ÌâÄ¿ÄÚÈÝ
ʵÑéÊÒÐèÓÃ480mL0.2mol?L-1µÄÏ¡ÁòËᣬÏÖÓÃ18.4mol?L-1µÄŨÁòËáÀ´ÅäÖã®
£¨1£©¼ÆËãËùÐèŨÁòËáµÄÌå»ýΪ______mL£®
£¨2£©ËùÐèÒÇÆ÷³ýÁ˲£Á§°ô¡¢ÉÕ±¡¢½ºÍ·µÎ¹Ü¡¢Á¿Í²Í⣬»¹ÐèÒªÄĸöÒÇÆ÷²ÅÄÜÍê³É¸ÃʵÑ飬Çëд³ö£º______£®
£¨3£©ÊµÑéÖÐÁ½´ÎÓõ½²£Á§°ô£¬Æä×÷Ó÷ֱðÊÇ£º______¡¢______£®
£¨4£©ÏÂÁжÔÈÝÁ¿Æ¿¼°ÆäʹÓ÷½·¨µÄÃèÊöÖÐÕýÈ·µÄÊÇ______£®
A£®ÈÝÁ¿Æ¿ÉϱêÓÐÈÝ»ý¡¢Î¶ȺͿ̶ÈÏß
B£®ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»ºó£¬±ØÐëºæ¸É
C£®ÅäÖÆÈÜҺʱ£¬°ÑÁ¿ºÃµÄŨÁòËáСÐĵ¹ÈëÈÝÁ¿Æ¿ÖУ¬¼ÓÈëÕôÁóË®µ½½Ó½ü¿Ì¶ÈÏß1¡«2cm´¦£¬¸ÄÓýºÍ·µÎ¹Ü¼ÓÕôÁóË®ÖÁ¿Ì¶ÈÏß
D£®Ê¹ÓÃÇ°Òª¼ì²éÈÝÁ¿Æ¿ÊÇ·ñ©ˮ
£¨5£©ÔÚÅäÖƹý³ÌÖУ¬ÏÂÁвÙ×÷¿ÉÒýÆðËùÅäÈÜҺŨ¶ÈÆ«µÍµÄÓÐ______£®£¨ÌîÐòºÅ£©
¢ÙδϴµÓÏ¡ÊÍŨÁòËáʱÓùýµÄÉÕ±ºÍ²£Á§°ô£®
¢ÚδµÈÏ¡ÊͺóµÄÁòËáÈÜÒºÀäÈ´ÖÁÊÒξÍתÒƵ½ÈÝÁ¿Æ¿ÖУ®
¢ÛתÒÆÇ°£¬ÈÝÁ¿Æ¿Öк¬ÓÐÉÙÁ¿ÕôÁóË®£®
¢Ü¶¨ÈÝʱ£¬ÑöÊӿ̶ÈÏߣ®
£¨1£©¼ÆËãËùÐèŨÁòËáµÄÌå»ýΪ______mL£®
£¨2£©ËùÐèÒÇÆ÷³ýÁ˲£Á§°ô¡¢ÉÕ±¡¢½ºÍ·µÎ¹Ü¡¢Á¿Í²Í⣬»¹ÐèÒªÄĸöÒÇÆ÷²ÅÄÜÍê³É¸ÃʵÑ飬Çëд³ö£º______£®
£¨3£©ÊµÑéÖÐÁ½´ÎÓõ½²£Á§°ô£¬Æä×÷Ó÷ֱðÊÇ£º______¡¢______£®
£¨4£©ÏÂÁжÔÈÝÁ¿Æ¿¼°ÆäʹÓ÷½·¨µÄÃèÊöÖÐÕýÈ·µÄÊÇ______£®
A£®ÈÝÁ¿Æ¿ÉϱêÓÐÈÝ»ý¡¢Î¶ȺͿ̶ÈÏß
B£®ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»ºó£¬±ØÐëºæ¸É
C£®ÅäÖÆÈÜҺʱ£¬°ÑÁ¿ºÃµÄŨÁòËáСÐĵ¹ÈëÈÝÁ¿Æ¿ÖУ¬¼ÓÈëÕôÁóË®µ½½Ó½ü¿Ì¶ÈÏß1¡«2cm´¦£¬¸ÄÓýºÍ·µÎ¹Ü¼ÓÕôÁóË®ÖÁ¿Ì¶ÈÏß
D£®Ê¹ÓÃÇ°Òª¼ì²éÈÝÁ¿Æ¿ÊÇ·ñ©ˮ
£¨5£©ÔÚÅäÖƹý³ÌÖУ¬ÏÂÁвÙ×÷¿ÉÒýÆðËùÅäÈÜҺŨ¶ÈÆ«µÍµÄÓÐ______£®£¨ÌîÐòºÅ£©
¢ÙδϴµÓÏ¡ÊÍŨÁòËáʱÓùýµÄÉÕ±ºÍ²£Á§°ô£®
¢ÚδµÈÏ¡ÊͺóµÄÁòËáÈÜÒºÀäÈ´ÖÁÊÒξÍתÒƵ½ÈÝÁ¿Æ¿ÖУ®
¢ÛתÒÆÇ°£¬ÈÝÁ¿Æ¿Öк¬ÓÐÉÙÁ¿ÕôÁóË®£®
¢Ü¶¨ÈÝʱ£¬ÑöÊӿ̶ÈÏߣ®
£¨1£©ÓÉÓÚʵÑéÊÒûÓÐ480mlµÄÈÝÁ¿Æ¿£¬ËùÒÔÓ¦¸ÃÅäÖÆ500mlÈÜÒº£¬ÅäÖÆ500mL 0.2mol?L-1µÄÏ¡ÁòËáÐèҪŨÁòËáµÄÌå»ýΪ£º
¡Ö0.0054L=5.4mL£¬
¹Ê´ð°¸Îª£º5.4£»
£¨2£©ÅäÖÆ500mL0.2mol?L-1µÄÏ¡ÁòËᣬËùÐèÒÇÆ÷³ýÁ˲£Á§°ô¡¢ÉÕ±¡¢½ºÍ·µÎ¹Ü¡¢Á¿Í²Í⣬»¹ÐèÒª500mLÈÝÁ¿Æ¿£¬
¹Ê´ð°¸Îª£º500mLÈÝÁ¿Æ¿£»
£¨3£©ÔÚÏ¡ÊÍŨÁòËáʱ£¬ÐèҪʹÓò£Á§°ô½Á°è£¬¼ÓËÙŨÁòËáµÄÏ¡ÊÍ£»ÔÚתÒÆÈÜҺʱÐèҪͨ¹ý²£Á§°ôÒýÁ÷£¬·ÀÖ¹ÈÜÒºÁ÷µ½ÈÝÁ¿Æ¿ÍâÃ棬
¹Ê´ð°¸Îª£º½Á°è×÷Óã»ÒýÁ÷£»
£¨4£©A£®ÈÝÁ¿Æ¿µÄ¶¨Á¿ÒÇÆ÷£¬ËùÒÔ±êÓÐÈÝ»ýºÍ¿Ì¶È£¬Î¶ÈÓ°ÏìÈÜÒºµÄÌå»ý£¬ËùÒÔÈÝÁ¿Æ¿ÉÏ»¹±êÓÐʹÓõÄζȣ¬¹ÊAÕýÈ·£»
B£®ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»ºó£¬ÓÉÓÚºóÃ滹ÐèÒª¼ÓÈëÕôÁóË®¶¨ÈÝ£¬ËùÒÔ²»±Øºæ¸É£¬²»Ó°ÏìÅäÖƽá¹û£¬¹ÊB´íÎó£»
C£®ÈÝÁ¿Æ¿Öв»ÄÜÓÃÓÚÏ¡ÊÍŨÁòËᣬӦ¸ÃÔÚÉÕ±ÖÐÏ¡ÊÍ£¬ÀäÈ´ºóתÒƵÄÈÝÁ¿Æ¿ÖУ¬¹ÊC´íÎó£»
D£®ÓÉÓÚÈÝÁ¿Æ¿ÓÐÆ¿Èû£¬ÅäÖÆʱÐèÒªÒ¡ÔÈ£¬ËùÒÔʹÓÃÇ°Òª¼ì²éÈÝÁ¿Æ¿ÊÇ·ñ©ˮ£¬¹ÊDÕýÈ·£»
¹ÊÑ¡AD£»
£¨5£©¢ÙδϴµÓÏ¡ÊÍŨÁòËáʱÓùýµÄÉÕ±ºÍ²£Á§°ô£¬ÔòÈÝÁ¿Æ¿ÖÐÈÜÖʵÄÎïÖʵÄÁ¿¼õС£¬¸ù¾ÝcB=
¿ÉµÃ£¬ÅäÖƵÄÈÜÒºµÄŨ¶ÈÆ«µÍ£¬¹Ê¢ÙÕýÈ·£»
¢ÚδµÈÏ¡ÊͺóµÄÁòËáÈÜÒºÀäÈ´ÖÁÊÒξÍתÒƵ½ÈÝÁ¿Æ¿ÖУ¬ÀäÈ´ºóÈÜÒºµÄÌå»ý±äС£¬¸ù¾ÝcB=
¿ÉµÃ£¬ÅäÖƵÄÈÜÒºµÄŨ¶ÈÆ«¸ß£¬¹Ê¢Ú´íÎó£»
¢ÛתÒÆÇ°£¬ÈÝÁ¿Æ¿Öк¬ÓÐÉÙÁ¿ÕôÁóË®£¬ÓÉÓÚºóÃ滹ÐèÒª¼ÓÈëÕôÁóË®¶¨ÈÝ£¬¸ù¾ÝcB=
¿ÉµÃ£¬²»Ó°ÏìÅäÖƽá¹û£¬¹Ê¢Û´íÎó£»
¢Ü¶¨ÈÝʱ£¬ÑÛ¾¦ÑöÊӿ̶ÈÏߣ¬ÔòÈÝÁ¿Æ¿ÖÐÈÜÒºµÄÌå»ýÆ«´ó£¬¸ù¾ÝcB=
¿ÉµÃ£¬ÅäÖƵÄÈÜÒºµÄŨ¶ÈÆ«µÍ£¬¹Ê¢ÜÕýÈ·£»
¹ÊÑ¡¢Ù¢Ü£®
0.2mol/L¡Á0.5L |
18.4mol/L |
¹Ê´ð°¸Îª£º5.4£»
£¨2£©ÅäÖÆ500mL0.2mol?L-1µÄÏ¡ÁòËᣬËùÐèÒÇÆ÷³ýÁ˲£Á§°ô¡¢ÉÕ±¡¢½ºÍ·µÎ¹Ü¡¢Á¿Í²Í⣬»¹ÐèÒª500mLÈÝÁ¿Æ¿£¬
¹Ê´ð°¸Îª£º500mLÈÝÁ¿Æ¿£»
£¨3£©ÔÚÏ¡ÊÍŨÁòËáʱ£¬ÐèҪʹÓò£Á§°ô½Á°è£¬¼ÓËÙŨÁòËáµÄÏ¡ÊÍ£»ÔÚתÒÆÈÜҺʱÐèҪͨ¹ý²£Á§°ôÒýÁ÷£¬·ÀÖ¹ÈÜÒºÁ÷µ½ÈÝÁ¿Æ¿ÍâÃ棬
¹Ê´ð°¸Îª£º½Á°è×÷Óã»ÒýÁ÷£»
£¨4£©A£®ÈÝÁ¿Æ¿µÄ¶¨Á¿ÒÇÆ÷£¬ËùÒÔ±êÓÐÈÝ»ýºÍ¿Ì¶È£¬Î¶ÈÓ°ÏìÈÜÒºµÄÌå»ý£¬ËùÒÔÈÝÁ¿Æ¿ÉÏ»¹±êÓÐʹÓõÄζȣ¬¹ÊAÕýÈ·£»
B£®ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»ºó£¬ÓÉÓÚºóÃ滹ÐèÒª¼ÓÈëÕôÁóË®¶¨ÈÝ£¬ËùÒÔ²»±Øºæ¸É£¬²»Ó°ÏìÅäÖƽá¹û£¬¹ÊB´íÎó£»
C£®ÈÝÁ¿Æ¿Öв»ÄÜÓÃÓÚÏ¡ÊÍŨÁòËᣬӦ¸ÃÔÚÉÕ±ÖÐÏ¡ÊÍ£¬ÀäÈ´ºóתÒƵÄÈÝÁ¿Æ¿ÖУ¬¹ÊC´íÎó£»
D£®ÓÉÓÚÈÝÁ¿Æ¿ÓÐÆ¿Èû£¬ÅäÖÆʱÐèÒªÒ¡ÔÈ£¬ËùÒÔʹÓÃÇ°Òª¼ì²éÈÝÁ¿Æ¿ÊÇ·ñ©ˮ£¬¹ÊDÕýÈ·£»
¹ÊÑ¡AD£»
£¨5£©¢ÙδϴµÓÏ¡ÊÍŨÁòËáʱÓùýµÄÉÕ±ºÍ²£Á§°ô£¬ÔòÈÝÁ¿Æ¿ÖÐÈÜÖʵÄÎïÖʵÄÁ¿¼õС£¬¸ù¾ÝcB=
nB |
V |
¢ÚδµÈÏ¡ÊͺóµÄÁòËáÈÜÒºÀäÈ´ÖÁÊÒξÍתÒƵ½ÈÝÁ¿Æ¿ÖУ¬ÀäÈ´ºóÈÜÒºµÄÌå»ý±äС£¬¸ù¾ÝcB=
nB |
V |
¢ÛתÒÆÇ°£¬ÈÝÁ¿Æ¿Öк¬ÓÐÉÙÁ¿ÕôÁóË®£¬ÓÉÓÚºóÃ滹ÐèÒª¼ÓÈëÕôÁóË®¶¨ÈÝ£¬¸ù¾ÝcB=
nB |
V |
¢Ü¶¨ÈÝʱ£¬ÑÛ¾¦ÑöÊӿ̶ÈÏߣ¬ÔòÈÝÁ¿Æ¿ÖÐÈÜÒºµÄÌå»ýÆ«´ó£¬¸ù¾ÝcB=
nB |
V |
¹ÊÑ¡¢Ù¢Ü£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿