ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿º£´øÖк¬ÓзḻµÄµâ¡£Ä³Ñо¿ÐÔѧϰС×é°´ÏÂͼËùʾʵÑéÁ÷³ÌÌáÈ¡º£´øÖеĵ⡣

»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©²½Öè¢Ù×ÆÉÕº£´øʱ£¬³ýÈý½Å¼ÜÍ⣬»¹ÐèÒªÓõ½ÏÂÁÐÒÇÆ÷ÖеÄ________£¨Ìî×Öĸ±êºÅ£©¡£

A£®ÉÕ±­ B£®ÛáÛö C£®Õô·¢Ãó D£®ÄàÈý½Ç E£®¾Æ¾«µÆ F£®¸ÉÔïÆ÷

£¨2£©²½Öè¢ÛµÄʵÑé²Ù×÷Ãû³ÆÊÇ________¡£

£¨3£©²½Öè¢Ü·´Ó¦µÄÀë×Ó·½³ÌʽΪ____________________________¡£

£¨4£©²½Öè¢ÝÖУ¬¿ÉÒÔÓñ½À´ÌáÈ¡µâµÄÀíÓÉÊÇ__________________£¬µâË®ÈÜÒº¼ÓÈë±½ºó£¬Õñµ´¡¢¾²Ö¹¿É¹Û²ìµ½µÄʵÑéÏÖÏóΪ________¡£

£¨5£©ÇëÉè¼ÆʵÑé¼ìÑéÌáÈ¡µâºóµÄË®ÈÜÒºÖÐÊÇ·ñ»¹Óе¥Öʵâ__________________¡£

¡¾´ð°¸¡¿ BDE ¹ýÂË 2I£­£«MnO2£«4H£«£½Mn2£«£«I2£«2H2O ±½ÓëË®»¥²»ÏàÈÜ£¬µâÔÚ±½ÖеÄÈܽâ¶È±ÈÔÚË®ÖеĴó ·Ö²ã£¬ÉϲãΪ×ÏÉ«£¬Ï²ã½Ó½üÎÞÉ« È¡ÉÙÁ¿ÌáÈ¡µâºóµÄË®ÈÜÒºÓÚÊÔ¹ÜÖУ¬¼ÓÈ뼸µÎµí·ÛÊÔÒº¡£Èç¹ûÈÜÒº±äÀ¶£¬ËµÃ÷»¹Óе¥Öʵ⣻Èç¹ûÈÜÒº²»±äÀ¶£¬ËµÃ÷ûÓе¥Öʵâ

¡¾½âÎö¡¿£¨1£©ÈçͼÊÇ×ÆÉÕº£´øµÄ×°ÖÃͼ£¬ÛáÛö·ÅÔÚÄàÈý½ÇÉÏ£¬ÄàÈý½ÇÔÚÈý½Å¼ÜÉÏ£¬Ï·½¿Õ¼ä·Å¾Æ¾«µÆ¼ÓÈÈ£¬¹ÊÑ¡BDE¡£

£¨2£©²½Öè¢ÛÊÇ·ÖÀë¹ÌÌåºÍÒºÌåµÃµ½º¬µâÀë×ÓµÄÈÜÒº£¬ÊµÑé²Ù×÷Ãû³ÆÊǹýÂË¡£

£¨3£©µâÀë×Ó¾ßÓл¹Ô­ÐÔ£¬MnO2¾ßÓнÏÇ¿µÄÑõ»¯ÐÔ£¬ÔÚËáÐÔÌõ¼þÏ·¢ÉúÑõ»¯»¹Ô­·´Ó¦½«µâÀë×Óת»¯³Éµâµ¥ÖÊ£¬¸ù¾ÝÊغ㷨²»ÄÑд³öÀë×Ó·½³Ìʽ£º2I£­£«MnO2£«4H£«£½Mn2£«£«I2£«2H2O¡£

£¨4£©±½ÓëË®»¥²»ÏàÈÜÇÒµâÔÚ±½ÖеÄÈܽâ¶È±ÈÔÚË®Öдó£¬ÕâÑù¿ÉÒÔͨ¹ýÝÍÈ¡·¨Óñ½À´ÌáÈ¡µâ£»µâµ¥ÖÊÈÜÓÚ±½ºóÈÜÒºÑÕÉ«¼ÓÉÇÒ±½µÄÃܶȱÈË®µÄÃܶÈС£¬Òò´ËµâË®ÈÜÒº¼ÓÈë±½ºó£¬Õñµ´¡¢¾²Ö¹¿É¹Û²ìµ½µÄʵÑéÏÖÏóΪ£ºÒºÌå·Ö²ã£¬ÉϲãΪ×ÏÉ«£¬Ï²ã½Ó½üÎÞÉ«¡£

£¨5£©µí·ÛÈÜÒºÓöI2±äÀ¶É«£¬¿ÉÓõí·ÛÈÜÒºÀ´¼ìÑéµâµ¥ÖÊ£¬È¡ÉÙÁ¿ÌáÈ¡µâºóµÄË®ÈÜÒºÓÚÊÔ¹ÜÖУ¬¼ÓÈ뼸µÎµí·ÛÊÔÒº£¬Èç¹ûÈÜÒº±äÀ¶£¬ËµÃ÷»¹Óе¥Öʵ⣻Èç¹ûÈÜÒº²»±äÀ¶£¬ËµÃ÷ûÓе¥Öʵ⡣

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿£¨1£©º¬0.4 mol Al2£¨SO4£©3µÄÈÜÒºÖУ¬º¬________mol SO¡£

£¨2£©ÅäÖÆ480mL 1mol/L µÄNaOHÈÜÒº£¬ÐèÒª³ÆÁ¿ÇâÑõ»¯ÄƹÌÌåµÄÖÊÁ¿Îª_______¡£

£¨3£©Èôm gijÆøÌåÖк¬·Ö×ÓÊýN¸ö£¬ÒÑÖª°¢·ü¼ÓµÂÂÞ³£ÊýΪNA£¬Ôò¸ÃÆøÌåµÄĦ¶ûÖÊÁ¿Îª____¡£

£¨4£©O2ºÍN2×é³ÉµÄ»ìºÏÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿ÊÇ31£¬ÔòO2ºÍN2µÄÎïÖʵÄÁ¿±ÈΪ__________¡£

£¨5£©ÔÚ·´Ó¦2KClO3£«H2C2O4£«H2SO42ClO2¡ü£«K2SO4£«2CO2¡ü£«2H2OÖУ¬Ñõ»¯¼ÁÊÇ________¡£

£¨6£©·Ö±ðÈ¡0.1mol ÄÆ¡¢Ã¾¡¢ÂÁÓë×ãÁ¿µÄÑÎËá·´Ó¦£¬ÔÚÏàͬÌõ¼þϲúÉúÇâÆøµÄÌå»ý±ÈÊÇ ____________£»Èô0.2mol ÄÆ¡¢Ã¾¡¢ÂÁ·Ö±ð·ÅÈëµ½10mL 1mol/L µÄÑÎËáÖУ¬ÔÚ±ê×¼×´¿öÏ£¬²úÉúÇâÆøÌå»ý·Ö±ðΪV1¡¢V2¡¢V3£¬ÔòÈýÕߵĴóС˳ÐòÊÇ____________£¨ÓÃV1¡¢V2¡¢V3Ìîд£©

£¨7£©ÏÖÓÐÏÂÁÐÎïÖÊ¢ÙNaCl¾§Ìå¢Ú¸É±ù¢ÛHCl¢ÜÍ­¢ÝCaCO3¹ÌÌå¢ÞÆÏÌÑÌǢ߾ƾ«¢àÈÛÈÚµÄKNO3¢áÒºÑõ¢âÏ¡ÁòËá¡£ÒÔÉÏÎïÖÊÄܵ¼µçµÄÊÇ_________________¡£

£¨8£©ÔÚ´ÖÑÎÌá´¿µÄʵÑéÖУ¬ÅжÏBaCl2ÈÜÒº¹ýÁ¿µÄʵÑé²Ù×÷·½·¨ÊÇ______________¡£

£¨9£©Î¸ËáÖк¬ÓÐÑÎËᣬθËá¹ý¶àµÄÈ˳£ÓÐθÌÛÉÕÐĵĸоõ£¬Ò×ÍÂËáË®£¬·þÓÃÊÊÁ¿µÄСËÕ´ò£¬ÄÜÖÎÁÆθËá¹ý¶à£¬Çëд³öÆä·´Ó¦µÄÀë×Ó·½³Ìʽ________________________________¡£

¡¾ÌâÄ¿¡¿¶ÌÖÜÆÚÔªËØX¡¢Y¡¢Z¡¢W¡¢QÔÚÔªËØÖÜÆÚ±íÖеÄÏà¶ÔλÖÃÈçͼËùʾ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)WÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ__________£¬Y¡¢ZµÄÀë×Ӱ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòΪ__________ (ÓÃÔªËØ·ûºÅ±íʾ)¡£

(2)ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ__________¡£

a.XY2ºÍWY2¶¼ÄÜÈÜÓÚË®Éú³É¶ÔÓ¦µÄËá

b.QµÄº¬ÑõËáµÄËáÐÔ±ÈXµÄº¬ÑõËáµÄËáÐÔÇ¿

c.XµÄ×î¼òµ¥Æø̬Ç⻯ÎïµÄÎȶ¨ÐÔ´óÓÚWµÄ×î¼òµ¥Æø̬Ç⻯ÎïµÄÎȶ¨ÐÔ

d.ÓÉNaOHÈÜÒº·Ö±ðµÎÈëMgQ2¡¢ZQ3ÈÜÒºÖеķ´Ó¦ÏÖÏó¿É±È½ÏMgºÍZ½ðÊôÐÔµÄÇ¿Èõ

(3)×ÔÀ´Ë®³§³£ÓÃQY2¶ÔÒûÓÃË®½øÐÐÏû¶¾£¬´¦ÀíºóµÄË®ÖÐÒªÇóQY2µÄŨ¶ÈÔÚ0.10¡«0.80mg¡¤L-1Ö®¼ä¡£µâÁ¿·¨¿ÉÒÔ¼ì²âË®ÖÐQY2µÄŨ¶È£¬²½ÖèÈçÏ£º

²Ù×÷1£ºÈ¡Ò»¶¨Ìå»ýµÄË®Ñù£¬¼ÓÈëÒ»¶¨Á¿µÄµâ»¯¼Ø£¬ÔÙÓÃNaOHÈÜÒºµ÷ÖÁÖÐÐÔ£¬²¢¼ÓÈëµí·ÛÈÜÒº£¬ÈÜÒº±äÀ¶¡£

²Ù×÷II£ºÔÙ¼ÓÈëÒ»¶¨Á¿µÄNa2S2O3ÈÜÒº¡££¨¼ºÖª£º2S2O32-+I2=S4O62-+2I-£©

²Ù×÷¢ó£ºÈ»ºóÔÙ¼ÓÁòËáµ÷½ÚË®ÑùpHÖÁ1¡«3¡£

²Ù×÷ʱ£¬²»Í¬pH»·¾³ÖÐQÔªËØÁ£×ÓÖÖÀ༰»¯ºÏ¼ÛÈçͼËùʾ£º

¢Ù²Ù×÷IÖз´Ó¦µÄÀë×Ó·½³ÌʽÊÇ___________________¡£

¢ÚÈ·¶¨²Ù×÷¢òÍêÈ«·´Ó¦µÄÏÖÏóÊÇ_________________¡£

¢ÛÔÚ²Ù×÷¢ó¹ý³ÌÖУ¬ÈÜÒºÓÖ³ÊÀ¶É«£¬·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ_________________¡£

¢ÜÈôË®ÑùµÄÌå»ýΪ1.0 L£¬ÔÚ²Ù×÷¢òÖÐÏûºÄÁË l.0¡Á10-3mol¡¤L-1µÄNa2S2O3ÈÜÒº10 mL£¬ÔòË®ÑùÖÐQY2µÄŨ¶ÈÊÇ_______ mg.L-1(¾«È·µ½0.01)¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø