ÌâÄ¿ÄÚÈÝ

£¨14·Ö£©Ï±íÊÇÖÜÆÚ±íÖеÄÒ»²¿·Ö£¬¸ù¾Ýa¡ªnÔÚÖÜÆÚ±íÖеÄλÖ㬰´ÒªÇó»Ø´ðÎÊÌ⣺

 
¢ñA
¢òA
¢óA
¢ôA
¢õA
¢öA
¢÷A
0
1
a
 
 
2
 
 
 
b
c
 
d
e
3
f
g
h
i
j
k
m
n
(1)±íÖÐÔªËØ£¬Ö»Óиº¼Û¶øÎÞÕý¼ÛµÄÔªËØÊÇ       £¬Ñõ»¯ÐÔ×îÇ¿µÄµ¥ÖÊÊÇ         ¡££¨±¾Ð¡Ìâ¾ùÌîÎïÖʵÄÃû³Æ£©
(2)×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÖмîÐÔ×îÇ¿µÄÊÇ      £¬³ÊÁ½ÐÔµÄÊÇ    £¬Ð´³öËüÓëÇâÑõ»¯ÄÆ·´Ó¦µÄÀë×Ó·½³Ìʽ     ¡¡¡¡¡¡¡¡¡¡¡¡¡££¨±¾Ð¡Ìâ¾ùÓû¯Ñ§Ê½±íʾ£©
(3)ÔÚb¡¢c¡¢d¡¢f¡¢g¡¢hÖУ¬Ô­×Ӱ뾶´Ó´óµ½Ð¡µÄ˳ÐòΪµÄÊÇ     ¡££¨ÓÃÔªËØ·ûºÅ±íʾ£©¡£
(4) ±È½Ïk¡¢mµÄÆø̬Ç⻯ÎïµÄÎȶ¨ÐÔ         ¡££¨Óû¯Ñ§Ê½±íʾ£©

(1)·ú¡¢·úÆø(2)Na¡¢AL¡¢AL(OH)3 + OH-=Al3+ + 2H2O(3)Na>Mg>Al>C>N  (4)H2S<HCl

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ϱíΪԪËØÖÜÆÚ±íµÄÒ»²¿£¬Çë²ÎÕÕÔªËØ¢Ù-¢âÔÚ±íÖеÄλÖã¬Óû¯Ñ§ÓÃÓï»Ø´ðÏÂÁÐÎÊÌ⣺
×åÖÜÆÚ IA 0
1 ¢Ù ¢òA ¢óA ¢ôA ¢õA ¢öA ¢÷A
2 ¢Ú ¢Û ¢Ü ¢Ý
3 ¢Þ ¢ß ¢à ¢á  ¢â
£¨1£©Çëд³ö¢ÚµÄÔªËØ·ûºÅ
Be
Be

£¨2£©Çëд³ö¢ÛµÄ×î¸ß¼ÛÑõ»¯ÎïµÄµç×Óʽ
£®
£¨3£©±È½Ï¢Ý¡¢¢Þ¡¢¢àµÄÔ­×Ӱ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòΪ£¨ÓÃÔªËØ·ûºÅ±íʾ£©
Na£¾Al£¾F
Na£¾Al£¾F

£¨4£©±È½Ï¢Û¡¢¢Ü¡¢¢áµÄ×î¸ß¼Ûº¬ÑõËáµÄËáÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòÊÇ£¨ÓÃËáµÄ»¯Ñ§Ê½±íʾ£©
HNO3£¾H2CO3£¾H2SiO3£¨»òH4SiO4£©
HNO3£¾H2CO3£¾H2SiO3£¨»òH4SiO4£©
£®
£¨5£©Ð´³öÔÚÔªËØ¢Ù-¢âÖÐ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïµÄ×îÇ¿¼îÓë×îÇ¿º¬ÑõËáÖ®¼äµÄ»¯Ñ§·´Ó¦·½³Ìʽ
NaOH+HClO4¨TNaClO4+H2O
NaOH+HClO4¨TNaClO4+H2O

£¨6£©¢ß¢àÁ½ÔªËØÏà±È½Ï£¬½ðÊôÐÔ½ÏÇ¿µÄÊÇ
þ
þ
£¨ÌîÃû³Æ£©£¬¿ÉÒÔÑéÖ¤¸Ã½áÂÛµÄʵÑéÊÇ
£¨b£©£¨c£©
£¨b£©£¨c£©
£¨Ìî±àºÅ£©£®
£¨a£©½«ÔÚ¿ÕÆøÖзÅÖÃÒѾõÄÕâÁ½ÖÖÔªËصĿé×´µ¥ÖÊ·Ö±ð·ÅÈëÈÈË®ÖÐ
£¨b£©½«ÐÎ×´¡¢´óСÏàͬµÄÕâÁ½ÖÖÔªËصĵ¥ÖÊ·Ö±ðºÍͬŨ¶ÈµÄÑÎËá·´Ó¦
£¨c£©½«ÐÎ×´¡¢´óСÏàͬÕâÁ½ÖÖÔªËصĵ¥ÖÊ·Ö±ðºÍÈÈË®×÷Ó㬲¢µÎÈë·Ó̪ÈÜÒº
£¨d£©±È½ÏÕâÁ½ÖÖÔªËصÄÆø̬Ç⻯ÎïµÄÎȶ¨ÐÔ£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø