ÌâÄ¿ÄÚÈÝ

£¨5·Ö£©ÔÚÒ»¶¨Ìõ¼þÏ£¬¼×ÍéÓëÒ»Ñõ»¯Ì¼µÄȼÉÕµÄÈÈ»¯Ñ§·½³Ìʽ·Ö±ðΪ£º
CH4(g)+2O2(g)=CO2(g)+ 2H2O(l) ¡÷H =-890kJ/mol
2CO(g) + O2(g)= 2CO2(g)  ¡÷H =-566.0kJ/mol
Ò»¶¨Á¿µÄ¼×ÍéÓëÒ»Ñõ»¯Ì¼µÄ»ìºÏÆøÍêȫȼÉÕʱ£¬·Å³öµÄÈÈÁ¿Îª262.9 kJ£¬Éú³ÉµÄCO2ÓùýÁ¿µÄ±¥ºÍʯ»ÒË®ÍêÈ«ÎüÊÕ£¬¿ÉµÃµ½50g°×É«³Áµí¡£Çó»ìºÏÆøÌåÖм×ÍéºÍÒ»Ñõ»¯Ì¼µÄÌå»ý±È¡£
2£º3
ÓÉËù¸øÈÈ»¯Ñ§·½³Ìʽ¿ÉÖª£¬¼×ÍéÓëÒ»Ñõ»¯Ì¼µÄȼÉÕÈÈ·Ö±ðΪ890kJ/mol¡¢283kJ/mol
Éè»ìºÏÆøÌåÖм×ÍéÓëÒ»Ñõ»¯Ì¼µÄÎïÖʵÄÁ¿·Ö±ðΪx¡¢y
50g°×É«³Áµí¼´0.5molµÄ̼Ëá¸Æ£¬ÓÉ̼µÄÊغã¿ÉÖª£ºx+y=0.5
Á½ÆøÌåȼÉշųöµÄÈÈÁ¿¿ÉÁеÈʽ£º890x+283y=262.9
½âµÃ£ºx=0.2mol    y=0.3mol
¹Ê»ìºÏÆøÌåÖм×ÍéºÍÒ»Ñõ»¯Ì¼µÄÌå»ý±ÈΪ2:3
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨12·Ö£©³£Î³£Ñ¹Ï£¬¶ÏÁÑ1mol£¨ÀíÏ룩ÆøÌå·Ö×Ó»¯Ñ§¼üËùÎüÊÕµÄÄÜÁ¿»òÐγÉ1mol  £¨ÀíÏ룩ÆøÌå·Ö×Ó»¯Ñ§¼üËù·Å³öµÄÄÜÁ¿³ÆΪ¼üÄÜ¡£Ï±íÊÇһЩ¼üÄÜÊý¾Ý£¨µ¥Î»ÎªKJ¡¤mol-1£©
»¯Ñ§¼ü
¼üÄÜ
»¯Ñ§¼ü
¼üÄÜ
»¯Ñ§¼ü
¼üÄÜ
C£­F
427
C£­Cl
330
C£­I
218
H£­H
436
S£½S
255
H£­S
339
 »Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÓɱíÖÐÊý¾Ý¹æÂÉÔ¤²âC£­Br¼üµÄ¼üÄÜ·¶Î§£º
_________   <C£­Br¼üÄÜ<__________  
(2)ÈÈ»¯Ñ§·½³Ìʽ2H2(g)£«S2(g) =2H2S(g)£»¡÷H= QKJ¡¤mol£­1£»ÔòQ=                   
(3) ÒÑÖªÏÂÁÐÈÈ»¯Ñ§·½³Ìʽ£º
O2 (g) = O+2(g) + e¡ª                              ¡÷H1=" +1175.7" kJ¡¤mol-1
PtF6(g) + e¡ª= PtF6¡ª(g)                ¡÷H2="-771.1" kJ¡¤mol-1
O2+PtF6¡ª(s) = O2+(g) + PtF6¡ª(g)         ¡÷H3=" +482.2" kJ¡¤mol-1
 Ôò·´Ó¦O2(g) +             (g) = O2+PtF6¡ª (s)µÄ¡÷H="___________________" kJ¡¤mol-1¡£
(4)ÒÑÖª½ð¸ÕʯºÍʯī·Ö±ðÔÚÑõÆøÖÐÍêȫȼÉÕµÄÈÈ»¯Ñ§·½³ÌʽΪ£º
C£¨½ð¸Õʯ,s£©+O2(g) £½CO2(g) ¡÷H=£­395.4 kJ?mol£­1
C(ʯī,s)+O2(g)£½CO2(g)       ¡÷H=£­393.5 kJ?mol£­1
Ôòʯīת»¯Îª½ð¸ÕʯʱµÄÈÈ»¯Ñ§·½³ÌʽΪ                                        
ÓÉ´Ë¿´À´Ì¼µÄÕâÁ½ÖÖͬËØÒìÐÎÌåÖиüÎȶ¨µÄΪ            ¡¡¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø