ÌâÄ¿ÄÚÈÝ

¼ò´ðÏÂÃæÓйرê×¼ÇâÑõ»¯ÄÆÈÜÒºµÎ¶¨´ý²âÑÎËáµÄÎÊÌâ¡£
£¨1£©Ê¢·Å´ý²âÑÎËáµÄ׶ÐÎÆ¿Ï·½µæÒ»ÕÅ°×Ö½µÄ×÷ÓÃ
________________________________________.
£¨2£©Ó÷Ó̪×÷ָʾ¼Á£¬µÎ¶¨µ½´ïÖÕµãʱ£¬ÈÜÒºÑÕÉ«±ä»¯ÊÇ
___________________________________.
£¨3£©ÓÐÏÂÁдíÎó²Ù×÷£º
¢Ù¼îʽµÎ¶¨¹ÜÓÃÕôÁóˮϴ¾»ºó£¬Î´¾­±ê×¼ÒºÈóÏ´¾Í×¢Èë±ê×¼ÇâÑõ»¯ÄÆÈÜÒº£»
¢ÚÓÃËáʽµÎ¶¨¹ÜÈ¡Óôý²âËáҺǰ£¬¼â×첿·ÖÓÐÆøÅÝ£¬È¡Óùý³ÌÖÐÆøÅÝÏûʧ£»
¢ÛµÎ¶¨Ç°£¬¶Á¼îÒºÌå»ýʱÊÓÏßµÍÓÚ¼îʽµÎ¶¨¹ÜÖеÄÒºÃ棬µÎ¶¨ºó¶Á³ö¼îÒºÌå»ýʱ£¬ÊÓÏ߸ßÓÚ¼îʽµÎ¶¨¹ÜÖеÄÒºÃ棻
¢Ü׶ÐÎÆ¿Óôý²âËáÒºÈóÏ´Á½´Î¡£
ÄÄЩ´íÎó²Ù×÷»áʹÑÎËáŨ¶ÈµÄ²â¶¨ÖµÆ«µÍ£¿´ð£º__________________;
ÄÄЩ´íÎó²Ù×÷»áʹÑÎËáŨ¶ÈµÄ²â¶¨ÖµÆ«¸ß£¿´ð£º___________________.
£¨4£©Èç¹ûÓü׻ù³È´úÌæ·Ó̪×÷ָʾ¼Á£¬´ËʱËùµÃÑÎËáŨ¶ÈµÄ²â¶¨Öµ±ÈÓ÷Ó̪×÷ָʾ¼Á²â³öµÄÉÔ´ó»¹ÊÇÉÔС£¿´ð£º
_________________________________________________________¡£
£¨1£©±ãÓÚ¹Û²ìÑÕÉ«±ä»¯£¬¼õÉٵζ¨Îó²î
£¨2£©ÓÉÎÞÉ«±äΪ·ÛºìÉ«£¬²¢ÔÚ°ë·ÖÖÓÄÚ²»ÍÊÈ¥
£¨3£©Æ«µÍµÄ£º¢Ú¢Û£»Æ«¸ßµÄ£º¢Ù¢Ü
£¨4£©ÉÔС¡£
Îó²î·ÖÎöÒÀ¾Ý£ºc(HCl)=[c(NaOH)¡¤V(NaOH)]/V(HCl)£¬¸ù¾ÝV(NaOH)µÄ´óСÅжÏc(HCl)ÊÇÆ«¸ß»¹ÊÇÆ«µÍ¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø