ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÊµÑéÊÒÐèÒª0.2 mol/L NaOHÈÜÒº450 mLºÍ0.5 mol/LÁòËáÈÜÒº500 mL¡£¸ù¾ÝÕâÁ½ÖÖÈÜÒºµÄÅäÖÆÇé¿ö»Ø´ðÏÂÁÐÎÊÌ⣺
(l)ÈçͼËùʾµÄÒÇÆ÷ÖÐÅäÖÆÈÜÒºÒ»¶¨²»ÐèÒªµÄÊÇ ___£¨Ìî×ÖĸÐòºÅ£©£¬ÅäÖÆÉÏÊöÈÜÒº»¹ÐèÓõ½µÄ²£Á§ÒÇÆ÷ÊÇ____ÌîÒÇÆ÷Ãû³Æ£©¡£
(2)ÔÚÅäÖÆNaOHÈÜҺʱ£º
¢Ù¸ù¾Ý¼ÆË㣬ÓÃÍÐÅÌÌìƽ³ÆÈ¡NaOH¹ÌÌå____g£»
¢ÚÈôNaOHÈÜÒºÔÚתÒÆÖÁÈÝÁ¿Æ¿Ê±£¬È÷ÂäÁËÉÙÐí£¬ÔòÅäÖõÄÈÜҺŨ¶È_____Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£©¡£
(3)ÔÚÅäÖÆÁòËáÈÜҺʱ£º
¢ÙËùÐèÖÊÁ¿·ÖÊýΪ98%¡¢ÃܶÈΪ1.84 g/cm3µÄŨÁòËáµÄÌå»ýΪ____mL£¨¼ÆËã½á¹û±£ÁôһλСÊý£©£»
¢ÚÈç¹ûʵÑéÊÒÓÐ15 mL¡¢20 mL¡¢50 mLÁ¿Í²£¬Ó¦Ñ¡Óà ___mLÁ¿Í²×îºÃ¡£
¡¾´ð°¸¡¿AC ÉÕ±¡¢²£Á§°ô 4.0 Æ«µÍ 13.6 15
¡¾½âÎö¡¿
¸ù¾ÝÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈÈÜÒºµÄÅäÖƹý³Ì·ÖÎöËùÐèÒªµÄʵÑéÒÇÆ÷£¬¸ù¾ÝÎïÖʵÄÁ¿Å¨¶ÈµÄ¼ÆË㹫ʽ½øÐвÙ×÷¹ý³ÌÖеÄʵÑéÎó²î·ÖÎö¡£
AΪƽµ×ÉÕÆ¿¡¢CΪ·ÖҺ©¶·£¬ÔÚÅäÖÆÈÜÒº¹ý³ÌÖв»»áʹÓõ½ÉÕÆ¿ºÍ·ÖҺ©¶·£»ÅäÖÆÒ»¶¨Å¨¶ÈµÄÈÜÒº»¹È±ÉÙ²£Á§°ôºÍ½ºÍ·µÎ¹Ü£¬¹Ê´ð°¸Îª£ºAC£¬ÉÕ±¡¢²£Á§°ô £»
ÅäÖÆ0.2 mol/L NaOHÈÜÒº450 mL£¬ÐèÒª500mLÈÝÁ¿Æ¿£¬¹Ê¼ÆËãÐèÒªÓÃ500mL£¬¼´m(NaOH)=0.20.5L
g/mol=4.0g£¬¸ù¾Ý¼ÆË㣬ÓÃÍÐÅÌÌìƽ³ÆÈ¡NaOH¹ÌÌå4.0g£»ÈôNaOHÈÜÒºÔÚתÒÆÖÁÈÝÁ¿Æ¿Ê±£¬È÷ÂäÁËÉÙÐí£¬¼´ÈÜÖʵÄÎïÖʵÄÁ¿¼õÉÙ£¬ÅäÖõÄÈÜҺŨ¶ÈÆ«µÍ£¬¹Ê´ð°¸Îª£º4.0£¬Æ«µÍ£»
ÖÊÁ¿·ÖÊýΪ98%¡¢ÃܶÈΪ1.84g/cm3µÄŨÁòËáµÄŨ¶ÈΪ£º=18.4mol/L£¬
ÅäÖÆ500£¬mL 0.5mol/LµÄÁòËᣬÐèҪŨÁòËáµÄÌå»ýΪ£º0.5mol/L¡Á0.5L=18.4mol/LV£¬V¡Ö0.0136L=13.6mL£¬¸ù¾Ý¡°´ó¶ø½ü¡±µÄÔÔòÑ¡ÓÃ15mLÁ¿Í²£¬¹Ê´ð°¸Îª£º13.6mL£¬15mL¡£
![](http://thumb2018.1010pic.com/images/loading.gif)
¡¾ÌâÄ¿¡¿½«Å£Ä̺ͽªÖ»ìºÏ£¬´ýÅ£ÄÌÄý¹Ì±ã³ÉΪһÖÖ¸»Óй㶫ÌØÉ«µÄÌðÆ·¡ª¡ª½ª×²ÄÌ¡£ÎªÁËÕÆÎÕÅ£ÄÌÄý¹ÌËùÐèµÄÌõ¼þ£¬Ä³Í¬Ñ§ÔÚ²»Í¬Î¶ȵĵÈÁ¿Å£ÄÌÖлìÈËһЩÐÂÏʽªÖ£¬¹Û²ì»ìºÏÎï15min£¬¿´ÆäÊÇ·ñ»áÄý¹Ì£¬½á¹ûÈçÏÂ±í¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
ζȣ¨¡æ£© | 20 | 40 | 60 | 80 | 100 |
½á¹û | 15minºóÈÔδÓÐÄý¹Ì¼£Ïó | 14minÄÚÍêÈ«Äý¹Ì | 1minÄÚÍêÈ«Äý¹Ì | 1minÄÚÍêÈ«Äý¹Ì | 15minºóÈÔδÓÐÄý¹Ì¼£Ïó |
£¨×¢£ºÓÃÔøÖó·ÐµÄ½ªÖÖظ´ÕâÏîʵÑ飬ţÄÌÔÚÈκÎζÈϾù²»ÄÜÄý¹Ì£©
£¨1£©ÊµÑéÖ¤Ã÷ÐÂÏʽªÖÖк¬ÓÐÒ»ÖÖø£¬Æä×÷ÓÃÊÇ ¡£
£¨2£©20¡æºÍ100¡æʱ£¬15minºóÈÔδÓÐÄý¹Ì¼£Ïó£¬ËµÃ÷øµÄ»îÐԽϵͣ¬ÆäÔÒò·Ö±ðÊÇ ºÍ ¡£
£¨3£©Èô60¡æʱţÄÌÔÚÓнªÖºÍûÓнªÖµÄÇé¿ö϶¼¿ÉÒÔÄý¹Ì£¬µ±·´Ó¦½øÐе½tʱ£¬ÏòÆäÖмÓÈ˽ªÖ¡£ÏÂͼÖÐÄÜÕýÈ·±íʾ¼Ó½ªÖºóÅ£ÄÌÄý¹ÌËæʱ¼ä±ä»¯Ç÷ÊƵÄÇúÏßÊÇ ¡£
£¨4£©ÎªÌá¸ßʵÑéµÄ׼ȷ¶È£¬ÊµÑéÖС°²»Í¬Î¶ȵĵÈÁ¿Å£ÄÌÖлìÈëһЩÐÂÏʽªÖ¡±²Ù×÷ÖÐӦעÒâµÄÊÇ ¡£
£¨5£©ÓÐͬѧ˵£¬¸ÃʵÑé²»Äܵóö½ªÖʹţÄÌÄý¹ÌµÄ×îÊÊζȣ¬ÇëÌá³ö½â¾ö·½°¸: ¡£
¡¾ÌâÄ¿¡¿H2Y2-ÊÇÒÒ¶þ°·ËÄÒÒËá¸ù()µÄ¼òд£¬¿ÉÓë¶àÖÖ½ðÊôÀë×ÓÐγÉÂçºÏÎï¡£
I. H2Y2-ÓëFe2+ÐγɵÄÂçºÏÎïFeY2-¿ÉÓÃÓÚÎüÊÕÑÌÆøÖеÄNO¡£ÆäÎüÊÕÔÀí:
FeY2-(aq)+NO(g)FeY2-(NO)(aq) ¡÷H<0
£¨1£©½«º¬NOµÄÑÌÆøÒÔÒ»¶¨µÄÁ÷ËÙͨÈëÆðʼζÈΪ50¡æµÄFeY2-ÈÜÒºÖС£NOÎüÊÕÂÊËæͨÈëÑÌÆøµÄʱ¼ä±ä»¯ÈçÓÒͼ¡£Ê±¼äÔ½³¤£¬NOÎüÊÕÂÊÔ½µÍµÄÔÒòÊÇ_________¡£
£¨2£©Éú³ÉµÄFeY2-(NO)(aq)¿Éͨ¹ý¼ÓÈëÌú·Û»¹ÔÔÙÉú£¬ÆäÔÀí:FeY2-(NO)(aq)+Fe+H2O¡úFeY2-(aq)+Fe(OH)2+NH3(δÅäƽ)¡£
ÈôÎüÊÕÒºÔÙÉúÏûºÄ14gÌú·Û£¬ÔòËùÎüÊÕµÄÑÌÆøÖк¬ÓÐNOµÄÎïÖʵÄÁ¿Îª_______¡£
II.ÂçºÏÍ(CuY2-)·ÏË®µÄ´¦ÀíÒ»Ö±ÊÇ»·¾³¹¤³ÌÁìÓòµÄÑо¿Èȵ㡣
£¨1£©H2Y2-ÓëCu2+¡¢Fe3+¡¢Ca2+ÂçºÏÇé¿öÈçϱí:
ÂçºÏ·´Ó¦ | lgK(KΪƽºâ³£Êý) |
Cu2++H2Y2- | 18.8 |
Fe3++H2Y2- | 25.1 |
Ca2++H2Y2- | 10.7 |
¢Ù±íÖÐ×î²»Îȶ¨µÄ½ðÊôÂçºÏÎïÊÇ_____(Ìѧʽ)¡£Ïòº¬ÓÐÂçºÏÍ(CuY2-)·ÏË®ÖмÓÈëÒ»ÖÖ»ÆÉ«µÄÑÎÈÜÒºA¿É½âÀë³öCu2+£¬ÔòÑÎAÖÐÑôÀë×ÓΪ________(Ìѧʽ)¡£
¢Úµ÷½ÚpH¿É½«½âÀë³öµÄCu2+ת»¯ÎªCu(OH)2³Áµí£¬ÈôҪʹc(Cu2+)¡Ü2.2¡Á10-4mol/L£¬pHÓ¦²»µÍÓÚ________(³£ÎÂÏÂKsp[Cu(OH)2]= 2.2¡Á10-20)¡£
£¨2£©ôÇ»ù×ÔÓÉ»ù(-OH)¡¢Na2FeO2¶¼¿ÉÑõ»¯ÂçºÏÍÖеÄY4-¶øʹCu2+µÃµ½½âÀë¡£
¢ÙËáÐÔÌõ¼þÏ£¬-OH¿É½«Y4-(C10H12O8N24-)Ñõ»¯Éú³ÉCO2¡¢H2O¡¢N2¡£¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ___________________¡£
¢ÚNa2FeO4ÔÚËáÐÔÌõ¼þϲ»Îȶ¨¡£ÓÃNa2FeO4´¦ÀíºóµÄ·ÏË®ÖÐCu2+µÄŨ¶ÈÓëpHµÄ¹ØϵÈçÓÒͼ¡£pHÔ½´ó£¬/span>·ÏË®´¦ÀíЧ¹ûÔ½ºÃ£¬ÕâÊÇÒòΪ______________¡£