ÌâÄ¿ÄÚÈÝ


¹ÌµªÓÐÈýÖÖ·½Ê½£ºÉúÎï¹Ìµª¡¢¹¤ÒµºÏ³É°±ºÍ·ÅµçÌõ¼þϵªÆøÓëÑõÆø»¯ºÏ¡£È«ÊÀ½ç¹¤ÒµºÏ³Éµª·ÊÖеĵªÖ»Õ¼¹Ìµª×ÜÁ¿µÄ20%£¬ÆäÓà¾ø´ó¶àÊýÊÇͨ¹ýÉúÎï¹Ìµª½øÐеģ¬×î³£¼ûµÄÊǶ¹¿ÆÖ²Îï¸ù²¿µÄ¸ùÁö¾ú£¬Äܽ«´óÆøÖÐÓÎÀë̬µÄµª¾­¹ÌµªÃ¸µÄ×÷ÓÃÉú³ÉµªµÄ»¯ºÏÎÒÔÀûÓÚÖ²ÎïÀûÓá£
£¨1£©¸ùÁö¾úÓ붹¿ÆÖ²ÎïµÄ¹ØϵÔÚÉúÎïѧÉϳÆΪ__________________;
£¨2£©¸ùÁö¾úÖ®ËùÒÔÓй̵ª×÷Óã¬ÊÇÒòΪËüÓжÀÌصĹ̵ªÃ¸£¬¶ø×î¸ù±¾Ô­ÒòÊÇËüº¬ÓжÀÌصÄ___________________;
£¨3£©ÈÕ±¾¿Æѧ¼Ò°Ñ¹Ìµª»ùÒòתÒƵ½Ë®µ¾¸ù¼Ê΢ÉúÎïÖУ¬Í¨¹ýÖ¸µ¼ºÏ³É¹ÌµªËùÐèµÄ_____________½ø¶øÒýÆð¹Ìµª×÷Ó᣸üΪÀíÏëµÄÊÇÖ±½Ó½«¹Ìµª»ùÒòתÒƵ½µ¾¡¢ÂóµÈÁ¸Ê³¼°¾­¼Ã×÷ÎïµÄϸ°ûÖУ¬ÈÃÖ²Îï±¾ÉíÖ±½Ó¹Ìµª£¬ÕâÑù¿ÉÒÔÃâÊ©µª·Ê¡£Èç¹ûÕâÖÖÔ¸ÍûʵÏֵĻ°Ëµ£¬ÄÇô¹Ìµª»ùÒòÖÐÒÅ´«ÐÅÏ¢±í´ï;¾¶Îª___________________________________;
£¨4£©ÕâÖÖÉúÎï¹ÌµªÓ빤ҵºÏ³É°±±È½Ï£¬ËüÊÇÔÚ_____________Ìõ¼þϽøÐеģ¬´Ó¶ø½ÚÊ¡ÁË´óÁ¿µÄÆ÷²Ä¡¢É豸ºÍÄÜÔ´£»
£¨5£©Ë×»°Ëµ¡°À×Ó귢ׯ¼Ú¡±£¬ÒòΪµçÉÁÀ×ÃùµÄÓêÌ죬µªÆøÔÚ¿ÕÆøÖз¢ÉúһϵÁеķ´Ó¦£¬²úÉúÁËÖ²Îï¿ÉÀûÓõ嬵ª»¯ºÏÎд³öÓйصÄÈý¸ö·´Ó¦·½³Ìʽ____________________¡¢____________________________¡¢
____________________________________¡£
(1)¹²Éú
(2)¹Ìµª»ùÒò
(3)¹ÌµªÃ¸£»¹Ìµª»ùÒò¡úÐÅʹRNA¡ú¹ÌµªÃ¸
(4)³£Î¡¢³£Ñ¹
(5)N2+O2="2NO"
2NO+O2=2NO2
3NO2+H2O=2HNO3+NO
¶ÔÓÚµªÔªËØÓ뵪ԪËصĻ¯ºÏÎïµÄÐÔÖÊ£¬ÒªºÜÇå³þ£¬Í¬Ê±ÐèÒª½áºÏÉúÎïѧ֪ʶ£¬ÕâÊÇ×ÛºÏÌâ¡£(1)¹²Éú
(2)¹Ìµª»ùÒò
(3)¹ÌµªÃ¸£»¹Ìµª»ùÒò¡úÐÅʹRNA¡ú¹ÌµªÃ¸
(4)³£Î¡¢³£Ñ¹
(5)N2+O2="2NO"
2NO+O2=2NO2
3NO2+H2O=2HNO3+NO
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø