ÌâÄ¿ÄÚÈÝ
ÒÑÖªA¡¢B¡¢C¡¢D¡¢E¡¢FÁùÖÖÔªËصÄÔ×ÓÐòÊýÒÀ´ÎµÝÔö£¬ AλÓÚÖÜÆÚ±íµÄsÇø£¬ÆäÔ×ÓÖеç×Ó²ãÊýºÍδ³É¶Ôµç×ÓÊýÏàͬ£»BµÄ»ù̬Ô×ÓÖеç×ÓÕ¼¾ÝÈýÖÖÄÜÁ¿²»Í¬µÄÔ×Ó¹ìµÀ£¬ÇÒÿÖÖ¹ìµÀÖеĵç×Ó×ÜÊýÏàͬ£»DÔ×ӵĺËÍâ³É¶Ôµç×ÓÊýÊÇδ³É¶Ôµç×ÓÊýµÄ3±¶;A¡¢EµÄÔ×ÓÐòÊýÏà²î10£¬F+µÄM²ãµç×ÓÈ«³äÂú¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺£¨´ðÌâʱ£¬A¡¢B¡¢C¡¢D¡¢E¡¢FÓÃËù¶ÔÓ¦µÄÔªËØ·ûºÅ±íʾ£©
£¨1£©CµÄ»ù̬Ô×ÓµÄÍâΧµç×ÓÅŲ¼Ê½Îª ,ÖÜÆÚ±íÖÐF
ÊôÓÚ Çø¡£
£¨2£©C¡¢D¡¢EÈýÔªËصĵ縺ÐÔÓÉ´óµ½Ð¡µÄ˳ÐòΪ£º £¬¼òµ¥Àë×Ӱ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòΪ£º ¡£
£¨3£©BD·Ö×ÓÖУ¬BÔ×ÓÓëDÔ×Ó¶¼´ïµ½8µç×ÓÎȶ¨½á¹¹£¬ÔòBDµÄµç×ÓʽÊÇ £»
£¨4£©BD2ÓëEDA·´Ó¦Ê±£¬Í¨¹ý¿ØÖÆ·´Ó¦ÎïµÄÎïÖʵÄÁ¿Ö®±È£¬¿ÉÒԵõ½²»Í¬µÄ²úÎÏàͬÌõ¼þÏ£¬ÔÚË®ÖÐÈܽâ¶È½ÏСµÄ²úÎïÊÇ £¨Ð´»¯Ñ§Ê½£©£¬ÆäÔÒòÊǸû¯ºÏÎïÒõÀë×Ó¼ä¿ÉÐγɶþ¾ÛÀë×Ó»ò¶à¾ÛÁ´×´Àë×Ó¡£¸Ã»¯ºÏÎïÒõÀë×ÓÄܹ»Ï໥µÞºÏµÄÔÒòÊÇ£º ¡£
£¨5£©B2D42£ºÍ £¨·Ö×Ó£©Êǵȵç×ÓÌ壬B2D42£Àë×Ó¾ßÓнÏÇ¿µÄ»¹ÔÐÔ£¬ËüÄÜʹËáÐÔKMnO4ÈÜÒºÍÊÉ«(»¹Ô²úÎïΪMn2+)£¬Ð´³ö±ä»¯µÄÀë×Ó·½³Ìʽ£º ¡£
£¨6£©ÓÒͼ·Ö±ðÊÇEºÍFµÄ¾§°û¡£¾§ÌåÖÐEºÍFµÄÅäλÊýÖ®±ÈΪ ¡£
£¨7£©ÏàͬÌõ¼þÏ£¬V1mLBD2ÓëV2mLCDµÄ»ìºÏÆøÌåͨ¹ý×ãÁ¿E2D2¹ÌÌåºó£¬ÆøÌåÌå»ý±äΪ(V1+V2)/2mL£¨²»¿¼ÂÇCDÓëE2D2µÄ·´Ó¦£©,ÔòV1ÓëV2µÄ¹ØϵÂú×㣺 ¡£
(1)2s22P 3 ds
(2)O£¾N£¾Na N 3£ £¾ O2££¾Na£«
(3)
(4)NaHCO3 HCO3£Àë×ÓÖ®¼ä´æÔÚÇâ¼ü
£¨5£©N2O4 5C2O42£+2MnO4£+16H+=10CO2¡ü+2Mn2++8H2O
(6)2:3
£¨7£©V1¡ÝV2
A¡¢Fe¡¢Cu¡¢Al¡¢Ag | B¡¢Al¡¢Cu¡¢Fe¡¢Ag | C¡¢Cu¡¢Ag¡¢Al¡¢Fe | D¡¢Ag¡¢Al¡¢Cu¡¢Fe |