ÌâÄ¿ÄÚÈÝ
ÏÂͼÖÐA~G¾ùΪÖÐѧ»¯Ñ§Öг£¼ûµÄÎïÖÊ£¬ËüÃÇÖ®¼äÓÐÈçÏÂת»¯¹Øϵ¡£³£ÎÂÏ£¬AΪ×ϺìÉ«½ðÊô¹ÌÌå,BΪ³£¼ûµÄÇ¿ËᣬGΪµØ¿ÇÖк¬Á¿×î¶àÔªËØ×é³ÉµÄÆø̬µ¥ÖÊ£»D¡¢F¶¼ÊÇ´óÆøÎÛȾÎÖ÷ÒªÀ´Ô´ÓÚÆû³µÎ²Æø£¬DΪÎÞÉ«ÆøÌ壬FΪºì×ØÉ«ÆøÌå¡£
Çë»Ø´ðÒÔÏÂÎÊÌ⣺
¢ÙDµÄ»¯Ñ§Ê½ÊÇ £»C+NaOHÉú³ÉµÄÀ¶É«³ÁµíÊÇ £¨Ìѧʽ£©£»
¢Ú¹¹³ÉGµ¥ÖʵÄÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪ £»
¢Ûд³öBµÄÏ¡ÈÜÒºÓëA·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º ¡£
Çë»Ø´ðÒÔÏÂÎÊÌ⣺
¢ÙDµÄ»¯Ñ§Ê½ÊÇ £»C+NaOHÉú³ÉµÄÀ¶É«³ÁµíÊÇ £¨Ìѧʽ£©£»
¢Ú¹¹³ÉGµ¥ÖʵÄÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪ £»
¢Ûд³öBµÄÏ¡ÈÜÒºÓëA·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º ¡£
¢ÙNO£» Cu(OH)2 ¢ÚµÚ¶þÖÜÆÚ¢öA×å¢Û3Cu+8HNO3(Ï¡)=3Cu(NO3)2+2NO¡ü+4H2O
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿