ÌâÄ¿ÄÚÈÝ

äåÒÒÍéÊÇÒ»ÖÖÖØÒªµÄ»¯¹¤ºÏ³ÉÔ­ÁÏ¡£ÊµÑéÊҺϳÉäåÒÒÍéµÄ·´Ó¦ºÍʵÑé×°ÖÃÈçÏ£º
·´Ó¦£ºCH3CH2OH+HBr CH3CH2Br+H2O
×°Öãº

ʵÑéÖпÉÄÜÓõ½µÄÊý¾ÝÈçÏÂ±í£º
ÎïÖÊ
Ïà¶Ô·Ö×ÓÖÊÁ¿
·Ðµã/¡æ
ÃܶÈ/g/cm3
Ë®ÈÜÐÔ
CH3CH2OH
46
78.4
0.79
»¥ÈÜ
CH3CH2Br
109
38.4
1.42
ÄÑÈÜ
CH3CH2OCH2CH3
74
34.5
0.71
΢ÈÜ
CH2=CH2
28
-103.7
0.38
²»ÈÜ
ŨÁòËᣨH2SO4£©
98
338.0
1.38
Ò×ÈÜ
 
¢ÙºÏ³É·´Ó¦£ºÔÚÒÇÆ÷BÖмÓÈëÊÊÁ¿NaBr¡¢Å¨ÁòËáºÍ50mLÒÒ´¼£¬°²×°ºÃÒÇÆ÷£¬»º»º¼ÓÈÈ£¬ÊÕ¼¯Áó³öÎï¡£
¢Ú·ÖÀëÌá´¿£º½«Áó³öÎï¼ÓË®ºóÕñµ´£¬ÔÙ¼ÓÈëÊÊÁ¿Ëá³ýÈ¥ÒÒÃÑ£¬·ÖÒº£¬×îºóµÃµ½52mLäåÒÒÍé¡£
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÒÇÆ÷BµÄÃû³ÆÊÇ___________¡£
£¨2£©ÒÇÆ÷CΪֱÐÎÀäÄý¹Ü£¬ÀäË®½ø¿ÚÊÇ___________£¨Ìî¡°a¡±»ò¡°b¡±£©¡£
£¨3£©ÒÇÆ÷DÖÃÓÚÊ¢ÓÐ_________µÄÉÕ±­ÖУ¬Ä¿µÄÊÇ__________________________________¡£
£¨4£©×°ÖÃAµÄÃû³ÆΪţ½Ç¹Ü£¬Æä½á¹¹ÖеÄcÖ§¹ÜµÄ×÷ÓÃÊÇ___________________________¡£
£¨5£©äåÒÒÍé´Ö²úÆ··ÖÀëÌá´¿½×¶Î£¬¼ÓË®µÄÄ¿µÄÊÇ___________________________________¡£
£¨6£©¸ÃʵÑéËùµÃäåÒÒÍéµÄ²úÂÊΪ ________________________¡£
£¨1£©ÕôÁóÉÕÆ¿
£¨2£©b
£¨3£©±ùË®»ìºÏÎï    ÀäÈ´äåÒÒÍé
£¨4£©Æ½ºâ×°ÖÃD ×°ÖÃBÖеÄÆøѹ£¬±ãÓÚ×°ÖÃD½ÓÊÜÁï³öÒº
£¨5£©³ýÈ¥ÈܽâÔÚäåÒÒÍéÖеÄÒÒ´¼
£¨6£©78.9%»ò79%»ò78.89%

ÊÔÌâ·ÖÎö£º£¨1£©ÒÇÆ÷BµÄÃû³ÆÊÇÕôÁóÉÕÆ¿£»£¨2£©ÎªÁËʹÀäÄýЧ¹û¸üºÃ£¬ÒÇÆ÷CÖ±ÐÎÀäÄý¹Ü£¬ÀäË®½ø¿ÚÊÇb.ÈÈË®³ö¿ÚΪa¡££¨3£©äåÒÒÍéµÄ·ÐµãΪ38.4¡ã£¬ÎªÁËÊÕ¼¯²úÆ·£¬Òª°ÑÒÇÆ÷DÖÃÓÚÊ¢ÓбùË®»ìºÏÎïµÄÉÕ±­ÖУ¬ÒÔÀäÈ´äåÒÒÍé¡££¨4£©×°ÖÃAµÄÃû³ÆΪţ½Ç¹Ü£¬Æä½á¹¹ÖеÄcÖ§¹ÜµÄ×÷ÓÃÊÇƽºâ×°ÖÃD¡¢×°ÖÃBÖеÄÆøѹ£¬±ãÓÚ×°ÖÃD½ÓÊÜÁï³öÒº¡££¨5£©ÓÉÓÚÒÒ´¼µÄ·ÐµãÖ»ÓÐ78.4¡ã£¬ÔÚ¼ÓÈÈʱÈÝÒ×·¢Éú·´Ó¦¶øËæ×ÅäåÒÒÍéÕô³ö¡£ÒÒ´¼ÓëË®»ìÈÜ£¬¶øäåÒÒÍé²»ÄÜÈܽâÓÚË®£¬ËùÒÔÔÚäåÒÒÍé´Ö²úÆ··ÖÀëÌá´¿½×¶Î£¬¼ÓË®¾Í¿ÉÒÔ³ýÈ¥ÈܽâÔÚäåÒÒÍéÖеÄÒÒ´¼£¬±ãÓÚ»ìºÏÎïµÄ·ÖÀë¡££¨6£©n(ÒÒ´¼)="(" 50mL¡Á0.79g/ml)¡Â46g/mol=0.8587mol;n(äåÒÒÍé)= (52mL¡Á1.42g/ml)¡Â109g/mol=0.6774mol.ËùÒÔ¸ÃʵÑéËùµÃäåÒÒÍéµÄ²úÂÊΪ(0.6774¡Â0.8587)¡Á100%=78.9%.
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
Õý¶¡Ãѳ£ÓÃ×÷Óлú·´Ó¦µÄÈܼÁ¡£ÊµÑéÊÒÖƱ¸Õý¶¡Ãѵķ´Ó¦ºÍÖ÷ҪʵÑé×°ÖÃÈçÏ£º
2CH3CH2CH2CH2OH (CH3CH2CH2CH2)2O+H2O
·´Ó¦ÎïºÍ²úÎïµÄÏà¹ØÊý¾ÝÈçÏÂ
 
Ïà¶Ô·Ö×ÓÖÊÁ¿
·Ðµã/¡æ
ÃܶÈ/£¨g/cm3£©
Ë®ÖÐÈܽâÐÔ
Õý¶¡´¼
74
117£®2
0£®8109
΢ÈÜ
Õý¶¡ÃÑ
130
142£®0
0£®7704
¼¸ºõ²»ÈÜ
ºÏ³É·´Ó¦£º
¢Ù½«6 mLŨÁòËáºÍ37 gÕý¶¡´¼£¬°´Ò»¶¨Ë³ÐòÌí¼Óµ½AÖУ¬²¢¼Ó¼¸Á£·Ðʯ¡£
¢Ú¼ÓÈÈAÖз´Ó¦Òº£¬Ñ¸ËÙÉýÎÂÖÁ135¡æ£¬Î¬³Ö·´Ó¦Ò»¶Îʱ¼ä¡£·ÖÀëÌá´¿£º
¢Û´ýAÖÐÒºÌåÀäÈ´ºó½«Æ仺Âýµ¹ÈËÊ¢ÓÐ70 mLË®µÄ·ÖÒºÚÒ¶·ÖУ¬ÕñÒ¡ºó¾²Ö㬷ÖÒºµÃ´Ö²úÎï¡£
¢Ü´Ö²úÎïÒÀ´ÎÓÃ40 mLË®¡¢20 mL NaOHÈÜÒººÍ40 mLˮϴµÓ£¬·ÖÒººó¼ÓÈëÔ¼3 gÎÞË®ÂÈ»¯¸Æ¿ÅÁ££¬¾²ÖÃÒ»¶Îʱ¼äºóÆúÈ¥ÂÈ»¯¸Æ¡£
¢Ý½«ÉÏÊö´¦Àí¹ýµÄ´Ö²úÎï½øÐÐÕôÁó£¬ÊÕ¼¯Áó·Ö£¬µÃ´¿¾»Õý¶¡ÃÑ11 g¡£

Çë»Ø´ð£º
£¨1£©²½Öè¢ÙÖÐŨÁòËáºÍÕý¶¡´¼µÄÌí¼Ó˳ÐòΪ                       ¡£
£¨2£©¼ÓÈÈAÇ°£¬ÐèÏÈ´Ó____£¨Ìî¡°a¡±»ò¡°b¡±£©¿ÚÏòBÖÐͨÈëË®¡£
£¨3£©²½Öè¢ÛµÄÄ¿µÄÊdzõ²½Ï´È¥           £¬ÕñÒ¡ºó¾²Ö㬴ֲúÎïÓ¦´Ó·ÖҺ©¶·µÄ       £¨Ìî¡°ÉÏ¡±»ò¡°Ï¡±£©¿Ú·ÖÀë³ö¡£
£¨4£©²½Öè¢ÛÖÐ×îºóÒ»´ÎˮϴµÄÄ¿µÄΪ                    ¡£
£¨5£©²½Öè¢ÝÖУ¬¼ÓÈÈÕôÁóʱӦÊÕ¼¯       £¨ÌîÑ¡Ïî×Öĸ£©×óÓÒµÄÁó·Ö¡£
A£®100¡æ     B£®117¡æ     C£®135¡æ      D£®142¡æ
£¨6£©·´Ó¦¹ý³ÌÖлá¹Û²ìµ½·ÖË®Æ÷ÖÐÊÕ¼¯µ½ÒºÌåÎïÖÊ£¬ÇÒ·ÖΪÉÏÏÂÁ½²ã£¬Ëæ×Å·´Ó¦µÄ½øÐУ¬·ÖË®Æ÷ÖÐÒºÌåÖð½¥Ôö¶àÖÁ³äÂúʱ£¬ÉϲãÒºÌå»á´Ó×ó²àÖ§¹Ü×Ô¶¯Á÷»ØA¡£·ÖË®Æ÷ÖÐÉϲãÒºÌåµÄÖ÷Òª³É·ÖΪ____£¬Ï²ãÒºÌåµÄÖ÷Òª³É·ÖΪ            ¡£
£¨7£©±¾ÊµÑéÖУ¬Õý¶¡ÃѵIJúÂÊΪ           ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø