔ­×Ó¶¼²ÉÓÃsp3ÔÓ»¯
E£®SO3ÓëCO32£­»¥ÎªµÈµç×ÓÌ壬SO3ÊǼ«ÐÔ·Ö×Ó
£¨II£©ÈËÀàÔÚʹÓýðÊôµÄÀúÊ·½ø³ÌÖУ¬¾­ÀúÁËÍ­¡¢Ìú¡¢ÂÁÖ®ºó£¬µÚËÄÖÖ½«±»¹ã·ºÓ¦ÓõĽðÊô±»¿Æѧ¼ÒÔ¤²âÊÇîÑ(Ti)£¬Ëü±»ÓþΪ¡°Î´À´ÊÀ¼ÍµÄ½ðÊô¡±¡£ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©TiÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃÊǵÚ________ÖÜÆÚµÚ________×壻Æä»ù̬ԭ×ӵĵç×ÓÅŲ¼Ê½Îª________¡£
£¨2£©ÔÚTiµÄ»¯ºÏÎïÖУ¬¿ÉÒÔ³ÊÏÖ£«2¡¢£«3¡¢£«4ÈýÖÖ»¯ºÏ¼Û£¬ÆäÖÐÒÔ£«4¼ÛµÄTi×îΪÎȶ¨¡£Æ«îÑËá±µµÄÈÈÎȶ¨ÐԺ㬽éµç³£Êý¸ß£¬ÔÚСÐͱäѹÆ÷¡¢»°Í²ºÍÀ©ÒôÆ÷Öж¼ÓÐÓ¦Óã®Æ«îÑËá±µ¾§ÌåÖо§°ûµÄ½á¹¹Ê¾ÒâͼÈçÓÒͼËùʾ£¬ËüµÄ»¯Ñ§Ê½ÊÇ           £¬ÆäÖÐTi4£«µÄÑõÅäλÊýΪ        £¬Ba2£«µÄÑõÅäλÊýΪ         £¬

£¨3£©³£ÎÂϵÄTiCl4ÊÇÓд̼¤ÐÔ³ôζµÄÎÞɫ͸Ã÷ÒºÌ壬ÈÛµã-23.2¡æ£¬·Ðµã136.2¡æ£¬ËùÒÔTiCl4ÊÇ       ¾§Ìå¡£
4£©ÒÑÖªTi3£«¿ÉÐγÉÅäλÊýΪ6µÄÅäºÏÎÆä¿Õ¼ä¹¹ÐÍΪÕý°ËÃæÌ壬ÈçÏÂͼ1Ëùʾ£¬ÎÒÃÇͨ³£¿ÉÒÔÓÃÏÂͼ2ËùʾµÄ·½·¨À´±íʾÆä¿Õ¼ä¹¹ÐÍ£¨ÆäÖÐA±íʾÅäÌ壬M±íʾÖÐÐÄÔ­×Ó£©¡£Åäλ»¯ºÏÎï[Co(NH3)4Cl2]µÄ¿Õ¼ä¹¹ÐÍҲΪ°ËÃæÌåÐÍ£¬ËüÓР      ÖÖͬ·ÖÒì¹¹Ìå¡£

£¨¢ó£©
(1)ÒÑÖª¹ýÑõ»¯Çâ·Ö×ӵĿռä½á¹¹ÈçÓÒͼËùʾ£¬·Ö×ÓÖÐÑõÔ­×Ó²ÉÈ¡      ÔÓ»¯¡£
(2)RÊÇ1~36
ºÅÔªËØÖÐδ³É¶Ôµç×ÓÊý×î¶àµÄÔ­×Ó¡£R3+ÔÚÈÜÒºÖдæÔÚÈçÏÂת»¯¹Øϵ£º

R3+  R(OH)3  [R(OH)4]£­
¢Ù»ù̬RÔ­×ӵļ۵ç×ÓÅŲ¼Ê½Îª                       £»
¢Ú[R(OH)4]£­ÖдæÔڵĻ¯Ñ§¼üÊÇ            ¡£
A£®Àë×Ó¼ü     B£®¼«ÐÔ¼ü    C£®·Ç¼«ÐÔ¼ü     D£®Åäλ¼ü

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø