题目内容
化学反应N2+3H2 = 2NH3的能量变化如下图所示,该反应的热化学方程式是
A、N2(g)+3H2(g) = 2NH3(l) ⊿H = 2(a—b—c)kJ/mol
B、N2(g)+3H2(g) = 2NH3(g) ⊿H = 2(b—a)kJ/mol
C、N2(g)+H2(g) = NH3(l) ⊿H = (b+c—a)kJ/mol
D、N2(g)+ H2(g) =NH3(g) ⊿H = (a+b)kJ/mol [来源:Z.xx.k.Com][来源:ZXXK]
【答案】
A
【解析】
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