ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿¢ñ.ÈçͼÊÇÖÐѧ»¯Ñ§Öг£ÓÃÓÚ»ìºÏÎïµÄ·ÖÀëºÍÌá´¿µÄ×°Öã¬Çë¸ù¾Ý×°ÖûشðÎÊÌ⣺
£¨1£©´ÓÂÈ»¯¼ØÈÜÒºÖеõ½ÂÈ»¯¼Ø¹ÌÌ壬ѡÔñ×°ÖÃ____________(Ìî´ú±í×°ÖÃͼµÄ×Öĸ£¬ÏÂͬ)£»³ýÈ¥×ÔÀ´Ë®ÖеÄCl£µÈÔÓÖÊ£¬Ñ¡Ôñ×°ÖÃ____________¡£
£¨2£©´ÓµâË®ÖзÖÀë³öI2£¬Ñ¡Ôñ×°ÖÃ_________£¬¸Ã·ÖÀë·½·¨µÄÃû³ÆΪ___________¡£
£¨3£©×°ÖÃAÖТٵÄË®µÄ½ø³ö·½ÏòÊÇ_________£¬AÖÐËùÓв£Á§ÒÇÆ÷µÄÃû³Æ·Ö±ðÊÇ__________¡£
¢ò.¶ÔÓÚ»ìºÏÎïµÄ·ÖÀë»òÌá´¿£¬³£²ÉÓõķ½·¨ÓУºA¡¢·ÖÒº B¡¢¹ýÂË C¡¢ÝÍÈ¡ D¡¢ÕôÁó E¡¢½á¾§ F¡¢¼ÓÈȷֽ⣬ÏÂÁи÷×éÎïÖʵķÖÀë»òÌá´¿£¬Ó¦Ñ¡ÓÃÉÏÊö·½·¨µÄÄÄÒ»ÖÖ£¿£¨Ìî×ÖĸÐòºÅ£©
£¨4£©³ýÈ¥Ca(OH)2ÈÜÒºÖÐÐü¸¡µÄCaCO3__________£»
£¨5£©·ÖÀëÖ²ÎïÓͺÍË®__________£»
£¨6£©³ýÈ¥NaClÖÐËùº¬µÄÉÙÁ¿KNO3___________£»
£¨7£©³ýÈ¥CaOÖÐÉÙÁ¿CaCO3__________£»
£¨8£©ÓÃʳÓþƾ«½þÅÝÖвÝÒ©ÌáÈ¡ÆäÖеÄÓÐЧ³É·Ý_________£»
£¨9£©»ØÊÕµâµÄCCl4ÈÜÒºÖеÄCCl4__________¡£
¡¾´ð°¸¡¿DABÝÍȡϽøÉϳö¾Æ¾«µÆ¡¢ÕôÁóÉÕÆ¿¡¢Î¶ȼơ¢ÀäÄý¹Ü¡¢Å£½Ç¹Ü¡¢×¶ÐÎÆ¿BAEFCD
¡¾½âÎö¡¿
¸ù¾Ý×°ÖÃͼ¿ÉÖªAÊÇÕôÁó×°Öã¬BÊÇ·ÖҺװÖã¬CÊǹýÂË×°Öã¬DÊÇÕô·¢×°Ö㬽áºÏÎïÖʵÄÐÔÖÊ·ÖÎö½â´ð¡£
£¨1£©Õô·¢Äܽ«Ò×ÈÜÓÚË®µÄ¹ÌÌåºÍË®µÄ·ÖÀ룬´ÓÂÈ»¯¼ØÈÜÒºÖеõ½ÂÈ»¯¼Ø¹ÌÌå¿ÉÓÃÕô·¢£¬´ð°¸Ñ¡D£»ÒòÕôÁó¿ÉÒÔʵÏÖË®ÖÐÄѻӷ¢ÐÔÔÓÖʺÍË®µÄ·ÖÀ룬Ôò³ýÈ¥×ÔÀ´Ë®ÖеÄCl©¤µÈÔÓÖÊ£¬¿ÉÓÃÕôÁ󣬴ð°¸Ñ¡A£»
£¨2£©µâ΢ÈÜÓÚË®£¬µâÒ×ÈÜÓÚ±½¡¢ËÄÂÈ»¯Ì¼µÈÓлúÈܼÁ£¬ÇÒ±½¡¢ËÄÂÈ»¯Ì¼ÓëË®»¥²»ÏàÈÜ£¬¿ÉÓÃÝÍÈ¡·¨·ÖÀ룬´ð°¸Ñ¡B£»
£¨3£©×°ÖÃAÖТٵÄÃû³ÆÊÇÖ±ÐÎÀäÄý¹Ü£¬Ê¹ÓÃʱÏ¿ڽøË®ÉÏ¿Ú³öË®¡£¸ù¾Ý×°Öù¹Ôì¿ÉÖªAÖв£Á§ÒÇÆ÷µÄÃû³Æ·Ö±ðÊǾƾ«µÆ¡¢ÕôÁóÉÕÆ¿¡¢Î¶ȼơ¢ÀäÄý¹Ü¡¢Å£½Ç¹Ü¡¢×¶ÐÎÆ¿£»
£¨4£©Ì¼Ëá¸Æ²»ÈÜÓÚË®£¬ÔòÑ¡Ôñ¹ýÂË·¨·ÖÀ룬´ð°¸ÎªB£»
£¨5£©Ö²ÎïÓÍÓëË®·Ö²ã£¬ÔòÑ¡Ôñ·ÖÒº·¨·ÖÀ룬´ð°¸ÎªA£»
£¨6£©¶þÕßÈܽâ¶ÈÊÜζÈÓ°Ï첻ͬ£¬ÔòÑ¡Ôñ½á¾§·¨·ÖÀ룬´ð°¸ÎªE£»
£¨7£©Ì¼Ëá¸Æ¸ßηֽâÉú³ÉCaO£¬ÔòÑ¡Ôñ¸ßηֽⷨ·ÖÀ룬´ð°¸ÎªF£»
£¨8£©ÓÐЧ³É·ÖΪÓлúÎÒ×ÈÜÓھƾ«£¬Ôò¸Ã·ÖÀë·½·¨ÎªÝÍÈ¡£¬´ð°¸ÎªC£»
£¨9£©¶þÕß»¥ÈÜ£¬µ«·Ðµã²»Í¬£¬ÔòÑ¡ÔñÕôÁó·¨·ÖÀë³öËÄÂÈ»¯Ì¼£¬´ð°¸ÎªD¡£
¡¾ÌâÄ¿¡¿Áò´úÁòËáÄƾ§Ìå(Na2S2O3¡¤5H2O)Óֳƺ£²¨£¬³ÊÎÞɫ͸Ã÷×´£¬Ò×ÈÜÓÚË®£¬²»ÈÜÓÚÒÒ´¼£¬³£ÓÃ×÷ÃÞÖ¯ÎïƯ°×ºóµÄÍÑÂȼÁ¡¢¶¨Á¿·ÖÎöÖеĻ¹Ô¼Á¡£
¢ñ. Na2S2O3¡¤5H2OµÄÖƱ¸
Na2S2O3¡¤5H2OµÄÖƱ¸·½·¨ÓжàÖÖ£¬ÆäÖÐÑÇÁòËáÄÆ·¨Êǹ¤ÒµºÍʵÑéÊÒÖеÄÖ÷Òª·½·¨£º
Na2SO3+S+5H2ONa2S2O3¡¤5H2O
ÖƱ¸¹ý³ÌÈçÏ£º
¢Ù³ÆÈ¡12.6gNa2SO3ÓÚ100mLÉÕ±ÖУ¬¼Ó50mLÈ¥Àë×ÓË®½Á°èÈܽ⡣
¢ÚÁíÈ¡4.0gÁò·ÛÓÚ200mLÉÕ±ÖУ¬¼Ó6mLÒÒ´¼³ä·Ö½Á°è¾ùÔȽ«ÆäÈóʪ£¬ÔÙ¼ÓÈëNa2SO3ÈÜÒº£¬¸ôʯÃÞÍøС»ð¼ÓÈÈÖó·Ð£¬²»¶Ï½Á°èÖÁÁò·Û¼¸ºõÈ«²¿·´Ó¦¡£
¢ÛÍ£Ö¹¼ÓÈÈ£¬´ýÈÜÒºÉÔÀäÈ´ºó¼Ó2g»îÐÔÌ¿£¬¼ÓÈÈÖó·Ð2·ÖÖÓ(ÍÑÉ«)¡£
¢Ü³ÃÈȹýÂË£¬µÃÂËÒºÖÁÕô·¢ÃóÖУ¬_________________¡¢____________________¡£
¢Ý¹ýÂË¡¢Ï´µÓ£¬ÓÃÂËÖ½Îü¸Éºó£¬³ÆÖØ£¬¼ÆËã²úÂÊ¡£
£¨1£©¼ÓÈëµÄÁò·ÛÓÃÒÒ´¼ÈóʪµÄÄ¿µÄÊÇ____________________________¡£
£¨2£©²½Öè¢Ü³ÃÈȹýÂ˵ÄÔÒò_____________________£¬¿Õ¸ñ´¦Ó¦²ÉÈ¡µÄ²Ù×÷ÊÇ_________________¡¢____________________¡£
£¨3£©²½Öè¢ÝÏ´µÓ¹ý³ÌÖУ¬Îª·ÀÖ¹Óв¿·Ö²úÆ·Ëðʧ£¬Ó¦Ñ¡ÓõÄÊÔ¼ÁΪ__________________________¡£
£¨4£©ÂËÒºÖгýNa2S2O3 ºÍδ·´Ó¦ÍêÈ«µÄNa2SO3Í⣬×î¿ÉÄÜ´æÔÚµÄÎÞ»úÔÓÖÊÊÇ________________£¬Éú³É¸ÃÔÓÖʵÄÔÒò¿ÉÄÜÊÇ____________________________¡£
¢ò.²úÆ·´¿¶ÈµÄ²â¶¨
׼ȷ³ÆÈ¡1.00g²úÆ·(Áò´úÁòËáÄƾ§ÌåµÄĦ¶ûÖÊÁ¿Îª248g/mol)£¬ÓÃÊÊÁ¿ÕôÁóË®Èܽ⣬ÒÔµí·Û×÷ָʾ¼Á£¬ÓÃ0.1000mol/LI2µÄ±ê×¼ÈÜÒºµÎ¶¨£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º2S2O32-+I2=S4O62-+2I-£¬¼Ç¼Êý¾ÝÈçÏ£º
µÎ¶¨´ÎÊý | µÎ¶¨Ç°¶ÁÊý(mL) | µÎ¶¨ºó¶ÁÊý(mL) |
1 | 0.30 | 21.32 |
2 | 0.36 | 22.56 |
3 | 0.10 | 21.08 |
£¨5£©¼ÆËãËùµÃ²úÆ·µÄ´¿¶ÈΪ___________(±£ÁôÈýλÓÐЧÊý×Ö)£¬¸ÃÊý¾ÝµÄºÏÀí½âÊÍ¿ÉÄÜÊÇ__________(²»¿¼ÂÇʵÑé²Ù×÷ÒýÆðµÄÎó²î)¡£
¢ó.²úÆ·µÄÓ¦ÓÃ
£¨6£©Na2S2O3 ³£ÓÃÓÚÍÑÂȼÁ£¬ÔÚÈÜÒºÖÐÒ×±»Cl2 Ñõ»¯ÎªSO42-£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ _____________________________¡£