ÌâÄ¿ÄÚÈÝ

ÓлúÎïAÊÇÒ»ÖÖ¾üÓôßÀᵯµÄÖ÷ÒªÓÐЧ³É·Ö¡£¾­·ÖÎöAµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª161£¬³ýº¬ÓÐC¡¢HÔªËØÍ⣬Ëü»¹º¬ÓÐÒ»ÖÖ±×åÔªËØ£¬ÇÒ·Ö×ÓÖÐÖ»º¬ÓÐÒ»¸ö¼×»ù¡£»¯ºÏÎïA¡«FµÄת»¯¹ØϵÈçÏÂͼËùʾ£¬ÆäÖÐ×ãÁ¿µÄÐÂÖÆCu(OH)2Ðü×ÇÒºÓë1mol C·´Ó¦¿ÉÉú³É1mol Cu2O ºÍ1mol D£¬B1ºÍB2¾ùΪ½ÏÎȶ¨µÄ»¯ºÏÎïÇÒ»¥ÎªÍ¬·ÖÒì¹¹Ìå¡£

ÒÑÖª£º¢Ù+
¢ÚÒ»¸ö̼ԭ×ÓÉÏÁ¬ÓÐÁ½¸ö̼̼˫¼üµÄ½á¹¹£¨¡ªC£½C£½C¡ª£©²»Îȶ¨¡£
ÇëÍê³ÉÏÂÁÐÎÊÌ⣻
£¨1£©»¯ºÏÎïAº¬ÓеĹÙÄÜÍÅÊÇ                   ¡£B1µÄÏà¶Ô·Ö×ÓÖÊÁ¿ÊÇ           ¡£
£¨2£©¢Ù¡¢¢Ú¡¢¢ÛµÄ·´Ó¦ÀàÐÍ·Ö±ðÊÇ                                       ¡£
£¨3£©Ð´³öA¡¢FµÄ½á¹¹¼òʽ£º
A£®                               £»F£®                                ¡£
£¨4£©Ð´³öC¡úD·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
                                                                         ¡£
£¨5£©·ûºÏÏÂÁÐÌõ¼þµÄCµÄͬ·ÖÒì¹¹Ìå¹²ÓÐ________ÖÖ¡£
¢Ùº¬Óжþ¸ö¼×»ù£»¢Úº¬Óжþ¸öÈ©»ù¡£
 £¨1£©Ì¼Ì¼Ë«¼ü¡¢  -Br(äåÔ­×Ó)¡¢80  (ÿ¿Õ1·Ö£¬¹²3·Ö)
£¨2£©ÏûÈ¥·´Ó¦¡¢¼Ó³É·´Ó¦(»ò»¹Ô­·´Ó¦)¡¢õ¥»¯·´Ó¦(»òÈ¡´ú·´Ó¦)£¨3·Ö£¬Ã¿ÌîÒ»¸ö1·Ö£©
£¨3£©£¨2·Ö£©   £¨2·Ö£©
£¨4£©OHCCH2CHBrCH2COCH3£«2Cu(OH)2¡úHOOCCH2CHBrCH2COCH3£«Cu2O¡ý£«2H2O £¨2·Ö£©
£¨5£©5  £¨2·Ö£©

ÊÔÌâ·ÖÎö£ºÓÉÌâÖÐËù¸øÐÅÏ¢FµÃ·Ö×Óʽ¿ÉÖªAÖÐÓÐÒ»¸öBrºÍ6¸öC£¬·ÖÎöAµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª161£¬AΪC6H9Br£¬²»±¥ºÍ¶ÈΪ2£¬A±Ø¶¨ÊÇ»·×´»¯ºÏÎº¬ÓÐÒ»¸öË«¼ü£¬Ñõ»¯ºó½á¹¹ÖÐÓÐÒ»¸öôÊ»ù¿ÉÔÙÑõ»¯£¬ÍƵ㺠B1¡¢B2·Ö±ðΪ£º¡¢£»CΪ£ºCH3-CO-CH2-CH(Br)-CH2-CHO£»DΪ£ºCH3-CO-CH2-CH(Br)-CH2-COOH£»EΪ£ºCH3-CH(OH)-CH2-CH(Br)-CH2-COOH£»FΪ£º
£¨1£©»¯ºÏÎïAº¬ÓеĹÙÄÜÍÅÊÇ̼̼˫¼ü¡¢  -Br(äåÔ­×Ó)£»¡¢·Ö×ÓÁ¿Îª80¡£
£¨2£©·Ö±ðΪ£ºÏûÈ¥·´Ó¦¡¢¼Ó³É·´Ó¦(»ò»¹Ô­·´Ó¦)¡¢õ¥»¯·´Ó¦(»òÈ¡´ú·´Ó¦)¡£
£¨3£©AΪ£»FΪ¡£
£¨4£©·´Ó¦ÎªOHCCH2CHBrCH2COCH3£«2Cu(OH)2¡úHOOCCH2CHBrCH2COCH3£«Cu2O¡ý£«2H2O
£¨5£©¸ú¾ÝÌâÒâÖ÷Á´ÎªOHC-C-C-CHO£¬ÁíÍâÁ½¸ö-CH3ºÍÒ»¸öBr¹²ÓÐ5ÖÖÁ¬½Ó·½Ê½¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø