ÌâÄ¿ÄÚÈÝ
ÏÂÁÐÊÇÓйØʵÑéµÄÐðÊöÖУ¬ºÏÀíµÄÊÇ
¢ÙÓÃÍÐÅÌÌìƽ³ÆÈ¡25.20 gNaCl¹ÌÌå
¢ÚÓÃÌúÛáÛö×ÆÉÕÇâÑõ»¯ÄƹÌÌå
¢ÛʹÓÃÈÝÁ¿Æ¿µÄµÚÒ»²½²Ù×÷ÊÇÏȽ«ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴµÓºóºæ¸É
¢ÜÓÃ25 mL¼îʽµÎ¶¨¹ÜÁ¿È¡14.80 mL 1 mol/L NaOHÈÜÒº
¢ÝÓÃʪÈóµÄpHÊÔÖ½²â¶¨Ä³ÈÜÒºµÄpH
¢ÞʵÑéÊÒÅäÖÆÂÈ»¯ÌúÈÜҺʱ£¬¿ÉÒÔÏȽ«ÂÈ»¯ÌúÈܽâÔÚÑÎËáÖУ¬ÔÙÅäÖƵ½ËùÐèÒªµÄŨ¶È
¢ÙÓÃÍÐÅÌÌìƽ³ÆÈ¡25.20 gNaCl¹ÌÌå
¢ÚÓÃÌúÛáÛö×ÆÉÕÇâÑõ»¯ÄƹÌÌå
¢ÛʹÓÃÈÝÁ¿Æ¿µÄµÚÒ»²½²Ù×÷ÊÇÏȽ«ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴµÓºóºæ¸É
¢ÜÓÃ25 mL¼îʽµÎ¶¨¹ÜÁ¿È¡14.80 mL 1 mol/L NaOHÈÜÒº
¢ÝÓÃʪÈóµÄpHÊÔÖ½²â¶¨Ä³ÈÜÒºµÄpH
¢ÞʵÑéÊÒÅäÖÆÂÈ»¯ÌúÈÜҺʱ£¬¿ÉÒÔÏȽ«ÂÈ»¯ÌúÈܽâÔÚÑÎËáÖУ¬ÔÙÅäÖƵ½ËùÐèÒªµÄŨ¶È
A£®¢Ú¢Ü¢Þ | B£®¢Ú¢Û¢Þ | C£®¢Ù¢Ú¢Ü | D£®¢Ú¢Û¢Ü¢Ý¢Þ |
A
ÊÔÌâ·ÖÎö£ºÍÐÅÌÌìƽֻÄܶÁÊýµ½0.1g£¬¢Ù²»ÕýÈ·£»½ðÊôÌúºÍÇâÑõ»¯ÄƲ»·´Ó¦£¬¿ÉÓÃÌúÛáÛö×ÆÉÕÇâÑõ»¯ÄƹÌÌ壬¢ÚÕýÈ·£»Ê¹ÓÃÈÝÁ¿Æ¿µÄµÚÒ»²½²Ù×÷ÊǼì©£¬¢Û²»ÕýÈ·£»ÇâÑõ»¯ÄÆÊÇÇ¿¼î£¬Ó¦¸ÃÓüîʽµÎ¶¨¹ÜÁ¿È¡£¬¢ÜÕýÈ·£»ÓÃpHÊÔÖ½²â¶¨Ä³ÈÜÒºµÄpHʱ£¬ÊÔÖ½²»ÄÜÊÂÏÈʪÈ󣬢ݲ»ÕýÈ·£»ÂÈ»¯ÌúÈÜÓÚË®£¬ÌúÀë×ÓË®½â£¬ÈÜÒºÏÔËáÐÔ£¬ËùÒÔʵÑéÊÒÅäÖÆÂÈ»¯ÌúÈÜҺʱ£¬¿ÉÒÔÏȽ«ÂÈ»¯ÌúÈܽâÔÚÑÎËáÖУ¬ÒÔÒÖÖÆÌúÀë×ÓË®½â£¬È»ºóÔÙÅäÖƵ½ËùÐèÒªµÄŨ¶È£¬¢ÞÕýÈ·£¬´ð°¸Ñ¡A¡£
µãÆÀ£º»¯Ñ§ÊµÑé³£ÓÃÒÇÆ÷µÄʹÓ÷½·¨ºÍ»¯Ñ§ÊµÑé»ù±¾²Ù×÷ÊǽøÐл¯Ñ§ÊµÑéµÄ»ù´¡£¬¶Ô»¯Ñ§ÊµÑéµÄ¿¼²éÀë²»¿ª»¯Ñ§ÊµÑéµÄ»ù±¾²Ù×÷£¬ËùÒÔ¹ýÂËÊÔÌâÖ÷ÒªÊÇÒÔ³£¼ûÒÇÆ÷µÄÑ¡Óá¢ÊµÑé»ù±¾²Ù×÷ΪÖÐÐÄ£¬Í¨¹ýÊÇʲô¡¢ÎªÊ²Ã´ºÍÔõÑù×öÖص㿼²éʵÑé»ù±¾²Ù×÷µÄ¹æ·¶ÐÔºÍ׼ȷÐÔ¼°Áé»îÔËÓÃ֪ʶ½â¾öʵ¼ÊÎÊÌâµÄÄÜÁ¦¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿