ÌâÄ¿ÄÚÈÝ
Ϊ¼õСCO2¶Ô»·¾³µÄÓ°Ï죬ÔÚ³«µ¼¡°µÍ̼¡±µÄͬʱ£¬»¹Ðè¼ÓÇ¿¶ÔCO2´´ÐÂÀûÓõÄÑо¿¡£T10C ʱ£¬½«9molCO2ºÍ12molH2³äÈë3LÃܱÕÈÝÆ÷ÖУ¬·¢Éú·´Ó¦CO2(g)+3H2(g)
CH3OH(g)+H2O(g)
¦¤H <0£¬ÈÝÆ÷ÖÐCH3OHµÄÎïÖʵÄÁ¿ËæÊ±¼ä±ä»¯ÈçÇúÏßIËùʾ£¬Æ½ºâʱÈÝÆ÷ÄÚѹǿΪP¡£¸Ä±äijһÌõ¼þÖØÐ½øÐÐÉÏÊö·´Ó¦,CH3OHµÄÎïÖʵÄÁ¿ËæÊ±¼ä±ä»¯ÈçÇúÏßIIËùʾ¡£ÏÂÁÐ˵·¨´íÎóµÄÊÇ
![]()
A£®ÇúÏßII¶ÔÓ¦µÄÌõ¼þ¸Ä±äÊÇÔö´óѹǿ
B£®T2¡ãCʱ£¬ÉÏÊö·´Ó¦Æ½ºâ³£ÊýΪ0.42£¬ÔòT2> T1
C£®ÔÚT10C£¬ÈôÆðʼʱÏòÈÝÆ÷ÖгäÈë5 mol CO2¡¢5 mol H2¡¢5 mol CH3OH(g)ºÍ 5 mol H2O(g)£¬Ôò´ïƽºâǰv(Õý)>v(Äæ£©
D£®ÔÚT10C£¬ÈôÆðʼʱÏòÈÝÆ÷ÓÉͨÈë4,5 molCO2¡¢6mol H2
,ƽºâʱÈÝÆ÷ÄÚѹǿ![]()
D
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£ºA¡¢´ÓͼÏñÖп´³ö£¬ÇúÏßIIËÙÂʼӿ죬ת»¯ÂÊÉý¸ß£¬Æ½ºâÕýÏòÒÆ¶¯£¬ÎªÔö´óѹǿ£¬ÕýÈ·£»B¡¢T1ʱƽºâ³£ÊýΪK1=
=0.5£¬K1>K2£¬Æ½ºâÄæÏòÒÆ¶¯£¬ÇÒÕý·´Ó¦·ÅÈÈ£¬¹ÊΪÉý¸ßζȣ¬ÕýÈ·£»C¡¢Q=
=1>K£¬Æ½ºâÕýÏòÒÆ¶¯£¬¹ÊÕý·´Ó¦ËÙÂÊ´óÓÚÄæ·´Ó¦ËÙÂÊ£¬ÕýÈ·£» D¡¢ÔÚT10C£¬ÈôÆðʼʱÏòÈÝÆ÷ÓÉͨÈë4,5molC02¡¢6mol H2
¡£Ï൱ÓÚ°ÑÔÀ´µÄ·´Ó¦ÈÝÆ÷´ÓÖмäÇпª£¬ÔÙ°ÑÆäÖеÄÒ»°ë½øÐмõѹ²Ù×÷£¬Ê¹Ìå»ýÀ©´óÒ»±¶£¬´ËʱƽºâÏ൱ÓÚÔÚÔÀ´µÄƽºâ»ù´¡ÉÏÏòÌå»ýÔö´óµÄ·½Ïò£¬ÄæÏòÒÆ¶¯£¬Æ½ºâºóʱÈÝÆ÷ÄÚѹǿҪ´óÓÚÔÀ´µÄÒ»°ë¡£
¿¼µã£º¿¼²éÓ°Ï컯ѧƽºâµÄÌõ¼þ¡¢»¯Ñ§Æ½ºâµÄÒÆ¶¯·½Ïò¡¢»¯Ñ§Æ½ºâ³£Êý¡¢µÈЧƽºâµÈ֪ʶ£¬
| A¡¢0¡«3minÄÚ£¬v£¨CO2£©Õý=v £¨CH3OH£©Õý | B¡¢ÆäËûÌõ¼þ²»±ä£¬ÈôÏòƽºâºóµÄÌåϵÖгäÈë1molº¤Æø£¬ÌåϵѹǿÔö´óƽºâ½«ÏòÕý·½ÏòÒÆ¶¯ | C¡¢ÔÚT1¡æÊ±£¬ÈôÆðʼʱÏòÈÝÆ÷ÖгäÈë2molCO2ºÍ6mol H2£¬²âµÃƽºâʱÈÝÆ÷ÄÚѹǿΪP2£¬Ôò P2£¼2P1 | D¡¢T2¡æÊ±£¬ÉÏÊö·´Ó¦Æ½ºâ³£ÊýΪ4.2£¬ÔòT2£¾T1 |
Ϊ¼õСCO2¶Ô»·¾³µÄÓ°Ï죬ÔÚÏÞÖÆÆäÅÅ·ÅÁ¿µÄͬʱ£¬Ó¦¼ÓÇ¿¶ÔCO2´´ÐÂÀûÓõÄÑо¿¡£
(1)¢Ù °Ñº¬ÓнϸßŨ¶ÈCO2µÄ¿ÕÆøÍ¨Èë±¥ºÍK2CO3ÈÜÒº¡£
¢Ú ÔÚ¢ÙµÄÎüÊÕÒºÖÐͨ¸ßÎÂË®ÕôÆøµÃµ½¸ßŨ¶ÈµÄCO2ÆøÌå¡£
д³ö¢ÚÖз´Ó¦µÄ»¯Ñ§·½³Ìʽ________¡£
(2)È罫CO2ÓëH2ÒÔ1:3µÄÌå»ý±È»ìºÏ¡£
¢ÙÊʵ±Ìõ¼þϺϳÉijÌþºÍË®£¬¸ÃÌþÊÇ_______(ÌîÐòºÅ)¡£
| A£®ÍéÌþ | B£®Ï©Ìþ | C£®È²Ìþ | D£®±½µÄͬϵÎï |
²âµÃCO2(g)ºÍCH3OH(g)µÄŨ¶ÈËæÊ±¼ä±ä»¯ÈçͼËùʾ¡£
´Ó·´Ó¦¿ªÊ¼µ½Æ½ºâ£¬v(H2)£½______£»ÇâÆøµÄת»¯ÂÊ£½_______£»ÄÜʹƽºâÌåϵÖÐn(CH3OH)Ôö´óµÄ´ëÊ©ÓÐ______¡£
(3)È罫CO2ÓëH2ÒÔ1:4µÄÌå»ý±È»ìºÏ£¬ÔÚÊʵ±µÄÌõ¼þÏ¿ÉÖÆµÃCH4¡£
ÒÑÖª£º
CH4 (g) + 2O2(g)
H2(g) + 1/2O2(g)
ÔòCO2(g)ÓëH2(g)·´Ó¦Éú³ÉCH4(g)ÓëҺ̬ˮµÄÈÈ»¯Ñ§·½³ÌʽÊÇ________¡£
(4)ijͬѧÓóÁµí·¨²â¶¨º¬ÓнϸßŨ¶ÈCO2µÄ¿ÕÆøÖÐCO2µÄº¬Á¿£¬¾²éµÃһЩÎïÖÊÔÚ20¡æµÄÊý¾ÝÈçÏÂ±í¡£
| Èܽâ¶È(S)/g | ÈܶȻý(Ksp) | ||
| Ca(OH)2 | Ba(OH)2 | CaCO3 | BaCO3 |
| 0.16 | 3.89 | 2.9¡Á10-9 | 2.6¡Á10-9 |
ÎüÊÕCO2×îºÏÊʵÄÊÔ¼ÁÊÇ_________[Ìî¡°Ca(OH)2¡±»ò¡°Ba(OH)2¡±]ÈÜÒº£¬ÊµÑéʱ³ýÐèÒª²â¶¨¹¤Òµ·ÏÆøµÄÌå»ý(ÕÛËã³É±ê×¼×´¿ö)Í⣬»¹ÐèÒª²â¶¨__________¡£
Ϊ¼õСCO2¶Ô»·¾³µÄÓ°Ï죬ÔÚÏÞÖÆÆäÅÅ·ÅÁ¿µÄͬʱ£¬Ó¦¼ÓÇ¿¶ÔCO2´´ÐÂÀûÓõÄÑо¿¡£
(1)¢Ù °Ñº¬ÓнϸßŨ¶ÈCO2µÄ¿ÕÆøÍ¨Èë±¥ºÍK2CO3ÈÜÒº¡£
¢Ú ÔÚ¢ÙµÄÎüÊÕÒºÖÐͨ¸ßÎÂË®ÕôÆøµÃµ½¸ßŨ¶ÈµÄCO2ÆøÌå¡£
д³ö¢ÚÖз´Ó¦µÄ»¯Ñ§·½³Ìʽ________¡£
(2)È罫CO2ÓëH2 ÒÔ1:3µÄÌå»ý±È»ìºÏ¡£
¢ÙÊʵ±Ìõ¼þϺϳÉijÌþºÍË®£¬¸ÃÌþÊÇ_______(ÌîÐòºÅ)¡£
A£®ÍéÌþ B£®Ï©Ìþ C£®È²Ìþ D£®±½µÄͬϵÎï
¢Ú Êʵ±Ìõ¼þϺϳÉȼÁϼ״¼ºÍË®¡£ÔÚÌå»ýΪ2LµÄÃܱÕÈÝÆ÷ÖУ¬³äÈë2 mol CO2ºÍ6 mol H2£¬Ò»¶¨Ìõ¼þÏ·¢Éú·´Ó¦£ºCO2(g)£«3H2(g)
CH3OH(g)£«H2O(g)
¡÷H£½£49.0 kJ/mol¡£
²âµÃCO2(g)ºÍCH3OH(g)µÄŨ¶ÈËæÊ±¼ä±ä»¯ÈçͼËùʾ¡£
![]()
´Ó·´Ó¦¿ªÊ¼µ½Æ½ºâ£¬v(H2)£½______£»ÇâÆøµÄת»¯ÂÊ£½_______£»ÄÜʹƽºâÌåϵÖÐn(CH3OH)Ôö´óµÄ´ëÊ©ÓÐ______¡£
(3)È罫CO2ÓëH2 ÒÔ1:4µÄÌå»ý±È»ìºÏ£¬ÔÚÊʵ±µÄÌõ¼þÏ¿ÉÖÆµÃCH4¡£
ÒÑÖª£º
CH4 (g) + 2O2(g)
CO2(g)+
2H2O(l) ¦¤H1£½¨D 890.3 kJ/mol
H2(g) + 1/2O2(g)
H2O(l)
¦¤H2£½£285.8 kJ/mol
ÔòCO2(g)ÓëH2(g)·´Ó¦Éú³ÉCH4(g)ÓëҺ̬ˮµÄÈÈ»¯Ñ§·½³ÌʽÊÇ________¡£
(4)ijͬѧÓóÁµí·¨²â¶¨º¬ÓнϸßŨ¶ÈCO2µÄ¿ÕÆøÖÐCO2µÄº¬Á¿£¬¾²éµÃһЩÎïÖÊÔÚ20¡æµÄÊý¾ÝÈçÏÂ±í¡£
|
Èܽâ¶È(S)/g |
ÈܶȻý(Ksp) |
||
|
Ca(OH)2 |
Ba(OH)2 |
CaCO3 |
BaCO3 |
|
0.16 |
3.89 |
2.9¡Á10-9 |
2.6¡Á10-9 |
(˵Ã÷£ºKspԽС£¬±íʾ¸ÃÎïÖÊÔÚË®ÈÜÒºÖÐÔ½Ò׳Áµí)
ÎüÊÕCO2×îºÏÊʵÄÊÔ¼ÁÊÇ_________[Ìî¡°Ca(OH)2¡±»ò¡°Ba(OH)2¡±]ÈÜÒº£¬ÊµÑéʱ³ýÐèÒª²â¶¨¹¤Òµ·ÏÆøµÄÌå»ý(ÕÛËã³É±ê×¼×´¿ö)Í⣬»¹ÐèÒª²â¶¨__________¡£