ÌâÄ¿ÄÚÈÝ

£¨1£©Ôڹ̶¨Ìå»ýµÄÃܱÕÈÝÆ÷ÖÐͨÈëN2ºÍH2£¬ÏÂÁÐÄÜ˵Ã÷´ïµ½Æ½ºâµÄÊÇ________¡£

A£®3v£¨N2£©£½v£¨H2£©
B£®¶ÏÁÑ1¸öN¡ÔNµÄͬʱ¶ÏÁÑ6¸öN¡ªH
C£®N2¡¢H2¡¢NH3µÄÎïÖʵÄÁ¿Ö®±ÈÊÇ1¡Ã3¡Ã2
D£®ÈÝÆ÷ÄÚÆøÌåµÄѹǿ²»±ä
E£®ÆøÌåµÄÃܶȲ»±ä
F£®ÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿²»±ä
£¨2£©ÔÚ2 LµÄÃܱÕÈÝÆ÷ÖÐͨÈë2 mol N2¡¢8 mol H2£¬5 minʱ´ïµ½Æ½ºâ£¬²âµÃNH3µÄÎïÖʵÄÁ¿ÊÇ2 mol£¬Ôòƽºâʱc£¨H2£©£½______________¡£

£¨1£©BDF¡¡£¨2£©2.5 mol/L

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ij»ðµç³§µÄÍÑÁòβÆøͨÈë±¥ºÍK2CO3ÈÜÒºÎüÊճغ󣬾­·Ö½â³ØÖƵô¿¾»µÄCO2£¬ÔÙÔںϳÉËþÓëH2·´Ó¦Éú³É¼×´¼¡£Æ乤ÒÕÒÕÁ÷³ÌʾÒâͼÈçÏÂ:

£¨1£©ÎüÊÕ³ØÖб¥ºÍK2CO3ÈÜÒºÎüÊÕCO2µÄÀë×Ó·½³ÌʽÊÇ                          ¡£
£¨2£©Á÷³ÌʾÒâͼÖÐÑ­»·Ê¹ÓõÄÎïÖÊÊÇ                        ¡£
£¨3£©300¡æʱ£¬ºÏ³ÉËþÖеķ´Ó¦ÎªCO2(g)£«3H2(g)CH3OH(g)£«H2O(g)£¬ÔÚÃܱÕÌõ¼þÏ£¬ÏÂÁÐʾÒâͼÄÜ˵Ã÷·´Ó¦½øÐе½t1ʱ¿Ìʱ´ïµ½Æ½ºâ״̬µÄÊÇ         (Ìî×ÖĸÐòºÅ)

£¨4£©ÀûÓúϳÉËþÖÐʧ»îºóµÄ¸õп´¥Ã½¿ÉÖƵú¬ÓÐCl- ºÍCrO42- µÄÈÜÒº£¬ÆäŨ¶È¾ùΪ0.01mol/L£¬Ïò¸ÃÈÜÒºÖÐÖðµÎ¼ÓÈë0.01mol/LµÄAgNO3ÈÜҺʱ£¬Ê×ÏȲúÉú³ÁµíµÄÒõÀë×ÓÊÇ      (ÒÑÖª:Ksp(AgCl)=1.56¡Á10-10£¬Ksp(Ag2CrO4)=9.0¡Á10-12)
£¨5£©ºÏ³ÉËþÖÐʧ»îµÄ¸õп´¥Ã½¿ÉÓÃÓÚÖƱ¸Ð¿Ã̵ç³Ø¡£ÔÚ¼îÐÔÌõ¼þÏ£¬¸Ãµç³ØµÄ×Ü·´Ó¦Îª£ºZn(s) £«2MnO2(s) £«H2O(l) = Zn(OH)2(s) £«Mn2O3(s) £¬¸Ãµç³ØÕý¼«µÄµç¼«·´Ó¦Ê½ÊÇ                   ¡£ÈôÓõç³Øµç½â(¶èÐԵ缫)×ãÁ¿µÄMg(NO3)2ºÍNaClµÄ»ìºÏÈÜÒº£¬µç½â¹ý³ÌÖÐÒõ¼«µÄÏÖÏóÊÇ                            ¡£

½«Ò»¶¨Á¿NO2ºÍN2O4µÄ»ìºÏÆøÌåͨÈëÌå»ýΪ2 LµÄºãÎÂÃܱÕÈÝÆ÷ÖУ¬¸÷ÎïÖÊŨ¶ÈËæʱ¼ä±ä»¯µÄ¹ØϵÈçͼ1Ëùʾ¡£

Çë»Ø´ð£º
(1)ͼlÖУ¬ÇúÏß________(Ìî¡°X¡±»ò¡°Y¡±)±íʾNO2Ũ¶ÈËæʱ¼äµÄ±ä»¯Çé¿ö£»Ç°10 minÄÚv(NO2)£½________mol/(L¡¤min)¡£
(2)ÏÂÁÐÑ¡ÏîÖв»ÄÜ˵Ã÷¸Ã·´Ó¦ÒѴﵽƽºâ״̬µÄÊÇ________(ÌîÑ¡Ïî×Öĸ)¡£

A£®ÈÝÆ÷ÄÚ»ìºÏÆøÌåµÄѹǿ²»Ëæʱ¼ä±ä»¯¶ø¸Ä±ä
B£®ÈÝÆ÷ÄÚ»ìºÏÆøÌåµÄÃܶȲ»Ëæʱ¼ä±ä»¯¶ø¸Ä±ä
C£®ÈÝÆ÷ÄÚ»ìºÏÆøÌåµÄÑÕÉ«²»Ëæʱ¼ä±ä»¯¶ø¸Ä±ä
D£®ÈÝÆ÷ÄÚ»ìºÏÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿²»Ëæʱ¼ä±ä»¯¶ø±ä»¯
(3)·´Ó¦½øÐе½10 minʱ£¬¹²ÎüÊÕÈÈÁ¿22.76 kJ£¬Ôò¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ_________________________________£»¸Ã·´Ó¦µÄƽºâ³£ÊýK£½________¡£
(4)·´Ó¦½øÐе½20 minʱ£¬ÔÙÏòÈÝÆ÷ÄÚ³äÈëÒ»¶¨Á¿NO2,10 minºó´ïµ½ÐµÄƽºâ£¬´Ëʱ²âµÃc(NO2)£½0.9 mol/L¡£
¢ÙµÚÒ»´Îƽºâʱ»ìºÏÆøÌåÖÐNO2µÄÌå»ý·ÖÊýΪ¦Ø1£¬´ïµ½ÐÂƽºâºó»ìºÏÆøÌåÖÐNO2µÄÌå»ý·ÖÊýΪ¦Ø2£¬Ôò¦Ø1________¦Ø2(Ìî¡°>¡±¡¢¡°£½¡±»ò¡°<¡±)£»
¢ÚÇëÔÚͼ2Öл­³ö20 minºó¸÷ÎïÖʵÄŨ¶ÈËæʱ¼ä±ä»¯µÄÇúÏß(ÇúÏßÉϱØÐë±ê³ö¡°X¡±ºÍ¡°Y¡±)¡£

Óõª»¯¹è(Si3N4)ÌÕ´É´úÌæ½ðÊôÖÆÔì·¢¶¯»úµÄÄÍÈȲ¿¼þ£¬ÄÜ´ó·ù¶ÈÌá¸ß·¢¶¯»úµÄÈÈЧÂÊ¡£¹¤ÒµÉÏÓû¯Ñ§ÆøÏà³Á»ý·¨ÖƱ¸µª»¯¹è£¬Æä·´Ó¦ÈçÏ£º
3SiCl4(g)£«2N2(g)£«6H2(g)Si3N4(s)£«12HCl(g)¡¡¦¤H<0
Íê³ÉÏÂÁÐÌî¿Õ£º
(1)ÔÚÒ»¶¨Î¶ÈϽøÐÐÉÏÊö·´Ó¦£¬Èô·´Ó¦ÈÝÆ÷µÄÈÝ»ýΪ2 L,3 minºó´ïµ½Æ½ºâ£¬²âµÃ¹ÌÌåµÄÖÊÁ¿Ôö¼ÓÁË2.80 g£¬ÔòH2µÄƽ¾ù·´Ó¦ËÙÂÊΪ________mol/(L¡¤min)£»¸Ã·´Ó¦µÄƽºâ³£Êý±í´ïʽK£½________¡£
(2)ÉÏÊö·´Ó¦´ïµ½Æ½ºâºó£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ________¡£
a£®ÆäËûÌõ¼þ²»±ä£¬Ñ¹Ç¿Ôö´ó£¬Æ½ºâ³£ÊýK¼õС
b£®ÆäËûÌõ¼þ²»±ä£¬Î¶ÈÉý¸ß£¬Æ½ºâ³£ÊýK¼õС
c£®ÆäËûÌõ¼þ²»±ä£¬Ôö´óSi3N4ÎïÖʵÄÁ¿Æ½ºâÏò×óÒƶ¯
d£®ÆäËûÌõ¼þ²»±ä£¬Ôö´óHClÎïÖʵÄÁ¿Æ½ºâÏò×óÒƶ¯
(3)Ò»¶¨Ìõ¼þÏ£¬ÔÚÃܱպãÈݵÄÈÝÆ÷ÖУ¬ÄܱíʾÉÏÊö·´Ó¦´ïµ½»¯Ñ§Æ½ºâ״̬µÄÊÇ________¡£
a£®3vÄæ(N2)£½vÕý(H2)
b£®vÕý(HCl)£½4vÕý(SiCl4)
c£®»ìºÏÆøÌåÃܶȱ£³Ö²»±ä
d£®c(N2)£ºc(H2)£ºc(HCl)£½1£º3£º6
(4)ÈôƽºâʱH2ºÍHClµÄÎïÖʵÄÁ¿Ö®±ÈΪm/n£¬±£³ÖÆäËûÌõ¼þ²»±ä£¬½µµÍζȺó´ïµ½ÐµÄƽºâʱ£¬H2ºÍHClµÄÎïÖʵÄÁ¿Ö®±È________m/n(Ìî¡°>¡±¡¢¡°£½¡±»ò¡°<¡±)¡£

»¯Ñ§·´Ó¦Ô­ÀíÔÚ¿ÆÑкÍÉú²úÖÐÓй㷺ӦÓá£
£¨1£©ÀûÓá°»¯Ñ§ÕôÆøתÒÆ·¨¡±Ìá´¿½ðÊôÎٵķ´Ó¦Ô­ÀíΪW(s)£«I2(g)WI2(g) (I)¡£¸Ã·´Ó¦ÔÚʯӢÕæ¿Õ¹ÜÖнøÐУ¬ÈçÏÂͼËùʾ£º

¢Ù·´Ó¦(I)µÄƽºâ³£Êý±í´ïʽK£½_______£¬ÈôK£½£¬ÏòijºãÈÝÃܱÕÈÝÆ÷ÖмÓÈë1mol I2(g)ºÍ×ãÁ¿W(s)£¬·´Ó¦´ïµ½Æ½ºâʱI2(g)µÄת»¯ÂÊΪ__________¡£
¢Ú·´Ó¦(I)µÄ¡÷H____0£¨Ìî¡°£¾¡±»ò¡°£¼¡±£©£¬ÉÏÊö·´Ó¦ÌåϵÖпÉÑ­»·Ê¹ÓõÄÎïÖÊÊÇ_________¡£
¢ÛÄܹ»ËµÃ÷ÉÏÊö·´Ó¦ÒѾ­´ïµ½Æ½ºâ״̬µÄÓÐ_________£¨ÌîÐòºÅ£©¡£
a£®I2ÓëWI2µÄŨ¶ÈÏàµÈ
b£®WµÄÖÊÁ¿²»Ôٱ仯
c£®ÈÝÆ÷ÄÚ»ìºÏÆøÌåµÄÃܶȱ£³Ö²»±ä
d£®µ¥Î»Ê±¼äÄÚ£¬½ðÊôÎÙÏûºÄµÄÎïÖʵÄÁ¿Óëµâ»¯ÎÙÉú³ÉµÄÎïÖʵÄÁ¿ÏàµÈ
£¨2£©25¡æʱ£¬NaHSO3µÄË®½âƽºâ³£Êý£½1.0¡Á10£­12mol/L£¬Ôò¸ÃζÈÏÂH2SO3HSO3£­£«H£«µÄµçÀë³£ÊýKa£½____mol/L£¬ÈôÏòH2SO3ÈÜÒºÖмÓÈëÉÙÁ¿µÄI2£¬ÔòÈÜÒºÖн«________£¨Ìî¡°Ôö´ó¡±¡¢¡°¼õС¡±»ò¡°²»±ä¡±£©¡£
£¨3£©Ö±½ÓÅŷź¬SO2µÄÑÌÆø»áÐγÉËáÓ꣬Σº¦»·¾³¡£ÓÃNa2SO3ÈÜÒºÎüÊÕSO2µÄ¹ý³ÌÖУ¬pHËæn£¨SO32£­£©£ºn(HSO3£­)±ä»¯¹ØϵÈçÏÂ±í£º

n(SO32£­): n ( HSO3£­)
91:9
1:1
1:91
pH(25¡æ)
8.2
7.2
6.2
 
µ±ÎüÊÕÒº³ÊÖÐÐÔʱ£¬ÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ_________________________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø