ÌâÄ¿ÄÚÈÝ

£¨2009?ÄÏ»ãÇøÄ£Ä⣩ÏÂÁÐʵÑé²Ù×÷ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
¢ÙÓôøÏðƤÈûµÄ×ØÉ«ÊÔ¼ÁÆ¿´æ·ÅŨÁòË᣻¢Ú½«0.1mol/LµÄNaOHÈÜÒºÓë0.5mol/LµÄCuSO4ÈÜÒºµÈÌå»ý»ìºÏÖƵÃÇâÑõ»¯Í­×ÇÒº£¬ÓÃÓÚ¼ìÑéÈ©»ù£»¢ÛʵÑéÊÒÖÆÏõ»ù±½Òª°ÑζȼƲåÔÚÉÕ±­ÈÈË®µÄÖв¿£»¢Ü¿ÉÓÃFeCl3ÈÜÒº³ýÈ¥ÊÔ¹ÜÄÚÄÑÒÔˢȥµÄÍ­¼££»¢ÝÓû²âijÈÜÒºµÄpH£¬ÐèÏÈÓÃÕôÁóË®ÈóʪpHÊÔÖ½£¬ÔÙÓýྻ¡¢¸ÉÔïµÄ²£Á§°ôպȡ¸ÃÈÜÒºµÎÔÚÊÔÖ½ÉÏ£¬²¢Óë±ê×¼±ÈÉ«¿¨±È½Ï£»¢Þ·ÖҺʱ£¬·ÖҺ©¶·ÖÐϲãÒºÌå´ÓÏ¿ڷųö£¬ÉϲãÒºÌå´ÓÉÏ¿Úµ¹³ö£»¢ßÕôÁóʱ£¬Ó¦Ê¹Î¶ȼÆË®ÒøÇòÉÏÔµÓëÕôÁóÉÕÆ¿Ö§¹Ü¿ÚÏÂÔµÏàƽ£®
·ÖÎö£º¢ÙŨÁòËáÓÐÇ¿Ñõ»¯ÐÔ£»
¢Ú¼ìÑéÈ©»ùʱӦÔÚ¼îÐÔÌõ¼þϽøÐУ»
¢ÛʵÑéÊÒÖÆÏõ»ù±½Î¶ȼƲâÁ¿µÄÊÇÉÕ±­ÖÐË®µÄζȣ»
¢ÜÂÈ»¯Ìú¿ÉÒÔºÍÍ­·´Ó¦£»
¢ÝpHÊÔÖ½²»ÄÜʪÈó£»
¢ÞϲãÒºÌå´ÓÏ¿ڷųö£¬ÉϲãÒºÌå´ÓÉÏ¿Úµ¹³ö£»
¢ßÕôÁóʱ£¬Î¶ȼƲâÁ¿µÄÊÇÕôÆøµÄζȣ®
½â´ð£º½â£º¢ÙÏ𽺷Ö×ÓÖдæÔÚË«¼ü£¬Ò×±»Å¨ÁòËáÑõ»¯£¬Ñõ»¯ºóÏ𽺺ÜÓ²£¬²»ÄÜʹÓã»Ã»Óмû¹âÒ×·Ö½âµÄÐÔÖÊ£¬¹Ê²»ÓÃ×ØÉ«ÊÔ¼ÁÆ¿£¬¹Ê¢Ù´íÎó£»
¢Ú¼ìÑéÈ©»ùʱӦÔÚ¼îÐÔÌõ¼þϽøÐУ¬¹ÊӦʹÇâÑõ»¯ÄÆÉÔ¹ýÁ¿£¬¹Ê¢Ú´íÎó£»
¢ÛʵÑéÊÒÖÆÏõ»ù±½Î¶ȼƲâÁ¿µÄÊÇÉÕ±­ÖÐË®µÄζȣ¬¹Ê¢ÛÕýÈ·£»
¢ÜÍ­ÓëFeCl3ÈÜÒº·¢Éú·´Ó¦£¬Ê¹Í­×ª»¯³É¿ÉÈÜÐÔµÄÍ­ÑΣ¬¹Ê¢ÜÕýÈ·£»
¢ÝÓÃpHÊÔÖ½²âijÈÜÒºµÄpH£¬pHÊÔÖ½²»ÄÜʪÈ󣬹ʢݴíÎó£»
¢Þ·ÖҺʱ£¬·ÖҺ©¶·ÖÐϲãÒºÌå´ÓÏ¿ڷųö£¬ÉϲãÒºÌå´ÓÉÏ¿Úµ¹³ö£¬¹Ê¢ÞÕýÈ·£»
¢ßÕôÁóʱ£¬Î¶ȼƲâÁ¿µÄÊÇÕôÆøµÄζȣ¬Ó¦Ê¹Î¶ȼÆË®ÒøÇòÉÏÔµÓëÕôÁóÉÕÆ¿Ö§¹Ü¿ÚÏÂÔµÏàƽ£¬¹Ê¢ßÕýÈ·£®
¹ÊÑ¡B£®
µãÆÀ£º±¾Ì⿼²é»¯Ñ§ÊµÑé»ù±¾²Ù×÷£¬ÌâÄ¿ÈÝÁ¿½Ï´ó£¬ÄѶȲ»´ó£¬Æ½Ê±×¢Òâ֪ʶµÄ»ýÀÛ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2009?ÄÏ»ãÇøÄ£Ä⣩Ñõ»¯¶þÂÈÊÇ×Ø»ÆÉ«´Ì¼¤ÐÔÆøÌ壬È۵㣺-116¡æ£¬·Ðµã3.8¡æ£®Ñõ»¯¶þÂȲ»Îȶ¨£¬½Ó´¥Ò»°ãÓлúÎïÒ×±¬Õ¨£»ËüÒ×ÈÜÓÚË®£¨1£º100£©£¬Í¬Ê±·´Ó¦Éú³É´ÎÂÈËáÈÜÒº£»ÖƱ¸³öÖ®ºóÒªÀäÈ´³É¹Ì̬ÒÔ±ã²Ù×÷ºÍÖü´æ£®ÖƱ¸ÉÙÁ¿Cl2O£¬ÊÇÓøÉÔïµÄÂÈÆøºÍHgO·´Ó¦£¨»¹Éú³ÉHgO?HgCl2£©£®×°ÖÃʾÒâÈçͼ£¨Ìú¼Ų̈ºÍ¼Ð³ÖÒÇÆ÷ÒÑÂÔÈ¥£©£®

£¨1£©AÖÐÊ¢ÓеÄÉîÉ«¹ÌÌåÊÔ¼ÁaÊÇ
¸ßÃÌËá¼Ø
¸ßÃÌËá¼Ø
£¬·ÖҺ©¶·ÖÐÊÔ¼ÁbÊÇ
ŨÑÎËá
ŨÑÎËá

£¨2£©BÖÐÊ¢ÓÐÒºÌåcÊÇ
±¥ºÍʳÑÎË®
±¥ºÍʳÑÎË®
£¬CÖеÄÒºÌådÊÇ
ŨÁòËá
ŨÁòËá

£¨3£©DÖÐËù·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ
2HgO+2Cl2=Cl2O+HgO?HgCl2
2HgO+2Cl2=Cl2O+HgO?HgCl2

£¨4£©EÖеı£ÎÂÆ¿ÖÐÊ¢ÓÐÖÂÀä¼Á£¬ËüÓ¦ÊÇ
Һ̬¿ÕÆø
Һ̬¿ÕÆø
£¨Ôڸɱù¡¢±ùË®¡¢ÒºÌ¬¿ÕÆøÖÐÑ¡Ôñ£©£¬ÔÚEµÄÄڹܵõ½µÄÑõ»¯¶þÂÈÖпÉÄܺ¬ÓÐÔÓÖÊÊÇ
ÒºÂÈ
ÒºÂÈ

£¨5£©×°ÖÃA¡¢B¡¢C¼äµÄÁ¬½Ó·½Ê½ÓëD¡¢E¼äµÄÁ¬½Ó·½Ê½ÓÐÃ÷ÏÔµÄÇø±ð£¬ÕâÇø±ðÊÇ
A¡¢B¡¢C¼äÓÃÈ齺¹ÜÁ¬½Ó£¬D¡¢E¼ä²»ÄÜÈ齺¹ÜÁ¬½Ó
A¡¢B¡¢C¼äÓÃÈ齺¹ÜÁ¬½Ó£¬D¡¢E¼ä²»ÄÜÈ齺¹ÜÁ¬½Ó
£¬ÓÃÕâЩ²»Í¬µÄÁ¬½Ó·½Ê½µÄÖ÷ÒªÀíÓÉÊÇ
Cl2OÓöÓлúÎïÒ×±¬Õ¨
Cl2OÓöÓлúÎïÒ×±¬Õ¨
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø