ÌâÄ¿ÄÚÈÝ

ijͬѧÓõ¨·¯¾§Ì壨CuSO4¡¤5H2O £©ÅäÖÆ0.40mol/LµÄCuSO4ÈÜÒº1000mL£¬
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ËùÐèÒÇÆ÷Ϊ£º(1000mL)ÈÝÁ¿Æ¿¡¢ÍÐÅÌÌìƽ¡¢Ò©³×¡¢ ½ºÍ·µÎ¹Ü ,»¹ÐèÒªÄÄЩ²£Á§ÒÇÆ÷²ÅÄÜÍê³É¸ÃʵÑ飬Çëд³ö£º¢Ù___________ £¬¢Ú___________¡¡¡¡¡¡¡¡   
£¨2£©Ð´³ö¸ÃʵÑé²½Öè  ¢Ù¼ÆËã  ¢Ú³ÆÁ¿µ¨·¯__________g  ¢Û  ___________  ¢ÜתÒÆ  ¢ÝÏ´µÓ²¢×ªÒÆ  ¢Þ¶¨ÈÝ  ¢ßÒ¡ÔÈ
£¨3£©ÏÂÁÐÇé¿ö¶ÔËùÅäÖƵÄCuSO4ÈÜҺŨ¶ÈÓкÎÓ°Ï죿£¨Óá°Æ«´ó¡±¡°Æ«Ð¡¡±¡°ÎÞÓ°Ï족Ìîд£©
A£®ÈÝÁ¿Æ¿ÓÃÕôÁóÏ´µÓºó²ÐÁôÓÐÉÙÁ¿µÄË®________________
B£®ËùÓùýµÄÉÕ±­¡¢²£Á§°ôδϴµÓ________________?
C£®¶¨ÈÝʱ¸©Êӿ̶ÈÏß________________?
£¨1£©ÉÕ±­   ²£Á§°ô
£¨2£©100.0g    Èܽ⣨²¢ÀäÈ´£©
£¨3£©ÎÞÓ°Ïì   Æ«Ð¡   Æ«¸ß
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨13·Ö£©ÊµÑéÊÒÓÃNa2CO3¡¤10H2O¾§ÌåÅäÖÆ240mL 0.1mol/L Na2CO3ÈÜÒº£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÓÃÍÐÅÌÌìƽ³ÆÈ¡Na2CO3¡¤10H2OµÄÖÊÁ¿Îª             g¡£
£¨2£©²Ù×÷ÖÐËùÐèÒÇÆ÷³ýÍÐÅÌÌìƽ¡¢ÉÕ±­¡¢²£Á§°ôÍ⣬»¹ÐèÒª            £¨ÌîÒÇÆ÷Ãû³Æ£©¡£
£¨3£©ÅäÖÆʱ£¬ÕýÈ·µÄ²Ù×÷˳ÐòÊÇ£¨ÓÃ×Öĸ±íʾ£¬Ã¿¸ö×ÖĸֻÄÜÓÃÒ»´Î£©           £»
A£®ÓÃÕôÁóˮϴµÓÉÕ±­¼°²£Á§°ô2-3´Î£¬Ï´µÓÒº¾ù×¢ÈëÈÝÁ¿Æ¿£¬Õñµ´
B£®ÓÃÍÐÅÌÌìƽ³ÆÁ¿ËùÐèµÄNa2CO3¡¤10H2O¾§Ì壬·ÅÈëÉÕ±­ÖУ¬ÔÙ¼ÓÈëÉÙÁ¿Ë®£¬Óò£Á§°ôÂýÂý½Á¶¯£¬Ê¹ÆäÍêÈ«Èܽâ
C£®½«ÒÑÀäÈ´µÄNa2CO3ÈÜÒºÑز£Á§°ô×¢ÈëÈÝÁ¿Æ¿ÖÐ
D£®½«ÈÝÁ¿Æ¿¸Ç½ô£¬Õñµ´Ò¡ÔÈ
E.¸ÄÓýºÍ·µÎ¹Ü¼ÓË®£¬Ê¹ÈÜÒº°¼ÒºÃæµÄ×îµÍµãÇ¡ºÃÓë¿Ì¶ÈÏßÏàÇÐ
F.¼ÌÐøÍùÈÝÁ¿Æ¿ÄÚСÐļÓË®£¬Ö±µ½ÒºÃæ½Ó½ü¿Ì¶ÈÏß1-2cm´¦
£¨4£©ÈÜҺעÈëÈÝÁ¿Æ¿Ç°Ðè»Ö¸´µ½ÊÒΣ¬ÕâÊÇÒòΪ                      £»
£¨5£©Èô³öÏÖÈçÏÂÇé¿ö£¬¶ÔËùÅäÈÜÒºµÄŨ¶È½«ÓкÎÓ°Ï죨Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£©£º
¢ÙûÓнøÐÐA²Ù×÷      £»
¢Ú ³ÆÁ¿Ê±£¬Na2CO3¡¤10H2OÒÑʧȥ²¿·Ö½á¾§Ë®      £»
¢Û Èô¶¨ÈÝʱ¸©Êӿ̶ÈÏß      £»
¢Ü ¶¨ÈÝÒ¡ÔÈʱ£¬·¢ÏÖÒºÃæϽµ£¬ÓÖ¼ÓË®ÖÁ¿Ì¶ÈÏß      £»
¢Ý ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»ºóûÓиÉÔï       ¡£
£¨11·Ö£©Ê¹ÓÃÆôÆÕ·¢ÉúÆ÷ÖÆÈ¡ÆøÌ壬¾ßÓÐËæʱ¿É¿ØÖÆ·´Ó¦½øÐкÍÍ£Ö¹µÄÓŵ㡣ij»¯Ñ§ÐËȤС×éÖÆ×÷ÁËÈçͼËùʾµÄ×°Ö㬴úÌæÆôÆÕ·¢ÉúÆ÷¡£
£¨1£©Í¼ÖÐAÒÇÆ÷µÄÃû³ÆÊÇ               £¬È±ÉÙµÄÒÇÆ÷ÊÇ          £¬
£¨2£©ÖÆ×÷BʹÓõÄÊÇ£¨    £©
A¡¢ÌúƬ   B¡¢ÂÁ²­    C¡¢Ö½Æ¬      D¡¢ËÜÁÏƬ
£¨3£©ÔÚ¸Ã×°ÖÃÖÐÓÃÏÂÁз´Ó¦ÖÆÆøÌ壬·´Ó¦Ô­Àí¿ÉÐУ¬ÇÒ¿ÉÄÜ´ïµ½ÉÏÊöÓŵãµÄÊÇ£¨   £©
A¡¢Na2CO3¡¤10H2O+HCl¡úCO2¡ü   B¡¢Cu+H2SO4¡úH2¡ü   C¡¢CaCO3+HNO3¡úCO2¡ü
£¨4£©ÈôÓøÃ×°ÖýøÐÐпÁ£ÓëÏ¡ÁòËá·´Ó¦ÖÆÈ¡ÇâÆøµÄʵÑ飻¶Ô×°ÖÃ×÷ÆøÃÜÐÔ¼ì²éµÄ·½·¨ÊÇ                                                                                                                                                    £¬
£¨5£©Ïò×°ÖÃÖмÓÈëпÁ£µÄ·½·¨ÊÇ                                                 ¡£
£¨6£©µ±Ð跴ӦֹͣʱµÄ²Ù×÷ºÍ·¢ÉúµÄÏÖÏóÊÇ                                       ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø