ÌâÄ¿ÄÚÈÝ

£¨7·Ö£¬Ã¿¿Õ1·Ö£©A¡¢B¡¢C¡¢DΪͬһÖÜÆÚµÄËÄÖÖÔªËØ£¬Ô­×ÓÐòÊýÒÀ´ÎÔö´ó£¬ÒÑÖª0.2ĦAÓëËá³ä·Ö·´Ó¦Ê±£¬ÔÚ±ê¿öÏ¿ÉÉú³É2.24ÉýÇâÆø£»BµÄÑõ»¯Îï¼È¿ÉÈÜÓÚÇ¿ËáÓÖ¿ÉÈÜÓÚÇ¿¼îÈÜÒº£»C¡¢DÒõÀë×ӵĵç×Ó²ã½á¹¹Óëë²Ô­×ÓÏàͬ£¬CµÄÆø̬Ç⻯ÎïÓëCµÄµÍ¼ÛÑõ»¯Îï·´Ó¦£¬Óֿɵõ½CµÄµ¥ÖÊ¡£ÊԻشð£º
£¨1£©A¡¢B¡¢C¡¢DµÄÔªËØ·ûºÅ·Ö±ðΪ______¡¢____ ¡¢     ¡¢______¡£
£¨2£©Óõç×Óʽ±íʾAÓëCÐγɻ¯ºÏÎïµÄ¹ý³Ì£º
_________________________________________________¡£
£¨3£©Ð´³öBµÄÑõ»¯ÎïÓëAµÄÇâÑõ»¯Îï·´Ó¦µÄÀë×Ó·½³Ìʽ£º
_________________________________               ¡£
£¨4£©Ð´³öʵÑéÊÒÖƱ¸DµÄµ¥ÖʵĻ¯Ñ§·´Ó¦·½³Ìʽ£º
__________________________________________¡£
£¨Ã¿¿Õ1·Ö£©£¨1£©Na¡¢Al¡¢S¡¢Cl£¨2£©ÂÔ
£¨3£©Al2O3 + 2OH - =" AlO" - + H 2O
£¨4£©MnO2 + 4HCl(Ũ)  MnCl2 + Cl2¡ü + H2O
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø