ÌâÄ¿ÄÚÈÝ


ÏàͬζÈÏ£¬ÔÚÌå»ýÏàµÈµÄÈý¸öºãÈÝÃܱÕÈÝÆ÷Öз¢Éú¿ÉÄæ·´Ó¦£º

    N2(g)£«3H2(g)2NH3(g)    ¡÷H£½£­92.4 kJ/mol¡£

    ʵÑé²âµÃÆðʼ¡¢Æ½ºâʱµÄÓйØÊý¾ÝÈçÏÂ±í£º

ÈÝÆ÷±àºÅ

Æðʼʱ¸÷ÎïÖÊÎïÖʵÄÁ¿/mol

ƽºâʱ·´Ó¦ÖеÄÄÜÁ¿±ä»¯

N2

H2

NH3

¢Ù

1

3

0

·Å³öÈÈÁ¿a kJ

¢Ú

2

3

0

·Å³öÈÈÁ¿b kJ

¢Û

2

6

0

·Å³öÈÈÁ¿c kJ

ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ£¨   £©

A£®·Å³öÈÈÁ¿¹Øϵ£ºa < b < 92.4     B£®Èý¸öÈÝÆ÷ÄÚ·´Ó¦µÄƽºâ³£Êý£º¢Û>¢Ù>¢Ú

C£®´ïƽºâʱ°±ÆøµÄÌå»ý·ÖÊý£º¢Ù>¢Û   D£®N2µÄת»¯ÂÊ£º¢Ú>¢Ù>¢Û

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ij»¯Ñ§Ð¡×é²ÉÓÃÀàËÆÖÆÒÒËáÒÒõ¥µÄ×°ÖÃ(Èçͼ)£¬ÒÔ»·¼º´¼ÖƱ¸»·¼ºÏ©¡£

ÒÑÖª£º

ÃܶÈ/(g¡¤cm£­3)

ÈÛµã/¡æ

·Ðµã/¡æ

ÈܽâÐÔ

»·¼º´¼

0.96

25

161

ÄÜÈÜÓÚË®

»·¼ºÏ©

0.81

¡ª103

83

ÄÑÈÜÓÚË®

(1)ÖƱ¸´ÖÆ·

½«12.5 mL»·¼º´¼¼ÓÈëÊÔ¹ÜAÖУ¬ÔÙ¼ÓÈë1 mLŨÁòËᣬҡÔȺó·ÅÈëËé´ÉƬ£¬»ºÂý¼ÓÈÈÖÁ·´Ó¦ÍêÈ«£¬ÔÚÊÔ¹ÜCÄڵõ½»·¼ºÏ©´ÖÆ·¡£

¢ÙAÖÐËé´ÉƬµÄ×÷ÓÃÊÇ________£¬µ¼¹ÜB³ýÁ˵¼ÆøÍ⻹¾ßÓеÄ×÷ÓÃÊÇ________________________________________________________________¡£

¢ÚÊÔ¹ÜCÖÃÓÚ±ùˮԡÖеÄÄ¿µÄÊÇ______________________________________

__________________________________¡£

(2)ÖƱ¸¾«Æ·

¢Ù»·¼ºÏ©´ÖÆ·Öк¬Óл·¼º´¼ºÍÉÙÁ¿ËáÐÔÔÓÖʵȡ£¼ÓÈë±¥ºÍʳÑÎË®£¬Õñµ´¡¢¾²Öᢷֲ㣬»·¼ºÏ©ÔÚ________²ã(Ìî¡°ÉÏ¡±»ò¡°Ï¡±)£¬·ÖÒººóÓÃ________(ÌîÈë±àºÅ)Ï´µÓ¡£

a£®KMnO4ÈÜÒº¡¡b£®Ï¡H2SO4¡¡c£®Na2CO3ÈÜÒº

¢ÚÔÙ½«»·¼ºÏ©°´ÈçͼװÖÃÕôÁó£¬ÀäÈ´Ë®´Ó________¿Ú½øÈë¡£ÕôÁóʱҪ¼ÓÈëÉúʯ»Ò£¬Ä¿µÄÊÇ______________________________________________________

________________________________________________________________¡£

¢ÛÊÕ¼¯²úƷʱ£¬¿ØÖƵÄζÈÓ¦ÔÚ________×óÓÒ£¬ÊµÑéÖƵõĻ·¼ºÏ©¾«Æ·ÖÊÁ¿µÍÓÚÀíÂÛ²úÁ¿£¬¿ÉÄܵÄÔ­ÒòÊÇ________¡£

a£®ÕôÁóʱ´Ó70 ¡æ¿ªÊ¼ÊÕ¼¯²úÆ·

b£®»·¼º´¼Êµ¼ÊÓÃÁ¿¶àÁË

c£®ÖƱ¸´ÖƷʱ»·¼º´¼Ëæ²úÆ·Ò»ÆðÕô³ö

(3)ÒÔÏÂÇø·Ö»·¼ºÏ©¾«Æ·ºÍ´ÖÆ·µÄ·½·¨£¬ºÏÀíµÄÊÇ________¡£

a£®ÓÃËáÐÔ¸ßÃÌËá¼ØÈÜÒº¡¡b£®ÓýðÊôÄÆ¡¡c£®²â¶¨·Ðµã

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø