ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿Ï±íÖеÄʵÏß±íʾԪËØÖÜÆÚ±íµÄ²¿·Ö±ß½ç¡£

£¨1£©ÇëÔÚÉϱíÖÐÓÃʵÏß²¹³öÔªËØÖÜÆÚ±íµÄÉϱ߽硣_____________

£¨2£©Ä³Ö÷×åÔªËØÔ­×ӵĺËÍâµç×ÓÅŲ¼Îª£º£¬¸ÃÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪ_______________¡£

£¨3£©ÔªËØIµÄ·Ç½ðÊôÐÔ________(Ìî¡°Ç¿ÓÚ¡±»ò¡°ÈõÓÚ¡±)ÔªËØH£¬ÓÃÔ­×ӽṹµÄ¹Ûµã½âÊÍÔ­Òò£ºÍ¬ÖÜÆÚÔªËØËæ×ÅÔ­×ÓÐòÊýµÄµÝÔö£¬______________________£¬·Ç½ðÊôÐÔÔöÇ¿¡£Éè¼ÆʵÑéÖ¤Ã÷ÔªËØEµÄ½ðÊôÐÔÇ¿ÓÚÔªËØF£º__________________________¡£

£¨4£©´¦ÓÚÖÜÆÚ±íÖжԽÇÏßλÖÃ(×óÉÏ·½ºÍÓÒÏ·½) µÄÔªËØ£¬ÆäÐÔÖʾßÓÐÏàËÆÐÔ£¬³ÆΪ¡°¶Ô½ÇÏß¹æÔò¡±¡£ÔªËØDÓëFµÄµ¥Öʼ°Æ仯ºÏÎïÐÔÖÊÏàËÆ£¬ÈçD¡¢DO¡¢D(OH)2ÓëNaOHÈÜÒº¶¼ÄÜ·´Ó¦Éú³ÉNa2DO2µÈÎïÖÊ¡£»Ø´ðÏÂÁÐÎÊÌâ¡£

¢Ùд³öFµÄµ¥ÖÊÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ___________________________¡£

¢Ú¼ø±ðÔªËØDÓëEµÄÇâÑõ»¯Îï¿ÉÓÃÊÔ¼ÁÊÇ_________________¡£

¡¾´ð°¸¡¿ µÚËÄÖÜÆÚµÚ¢öA×å Ç¿ÓÚ Ô­×Ӱ뾶µÝ¼õ£¬µÃµç×ÓÄÜÁ¦ÔöÇ¿ ½«´òÄ¥¹ýµÄþÌõ¡¢ÂÁÌõ·Ö±ðͶÈëÊ¢ÓÐÏàͬÑÎËáµÄÊÔ¹ÜÖУ¬Ã¾Ìõ·´Ó¦¸ü¾çÁÒ 2Al+2H2O+ 2OH-=2AlO2-+3H2¡ü NaOHÈÜÒº

¡¾½âÎö¡¿

·ÖÎöÖÜÆÚ±í½á¹¹µÃµ½DΪBe¡¢EΪMg¡¢FΪAl¡¢GΪP¡¢HΪS¡¢IΪCl¡£

(1)¸ù¾ÝÔªËØÖÜÆÚ±íµÄ½á¹¹ÒÔ¼°ÔªËصķֲ¼Çé¿ö£¬ÔªËØÖÜÆÚ±íÓÐÆ߸öÖÜÆÚ£¬18¸ö×ÝÐУ¬°üÀ¨Æ߸öÖ÷×å¡¢Æ߸ö¸±×å¡¢Ò»¸ö0×å¡¢Ò»¸ö¢ø×壬¾Ý´Ë»­³öÔªËØÖÜÆÚ±íµÄ±ß½ç£»

(2)¸ù¾ÝÖ÷×å×åÐòÊý=×îÍâ²ãµç×ÓÊý£¬ÖÜÆÚÐòÊý=µç×Ó²ãÊý·ÖÎöÅжϣ»

(3)¸ù¾ÝÔ­×ӽṹÓëÔªËصÄÐÔÖʵĹØϵ·ÖÎö½â´ð£»

(4)ÂÁºÍÇâÑõ»¯ÄÆÈÜÒº·´Ó¦Éú³ÉÆ«ÂÁËáÄƺÍÇâÆø£»ÇâÑõ»¯îëµÄÐÔÖÊÀàËÆÓÚÇâÑõ»¯ÂÁ£¬¾Ý´Ë·ÖÎö½â´ð¡£

(1)¸ù¾ÝÔªËØÖÜÆÚ±íµÄ½á¹¹ÒÔ¼°ÔªËصķֲ¼Çé¿ö£¬ÔªËØÖÜÆÚ±íÓÐÆ߸öÖÜÆÚ£¬18¸ö×ÝÐУ¬°üÀ¨Æ߸öÖ÷×å¡¢Æ߸ö¸±×å¡¢Ò»¸ö0×å¡¢Ò»¸ö¢ø×壬±íʾԪËØÖÜÆÚ±íµÄ²¿·Ö±ß½çÈçÏ£º£¬¹Ê´ð°¸Îª£º£»

(2)ijÖ÷×åÔªËØÔ­×ӵĺËÍâµç×ÓÅŲ¼Îª£º£¬¸ÃÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪ£ºµÚËÄÖÜÆÚµÚ¢öA×壬¹Ê´ð°¸Îª£ºµÚËÄÖÜÆÚµÚ¢öA×壻

(3)¸ù¾ÝÔªËØÔÚÖÜÆÚ±íÖеÄλÖã¬ÔªËØIΪClÔªËØ£¬ÔªËØHΪSÔªËØ£¬Í¬ÖÜÆÚÔªËØËæ×ÅÔ­×ÓÐòÊýµÄµÝÔö£¬Ô­×Ӱ뾶µÝ¼õ£¬µÃµç×ÓÄÜÁ¦ÔöÇ¿£¬·Ç½ðÊôÐÔÔöÇ¿£¬ÂÈÔªËصķǽðÊôÐÔÇ¿ÓÚÁòÔªËØ£»EΪMg £¬FΪAl£¬MgµÄ½ðÊôÐÔÇ¿ÓÚÔªËØAl£¬¿ÉÒÔºÍͬŨ¶ÈµÄÏ¡Ëá·´Ó¦µÄ¾çÁҳ̶ÈÅж϶þÕߵĽðÊôÐÔÇ¿Èõ£¬¾ßÌå²½ÖèΪ£º½«´òÄ¥¹ýµÄþÌõ¡¢ÂÁÌõ·Ö±ðͶÈëÊ¢ÓÐÏàͬÑÎËáµÄÊÔ¹ÜÖУ¬Ã¾Ìõ·´Ó¦¸ü¾çÁÒ£¬Ö¤Ã÷þµÄ½ðÊôÐÔÇ¿ÓÚÂÁ£¬¹Ê´ð°¸Îª£ºÇ¿ÓÚ£»Ô­×Ӱ뾶µÝ¼õ£¬µÃµç×ÓÄÜÁ¦ÔöÇ¿£»½«´òÄ¥¹ýµÄþÌõ¡¢ÂÁÌõ·Ö±ðͶÈëÊ¢ÓÐÏàͬÑÎËáµÄÊÔ¹ÜÖУ¬Ã¾Ìõ·´Ó¦¸ü¾çÁÒ£»

(4)ÔªËØDΪBe£¬FΪAl¡£

¢ÙÂÁºÍÇâÑõ»¯ÄÆÈÜÒº·´Ó¦Éú³ÉÆ«ÂÁËáÄƺÍÇâÆø£»·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º2Al+2H2O+2OH-=2AlO2-+3H2¡ü£¬¹Ê´ð°¸Îª£º2Al+2H2O+2OH-=2AlO2-+3H2¡ü£»

¢Ú´¦ÓÚÖÜÆÚ±íÖжԽÇÏßλÖÃ(×óÉÏ·½ºÍÓÒÏ·½) µÄÔªËØ£¬ÆäÐÔÖʾßÓÐÏàËÆÐÔ£¬³ÆΪ¡°¶Ô½ÇÏß¹æÔò¡±£¬îëºÍÂÁÐÔÖÊÏàËÆ£¬ÇâÑõ»¯îëÄܹ»ÈÜÓÚÇâÑõ»¯ÄÆÈÜÒº£¬ÇâÑõ»¯Ã¾²»ÈÜ£¬¼ø±ðÔªËØDÓëEµÄÇâÑõ»¯Îï¿ÉÓÃÊÔ¼ÁÊÇ£ºÇâÑõ»¯ÄÆÈÜÒº£¬¹Ê´ð°¸Îª£ºNaOHÈÜÒº¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø