ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿°´ÒªÇóÌî¿Õ£º

£¨1£©ÃüÃûÏÂÁÐÓлúÎHOCH2CH2CHO_____£¬________¡£

£¨2£©È¼ÉÕijÓлúÎïA 1.50 g£¬Éú³É1.12 L(±ê×¼×´¿ö)CO2ºÍ0.05 mol H2O£¬¸ÃÓлúÎïµÄÕôÆø¶Ô¿ÕÆøµÄÏà¶ÔÃܶÈÊÇ1.04£¬Ôò¸ÃÓлúÎïµÄ·Ö×ÓʽΪ_____¡£

£¨3£©ÒÑÖª¶ËȲÌþÔÚ´ß»¯¼Á´æÔÚÏ¿ɷ¢ÉúżÁª·´Ó¦:2RC¡ÔCHRC¡ÔC¡ªC¡ÔCR+H2,³ÆΪGlaser·´Ó¦£¬»Ø´ðÏÂÁÐÎÊÌ⣺

ÒÑÖª:£¬¸Ãת»¯¹ØϵµÄ²úÎïE£¨C16H10£©µÄ½á¹¹¼òʽÊÇ_______£¬ÓÃ1 mol EºÏ³É1,4¶þ±½»ù¶¡Í飬ÀíÂÛÉÏÐèÒªÏûºÄÇâÆø____mol¡£

¡¾´ð°¸¡¿3-ôÇ»ù±ûÈ© ÁÚ¼×»ù±½·Ó£¨2-¼×»ù±½·Ó£© CH2O 4

¡¾½âÎö¡¿

£¨1£©ÓлúÎﺬÓÐ3¸ö̼ԭ×Ó£¬Ö÷Á´ÊDZûÈ©£¬ôÇ»ùÁ¬½ÓÔÚ3ºÅ̼ԭ×ÓÉÏ£»¼×»ùºÍ·ÓôÇ»ù´¦ÓÚÁÚλ£¬Ä¸ÌåΪ±½·Ó£¬¼×»ùÁ¬½ÓÔÚ2ºÅ̼ԭ×ÓÉÏ£»

£¨2£©¸ÃÓлúÎïµÄÕôÆø¶Ô¿ÕÆøµÄÏà¶ÔÃܶÈÊÇ1.04£¬ËµÃ÷Ħ¶ûÖÊÁ¿Îª29g/mol¡Á1.04=30.16 g/mol£¬n(CO2)==0.05mol£¬ÓлúÎïÖÐ̼µÄÖÊÁ¿m(C)=0.05mol¡Á12g/mol=0.6g£¬ÇâµÄÖÊÁ¿m(H)=0.05mol¡Á2¡Á1g/mol=0.1g£¬m(C)+ m(H)<1.5g£¬ËµÃ÷ÓлúÎïAÖк¬ÓÐÑõÔªËØ£¬ÇÒm(O)=1.5g-0.6g-0.1g=0.8g£¬¸ù¾Ýn(A):n(C):n(H): n(O)È·¶¨ÓлúÎïµÄ·Ö×Óʽ£»

£¨3£©¸ù¾ÝGlaser·´Ó¦µÄ·´Ó¦Ô­ÀíÈ·¶¨EµÄ½á¹¹£»ÓëÇâÆø·¢Éú¼Ó³É·´Ó¦ºó¿ÉµÃ1,4¶þ±½»ù¶¡Í飻

£¨1£©ÓлúÎﺬÓÐ3¸ö̼ԭ×Ó£¬Ö÷Á´ÊDZûÈ©£¬ôÇ»ùÁ¬½ÓÔÚ3ºÅ̼ԭ×ÓÉÏ£¬Òò´Ë¸ÃÓлúÎïµÄÃû³ÆΪ3-ôÇ»ù±ûÈ©£»¼×»ùºÍ·ÓôÇ»ù´¦ÓÚÁÚλ£¬Ä¸ÌåΪ±½·Ó£¬¼×»ùÁ¬½ÓÔÚ2ºÅ̼ԭ×ÓÉÏ£¬Òò´Ë¸ÃÓлúÎïµÄÃû³ÆΪÁÚ¼×»ù±½·Ó»ò2-¼×»ù±½·Ó£»

£¨2£©ÓÉ·ÖÎö¿ÉÖªÓлúÎïAÖк¬ÓÐÑõÔªËØ£¬ÇÒm(O)=1.5g-0.6g-0.1g=0.8g£¬n(O)==0.05mol£¬ÓÖn(A)==0.05mol£¬Òò´Ën(A):n(C):n(H): n(O)=0.05:0.05:0.1:0.05=1:1:2:1£¬¸ÃÓлúÎïµÄ·Ö×ÓʽΪCH2O£»

£¨3£©¶ËȲÌþÔÚ´ß»¯¼Á´æÔÚ·¢ÉúGlaser·´Ó¦£¬Éú³ÉµÄEµÄ½á¹¹¼òʽΪ£» 1,4¶þ±½»ù¶¡ÍéµÄ½á¹¹Îª,Óë4molH2·¢Éú·´Ó¦¿ÉµÃ£»

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿Ñо¿¡¢¡¢µÈµÄ´¦Àí·½·¨¶Ô»·¾³±£»¤ÓÐÖØÒªÒâÒå¡£

£¨1£©¿Æѧ¼ÒÕýÔÚÑо¿ÀûÓô߻¯¼¼Êõ½«Î²ÆøÖеÄNOºÍCOת±ä³ÉºÍ£¬Æ䷴ӦΪ£º

¢ÙΪÁËÑо¿Íâ½çÌõ¼þ¶Ô¸Ã·´Ó¦µÄÓ°Ï죬½øÐÐϱíÈý×éʵÑ飬²âµÃ²»Í¬Ê±¿ÌNOµÄŨ¶È£¨c£©Ëæʱ¼ä±ä»¯µÄÇ÷ÊÆÈçͼ1Ëùʾ¡£1¡¢2¡¢3´ú±íµÄʵÑé±àºÅÒÀ´ÎÊÇ________¡££¨ÒÑÖªÔÚʹÓõÈÖÊÁ¿´ß»¯¼Áʱ£¬Ôö´ó´ß»¯¼Á±È±íÃæ»ý¿ÉÌá¸ß»¯Ñ§·´Ó¦ËÙÂÊ¡££©

ʵÑéζÈNO³õʼŨ¶ÈO³õʼŨ¶È´ß»¯¼Á±È±íÃæ»ý´ß»¯¼ÁÓÃÁ¿±àºÅ£¨¡æ£©

ʵÑé

񅧏

ζÈ

£¨¡æ£©

NO³õʼŨ¶È

CO³õʼŨ¶È

´ß»¯¼Á±È±íÃæ»ý

´ß»¯¼ÁÓÃÁ¿

£¨g£©

¢ñ

280

82

50

¢ò

280

124

50

¢ó

350

124

50

¢Úͼ2±íʾNOµÄƽºâת»¯ÂÊ£¨a£©Ëæζȡ¢Ñ¹Ç¿±ä»¯µÄʾÒâͼ¡£X±íʾµÄÊÇ________£¬ÀíÓÉÊÇ________£»Y±íʾµÄÊÇ________£¬ÇÒY1________Y2£¨Ìî¡°>¡±»ò¡°<¡±£©¡£

£¨2£©Ò»¶¨Î¶ÈÏ£¬½«ÓëÒÔÌå»ý±È1£º2ÖÃÓÚÃܱÕÈÝÆ÷Öз¢Éú·´Ó¦£¬´ïµ½Æ½ºâʱµÄÌå»ý·ÖÊýΪ25£¥¡£¸Ã·´Ó¦µÄƽºâ³£Êý________¡£

£¨3£©ÀûÓÃÔ­µç³Ø·´Ó¦¿ÉʵÏÖµÄÎÞº¦»¯£¬×Ü·´Ó¦Îª£¬µç½âÖÊÈÜҺΪ¼îÐÔ¡£¹¤×÷Ò»¶Îʱ¼äºó£¬¸Ãµç³Ø¸º¼«Çø¸½½üÈÜÒºpH________£¨Ìî¡°±ä´ó¡±¡¢¡°±äС¡±»ò¡°²»±ä¡±£©£¬Õý¼«µç¼«·´Ó¦Ê½Îª________¡£

¡¾ÌâÄ¿¡¿I.2017Äê5ÔÂ5ÈÕ£¬ÖйúÊ׼ܰ´ÕÕ¹ú¼Ê±ê×¼ÑÐÖƵÄÓµÓÐ×ÔÖ÷֪ʶ²úȨµÄ´óÐÍ¿Í»úC-919ÔÚÉϺ£ÆÖ¶«»ú³¡Ê×·É£¬¿Æѧ¼ÒÔÚʵÑéÊÒÖÐÑо¿µÄÀûÓô߻¯¼¼Êõ½«·É»úβÆøÖеÄNOºÍCOת±ä³ÉCO2ºÍN2µÄ·´Ó¦Îª2NO(g)+2CO(g)N2(g)+2CO2(g)¡÷H<0¡£

(1)Èô½«1mol NOºÍ2mol COͨÈë2LµÄºãÈÝÃܱÕÈÝÆ÷ÖУ¬ÔÚÒ»¶¨Ìõ¼þÏ·¢ÉúÉÏÊö·´Ó¦£¬·´Ó¦ÖÐÉú³ÉµÄN2µÄÎïÖʵÄÁ¿Å¨¶ÈËæʱ¼äµÄ±ä»¯Çé¿öÈçͼ1Ëùʾ¡£ÔòNO´Ó·´Ó¦¿ªÊ¼µ½Æ½ºâʱµÄƽ¾ù·´Ó¦ËÙÂÊv(NO)=__________£¬4minÄ©COµÄŨ¶ÈΪ__________mol¡¤L-1¡£

(2)ÒÑÖªÉÏÊö·´Ó¦ÖÐNOµÄƽºâת»¯ÂÊÓëѹǿ¡¢Î¶ȵĹØϵÈçͼ2Ëùʾ¡£¹¤ÒµÉÏ´ß»¯×°ÖÃÖбȽÏÊʺϵÄζȺÍѹǿÊÇ__________

II.È¡50 mL0.50mol¡¤L-1NaOHÈÜÒººÍ50 mL¡¢0.50mol/LÁòËáÈÜÒº½øÐÐÖкÍÈȲⶨʵÑ飬ʵÑéÊý¾ÝÈçÏÂ±í£º

(1)ÇëÌîд±íÖеĿհףº

ζÈ

ʵÑé´ÎÊý

ÆðʼζÈt1/¡æ

ÖÕֹζÈt2/¡æ

ζȲîƽ¾ùÖµ£¨t2-t1£©/¡æ

H2SO4

NaOH

ƽ¾ùÖµ

1

26.2

26.0

26.1

30.1

__________

2

27.0

27.4

27.2

31.3

3

25.9

25.9

25.9

29.8

4

26.4

26.2

26.3

31.4

(2)½üËÆÈÏΪ0.50mol¡¤L-1 NaOH ÈÜÒººÍ0.50mol¡¤L-1ÁòËáÈÜÒºµÄÃܶȶ¼ÊÇ1g¡¤cm-3£¬ÖкͺóÉú³ÉÈÜÒºµÄ±ÈÈÈÈÝc =4.18J¡¤g-1¡¤¡æ-1¡£ÔòÖкÍÈÈ¡÷H=__________¡£(ȡСÊýµãºóһλ)

(3)ÉÏÊöʵÑéÊýÖµ½á¹ûÓë57.3kJ¡¤mol-1ÓÐÆ«²î£¬²úÉúÆ«²îµÄÔ­Òò¿ÉÄÜÊÇ__________£¨Ìî×Öĸ£©¡£

a.ʵÑé×°Öñ£Î¡¢¸ôÈÈЧ¹û²î

b.Á¿È¡NaOHÈÜÒºµÄÌå»ýʱÑöÊÓ¶ÁÊý

c.·Ö¶à´Î°ÑNaOHÈÜÒºµ¹ÈëÊ¢ÓÐÁòËáµÄСÉÕ±­ÖÐ

d.ÓÃζȼƲⶨNaOHÈÜÒºÆðʼζȺóÖ±½Ó²â¶¨H2SO4ÈÜÒºµÄζÈ

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø