ÌâÄ¿ÄÚÈÝ
£¨¹²14·Ö£©ÏÂͼÊÇÖÐѧ»¯Ñ§Öг£¼ûÎïÖÊÖ®¼äµÄһЩ·´Ó¦¹Øϵ£¬ÆäÖв¿·Ö²úÎïδд³ö¡£³£ÎÂÏÂXÊǹÌÌ壬XÊÜÈÈ·Ö½âËùµÃÆøÌåÔÚ±ê¿öϵÄÌå»ý±ÈΪ1£º1£¬HΪµ»ÆÉ«·ÛÄ©£¬BºÍG³£ÎÂÏÂÊÇÒºÌ壬ÆäÓà¾ùΪÆøÌå¡£¸ù¾ÝͼÖйØϵÍƶϣº
£¨1£©»¯Ñ§Ê½X £»
£¨2£©AµÄµç×ÓʽΪ £»¿Õ¼ä¹¹ÐÍ £»
CµÄ½á¹¹Ê½Îª £»HËù°üº¬µÄ»¯Ñ§¼üÀàÐÍ ¡£
£¨3£©¹¤ÒµÉÏÖÆÈ¡AµÄ»¯Ñ§·´Ó¦·½³Ìʽ £»A¡úDµÄ»¯Ñ§·´Ó¦·½³Ìʽ £»
C+H¡úEµÄ»¯Ñ§·´Ó¦·½³Ìʽ £»G¡úDµÄÀë×Ó·´Ó¦·½³Ìʽ ¡£
£¨1£©NH4HCO3
£¨2£©Èý½Ç׶ÐÍ£»O=C=O£»Àë×Ó¼ü£¬·Ç¼«ÐÔ¹²¼Û¼ü
£¨3£©
2Na2O2+2CO2=2Na2CO3+O2; 3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O
½âÎö:

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿