ÌâÄ¿ÄÚÈÝ
´×ËáºÍÑÎËáÊÇÈÕ³£Éú»îÖм«Îª³£¼ûµÄËᣬÔÚÒ»¶¨Ìõ¼þÏÂCH3COOHÈÜÒºÖдæÔÚµçÀëƽºâ£ºCH3COOHCH3COO£+H+ ¦¤H£¾0
£¨1£©³£ÎÂÏ£¬pH£½5´×ËáÈÜÒºÖУ¬c(CH3COO£)£½______mol/L(¾«È·Öµ£¬ÒªÇóÁÐʽ²»±Ø»¯¼ò)£»
£¨2£©ÏÂÁз½·¨ÖпÉÒÔʹ0.10 mol¡¤L-1 CH3COOHµÄµçÀë³Ì¶ÈÔö´óµÄÊÇ
a£®¼ÓÈëÉÙÁ¿0.10 mol¡¤L£1Ï¡ÑÎËá b£®¼ÓÈÈCH3COOHÈÜÒº c£®¼ÓˮϡÊÍÖÁ0.010 mol¡¤L£1
d£®¼ÓÈëÉÙÁ¿±ù´×Ëá e£®¼ÓÈëÉÙÁ¿ÂÈ»¯ÄƹÌÌå f£®¼ÓÈëÉÙÁ¿0.10 mol¡¤L£1 NaOHÈÜÒº
£¨3£©½«µÈÖÊÁ¿µÄпͶÈëµÈÌå»ýÇÒpH¾ùµÈÓÚ3µÄ´×ËáºÍÑÎËáÈÜÒºÖУ¬¾¹ý³ä·Ö·´Ó¦ºó£¬·¢ÏÖÖ»ÔÚÒ»ÖÖÈÜÒºÖÐÓÐп·ÛÊ£Ó࣬ÔòÉú³ÉÇâÆøµÄÌå»ý£ºV(ÑÎËá)_________V(´×Ëá)£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©
£¨4£©ÓÃNaOHÈÜÒº·Ö±ðµÎ¶¨20.00mL0.1mol/LÑÎËáºÍ20.00mL0.1mol/L´×ËáÈÜÒº£¬µÃµ½ÈçͼËùʾÁ½ÌõµÎ¶¨ÇúÏߣ¬ÓÃNaOHÈÜÒºµÎ¶¨´×ËáÈÜÒºµÄÇúÏßÊÇ £¨Ìͼ1¡±»ò¡°Í¼2¡±£©
£¨5£©³£ÎÂÏ£¬½«0.1 mol/LÑÎËáºÍ0.1 mol/L´×ËáÄÆÈÜÒº»ìºÏ£¬ËùµÃÈÜҺΪÖÐÐÔ£¬Ôò»ìºÏÈÜÒºÖи÷Àë×ÓµÄŨ¶È°´ÓÉ´óµ½Ð¡ÅÅÐòΪ_______________________________¡£
£¨6£©ÏÂͼ±íʾÈÜÒºÖÐc(H£«)ºÍc(OH£)µÄ¹Øϵ
¢ÙMÇøÓòÄÚ£¨ÒõÓ°²¿·Ö£©ÈÎÒâµãc(H£«)______c(OH£)£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©
¢ÚÔÚT2ζÈÏ£¬½«pH£½9 NaOHÈÜÒºÓëpH£½4 HClÈÜÒº»ìºÏ£¬ÈôËùµÃ»ìºÏÈÜÒºµÄpH£½7£¬ÔòNaOHÈÜÒºÓëHClÈÜÒºµÄÌå»ý±ÈΪ ¡££¨»ìºÏºóÈÜÒºÌå»ýµÄ±ä»¯ºöÂÔ²»¼Æ£©
£¨1£©10£5£10£9£¨2£©bcf£¨3£©Ð¡ÓÚ£¨4£©Í¼2
£¨5£©c(Na+)£¾c(CH3COO£)£¾c(Cl£)£¾c(H£«)£½c(OH£)£¨6£©¢ÙСÓÚ £»¢Ú1£º9
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º£¨1£©ÔÚ pH=5µÄÏ¡´×ËáÈÜÒºÖУ¬c£¨H+£©=10-5mol/L£¬c£¨OH-£©=10-9mol/L£¬¸ù¾ÝÈÜÒºµçºÉÊغã¿ÉÖªc£¨H+£©=c£¨CH3COO-£©+c£¨OH-£©£¬Ôòc£¨CH3COO-£©=£¨10-5-10-9£©mol/L£¨2£©¼ÓÈÈ¡¢¼ÓˮϡÊÍ¡¢¼ÓÈë¼îÐÔÎïÖʾùÄÜʹµçÀëƽºâÏòÓÒÒƶ¯£¬¹Ê´ð°¸Îª bcf£»£¨3£©´×ËáÊÇÈõËᣬËæ×ÅËüºÍ½ðÊôµÄ·´Ó¦£¬µçÀëƽºâ²»¶ÏµØÏòÓÒÒƶ¯£¬»áµçÀë³ö¸ü¶àµÄÇâÀë×Ó£¬ËùÒÔ´×Ëá²úÉúµÄÇâÆøÌå»ý½Ï´ó£¬¹Ê´ð°¸ÎªÐ¡ÓÚ£»£¨4£©µÎ¶¨¿ªÊ¼Ê±0.002mol/LÑÎËápH=3£¬0.002mol/L´×ËápH£¾3£¬ËùÒԵζ¨´×ËáµÄÇúÏßÊÇͼ2£»£¨5£©½«0.1mol/LÑÎËáºÍ0.1mol/L´×ËáÄÆÈÜÒº»ìºÏ£¬·´Ó¦Éú³É´×ËᣬÈçµÈÌå»ý»ìºÏÎÈÜÒº³ÊËáÐÔ£¬ÈÜÒº³ÊÖÐÐÔ£¬Ó¦¼ÓÈëÉÙÁ¿ÑÎËᣬÉú³É´×ËᣬÔòc£¨Na+£©£¾c£¨CH3COO-£©£¾c£¨Cl-£©ÈÜҺǡºÃ³ÊÖÐÐÔ£¬ÇâÀë×ÓºÍÇâÑõ¸ùµÄŨ¶ÈÒ»¶¨ÏàµÈ£¬c£¨H+£©=c£¨OH-£©£¬ÔòÓÐc£¨Na+£©£¾c£¨CH3COO-£©£¾c£¨Cl-£©£¾c£¨H+£©=c£¨OH-£©£»£¨6£©¢ÙÓÉͼ¿ÉÖª£¬ZXÏß±íʾc(H£«)=c(OH£)£¬ÔòZXÏßÉϲ¿·Ö±íʾc(H£«)<c(OH£)£»¢ÚÓÉͼ֪£¬ÔÚT2ζÈÏ£¬Ë®µÄÀë×Ó»ýΪ£ºc£¨H+£©•c£¨OH-£©=10-12£¬´ËζÈÏÂpH=9µÄNaOHÈÜÒºÖÐc£¨OH-£©==10-3mol/L£¬pH=4µÄHClÈÜÒºc£¨H+£©=10-4mol/L£¬ÈôËùµÃ»ìºÏÈÜÒºµÄpH=7£¬Ôò·´Ó¦ºóµÄÈÜÒºµÄc£¨OH-£©==10-5mol/L£¬¼´=10-5 mol/L£¬µÃV(NaOH)£ºV(HCl)=1£º9¡£
¿¼µã£ºÈõµç½âÖÊÔÚË®ÖеĵçÀëƽºâ£»Àë×ÓŨ¶È´óСµÄ±È½Ï£»Öк͵樣»Àë×Ó»ý³£Êý