ÌâÄ¿ÄÚÈÝ
Ba2+ÊÇÒ»ÖÖÖØ½ðÊôÀë×Ó£¬ÓÐÒ»»·¾³¼à²âС×éÓûÀûÓÃNa2S2O3¡¢KI¡¢K2Cr2O7µÈÊÔ¼Á²â¶¨Ä³¹¤³§·ÏË®ÖÐBa2+µÄŨ¶È£®
(1)ÏÖÐèÅäÖÆ250 mL¡¡0.100 mol¡¤L£1µÄ±ê×¼Na2S2O3ÈÜÒº£¬ËùÐèÒªµÄ²£Á§ÒÇÆ÷³ýÁ¿Í²¡¢ÉÕ±¡¢²£Á§°ôÍ⣬»¹ÐèÒª________£®
(2)ÅäÖÆÉÏÊöÈÜÒºÐè׼ȷ³ÆÈ¡Na2S2O3¹ÌÌåµÄÖÊÁ¿Îª________g£®
(3)ÁíÈ¡·ÏË®40.00 mL£¬¿ØÖÆÊʵ±µÄËá¶È£¬¼ÓÈë×ãÁ¿µÄK2Cr2O7ÈÜÒº£¬µÃBaCrO4³Áµí£¬³Áµí¾Ï´µÓ¡¢¹ýÂ˺ó£¬ÓÃÊÊÁ¿µÄÏ¡ÑÎËáÈܽ⣬´ËʱCrO
È«²¿×ª»¯ÎªCr2O
£»ÔÙ¼ÓÈë¹ýÁ¿KIÈÜÒº½øÐз´Ó¦£¬È»ºóÔÚ·´Ó¦ÈÜÒºÖÐÔٵμÓÉÏÊöNa2S2O3ÈÜÒº£¬·´Ó¦Íêȫʱ£¬ÏûºÄNa2S2O3ÈÜÒº24.00 mL£®ÒÑÖªÓйط´Ó¦µÄÀë×Ó·½³ÌʽΪ£º
¢ÙCr2O
£«6I££«14H+
2Cr3+£«3I2£«7H2O£»
¢ÚI2£«2S2O![]()
2I££«S4O
£®
ÊÔ¼ÆËã¸Ã¹¤³§·ÏË®ÖÐBa2+µÄÎïÖʵÄÁ¿Å¨¶ÈΪ¶àÉÙ£¿
´ð°¸£º
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿