ÌâÄ¿ÄÚÈÝ

ÈçͼËùʾ£º

ÒÑÖª£º

¢Ù¼×¡¢ÒÒ¡¢±û¡¢¶¡¾ùΪǰÈýÖÜÆÚÔªËصĵ¥ÖÊ¡£?

¢ÚÔÚÒ»¶¨Ìõ¼þϼ×Óë±ûºÍ¼×Ó붡¶¼°´ÎïÖʵÄÁ¿Ö®±È1¡Ã3·´Ó¦£¬·Ö±ðÉú³ÉXºÍY£¬ÔÚ²úÎïÖÐÔªËؼ׳ʸº¼Û¡£?

¢ÛÔÚÒ»¶¨Ìõ¼þÏÂÒÒÓë±ûºÍÒÒÓ붡¶¼°´ÎïÖʵÄÁ¿Ö®±È1¡Ã2·´Ó¦£¬·Ö±ðÉú³ÉZºÍW£¬ÔÚ²úÎïÖÐÔªËØÒҳʸº¼Û¡£?

ÇëÌî¿Õ£º?

£¨1£©¼×ÊÇ                £¬ÒÒÊÇ                ¡£

£¨2£©¼×Óë±û·´Ó¦Éú³ÉXµÄ»¯Ñ§·½³ÌʽÊÇ                             ¡£

£¨3£©ÒÒÓ붡·´Ó¦Éú³ÉWµÄ»¯Ñ§·½³ÌʽÊÇ                    ¡£

 

£¨1£©N2  O2?

  £¨2£©N2+3MgMg3N2?

  £¨3£©O2+2H22H2O?

»ò´ð£º£¨2£©N2+3H22NH3?

    £¨3£©O2+2Mg===2MgO?

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø