ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿îܼ°Æ仯ºÏÎï¹ã·ºÓ¦ÓÃÓÚ´ÅÐÔ²ÄÁÏ¡¢µç³Ø²ÄÁϼ°³¬Ó²²ÄÁϵÈÁìÓò¡£

£¨1£©CoxNi(1-x)Fe2O4£¨ÆäÖÐCo¡¢Ni¾ùΪ+2£©¿ÉÓÃ×÷H2O2·Ö½âµÄ´ß»¯¼Á£¬¾ßÓнϸߵĻîÐÔ¡£

¢Ù¸Ã´ß»¯¼ÁÖÐÌúÔªËصĻ¯ºÏ¼ÛΪ______¡£

¢Úͼ1±íʾÁ½ÖÖ²»Í¬·½·¨ÖƵõĴ߻¯¼ÁCoxNi(1-x)Fe2O4ÔÚ10¡æʱ´ß»¯·Ö½â6%µÄH2O2ÈÜÒºµÄÏà¶Ô³õʼËÙÂÊËæx±ä»¯ÇúÏß¡£ÓÉͼÖÐÐÅÏ¢¿ÉÖª£º______________·¨ÖÆÈ¡µÃµ½µÄ´ß»¯¼Á»îÐÔ¸ü¸ß£»Co2+¡¢Ni2+Á½ÖÖÀë×ÓÖд߻¯Ð§¹û¸üºÃµÄÊÇ______¡£

£¨2£©²ÝËáîÜÊÇÖƱ¸îܵÄÑõ»¯ÎïµÄÖØÒªÔ­ÁÏ¡£ÏÂͼ2Ϊ¶þË®ºÏ²ÝËáîÜ£¨CoC2O4¡¤2H2O£©ÔÚ¿ÕÆøÖÐÊÜÈȵÄÖÊÁ¿±ä»¯ÇúÏߣ¬ÇúÏßÖÐ300¡æ¼°ÒÔÉÏËùµÃ¹ÌÌå¾ùΪîÜÑõ»¯Îï¡£

¢Ùͨ¹ý¼ÆËãÈ·¶¨AµãÊ£Óà¹ÌÌåµÄ»¯Ñ§³É·ÖΪ________________£¨Ìѧʽ£©¡£ÊÔд³öBµã¶ÔÓ¦µÄÎïÖÊÓëO2ÔÚ225¡æ~300¡æ·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_________________________________________¡£

¢ÚÈ¡Ò»¶¨ÖÊÁ¿µÄ¶þË®ºÏ²ÝËáîÜ·Ö½âºóµÄîÜÑõ»¯ÎÆäÖÐCoµÄ»¯ºÏ¼ÛΪ+2¡¢+3£©£¬ÓÃ480 mL 5 mol/LÑÎËáÇ¡ºÃÍêÈ«Èܽâ¹ÌÌ壬µÃµ½CoCl2ÈÜÒººÍ4.48 L£¨±ê×¼×´¿ö£©»ÆÂÌÉ«ÆøÌå¡£ÊÔÈ·¶¨¸ÃîÜÑõ»¯ÎïÖÐCo¡¢OµÄÎïÖʵÄÁ¿Ö®±ÈΪ___________¡£

¡¾´ð°¸¡¿+3΢²¨Ë®ÈÈCo2+CoC2O4 3CoC2O4 + 2O2 = Co3O4 +6CO2n(Co): n(O)=1mol: 1.2mol=5:6

¡¾½âÎö¡¿

£¨1£©¢Ù¸ù¾Ý»¯ºÏ¼Û´úÊýºÍΪ0¼ÆËãFeµÄ»¯ºÏ¼Û£¬CoxNi(1-x)Fe2O4ÖÐCo¡¢Ni¾ùΪ+2£¬OΪ-2¼Û£¬ÔòFeµÄ»¯ºÏ¼ÛΪ=+3£»

¢Ú¹ýÑõ»¯ÇâµÄ·Ö½âËÙÂÊÔ½´ó£¬´ß»¯¼Á»îÐÔ¸ü¸ß£¬¸ù¾ÝͼÏó¿ÉÖª£¬xÏàͬʱ£¬Î¢²¨Ë®ÈÈ·¨³õʼËٶȴóÓÚ³£¹æË®ÈÈ·¨£¬ËùÒÔ΢²¨Ë®ÈÈ·¨ÖƵô߻¯¼ÁµÄ»îÐÔ¸ü¸ß£»ÓÉͼ¿ÉÖª£¬ËæxÖµÔ½´ó£¬¹ýÑõ»¯ÇâµÄ·Ö½âËÙÂÊÔ½´ó£¬¶øxÔö´ó£¬Co2+µÄ±ÈÀýÔö´ó£¬ËùÒÔCo2+µÄ´ß»¯»îÐÔ¸ü¸ß£»

£¨2£©¢ÙÓÉͼ¿ÉÖª£¬CoC2O4¡¤2H2OµÄÖÊÁ¿Îª18.3g£¬ÎïÖʵÄÁ¿Îª =0.1mol£¬CoÔªËØÖÊÁ¿Îª5.9g£¬CµãîÜÑõ»¯ÎïÖÊÁ¿Îª8.03g£¬Ñõ»¯ÎïÖÐÑõÔªËØÖÊÁ¿Îª8.03g-5.9g=2.13g£¬ÔòÑõ»¯ÎïÖÐCoÔ­×ÓÓëOÔ­×ÓÎïÖʵÄÁ¿Ö®±ÈΪ0.1mol£ºmol¡Ö3£º4£¬ËùÒÔCµÄCoÑõ»¯ÎïΪCo3O4£»Bµã¶ÔÓ¦ÎïÖʵÄÖÊÁ¿Îª14.7g£¬ÓëÆäÆðʼÎïÖʵÄÖÊÁ¿Ïà±È¼õÉÙ18.3g-14.7g=3.6g£¬Îª½á¾§Ë®µÄÖÊÁ¿£¬ËùÒÔBµãÎïÖÊΪCoC2O4£¬ÓëÑõÆø·´Ó¦Éú³ÉCo3O4Óë¶þÑõ»¯Ì¼£¬·´Ó¦·½³ÌʽΪ3CoC2O4 + 2O2 = Co3O4 +6CO2£»

¢ÚÓɵç×ÓÊغ㣺n(Co3+) = 2 n(Cl2) = 0.4 mol£¬ÓɵçºÉÊغ㣺n(Co)×Ü =n(Co2+)ÈÜÒº= 0.5 n(Cl£­) = 0.5¡Á( 2.4mol£­0.2mol¡Á2)= 1 mol£¬ËùÒÔ¹ÌÌåÖеÄn(Co2+)= 1mol£­0.4mol= 0.6 mol£»n(O)==1.2mol£¬ËùÒÔn(Co): n(O)=1mol: 1.2mol=5£º6¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿¹¤ÒµÉÏÒÔ¸õÌú¿ó(Ö÷Òª³É·ÖΪFeOºÍCr2O3£¬º¬ÓÐAl2O3¡¢SiO2µÈÔÓÖÊ)ΪÖ÷ÒªÔ­ÁÏÉú²ú»¯¹¤Ô­ÁϺ췯ÄÆ(Ö÷Òª³É·ÖΪ:Na2Cr2O7¡¤2H2O)£¬ÆäÖ÷Òª¹¤ÒÕÁ÷³ÌÈçÏ£º

²éÔÄÏà¹Ø×ÊÁϵÃÖª:

i.³£ÎÂÏ£¬NaBiO3²»ÈÜÓÚË®£¬ÓÐÇ¿Ñõ»¯ÐÔ£¬ÔÚ¼îÐÔÌõ¼þÏÂÄܽ«Cr3+ת»¯ÎªCrO42£­£¬×ÔÉí±»»¹Ô­ÎªBi(OH)3¹ÌÌå¡£

ii.

ÎïÖÊ

¿ªÊ¼³ÁµíµÄpH

ÍêÈ«³ÁµíµÄpH

Fe(OH)3

2.7

3.7

Al(OH)3

3.4

4.4

Cr(OH)3

4.6

5.9

Fe(OH)2

7.5

9.7

Bi(OH)3

0.7

4.5

»Ø´ðÏÂÁÐÎÊÌâ:

(1)½«¸õÌú¿ó¿óʯ·ÛËéµÄÄ¿µÄÊÇ________________________________________¡£

(2)²Ù×÷I¡¢III¡¢IVÓõ½µÄÖ÷Òª²£Á§ÒÇÆ÷Óв£Á§°ôºÍ___________£¨ÌîÒÇÆ÷Ãû³Æ£©¡£

(3)д³ö¢Ü·´Ó¦µÄ»¯Ñ§·½³Ìʽ_____________________________________________¡£

(4)¢ÝÖÐËữÊÇʹCrO42£­×ª»¯ÎªCr2O72£­Ð´³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ______¡£

(5)½«ÈÜÒºH¾­ÏÂÁвÙ×÷£ºÕô·¢Å¨Ëõ£¬__________£¬¹ýÂË£¬Ï´µÓ£¬¸ÉÔï¼´µÃºì·¯ÄÆ¡£

(6)È¡Ò»¶¨ÖÊÁ¿µÄ¹ÌÌåDÈܽâÓÚ200 mLµÄÏ¡ÁòËáÖУ¬ÏòËùµÃÈÜÒºÖмÓÈë5.0 mol/LµÄNaOHÈÜÒº£¬Éú³É³ÁµíµÄÎïÖʵÄÁ¿£¨n£©Óë¼ÓÈëNaOHÈÜÒºµÄÌå»ý£¨V£©¹ØϵÈçͼËùʾ£¬ÔòÏ¡ÁòËáµÄŨ¶ÈΪ_________£¬¹ÌÌåDÖк¬Fe»¯ºÏÎïµÄÎïÖʵÄÁ¿Îª___________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø