Question

25 ℃、101 kPa下，碳、氢气、甲烷和葡萄糖的燃烧热依次是ΔH＝－393.5 kJ/mol、ΔH＝－285.8 kJ/mol、ΔH＝－890.3 kJ/mol、ΔH＝－2 800 kJ/mol，则下列热化学方程式正确的是(　　)

A．C(s)＋O2(g)=CO(g) ΔH＝－393.5 kJ/mol

B．2H2(g)＋O2(g)=2H2O(l) ΔH＝－571.6 kJ/mol

C．CH4(g)＋2O2(g)=CO2(g)＋2H2O(g) ΔH＝－890.3 kJ/mol

D.C6H12O6(s)＋3O2(g)=3CO2(g)＋3H2O(g) ΔH＝－1 400 kJ/mol

 

Answer 1

　B

【解析】　A项中C的稳定氧化物为CO2，C项和D项中H2O应为液态。