ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Ä³Î¶ÈÏ£¬Ag2SO4ÔÚË®ÖеijÁµíÈܽâƽºâÇúÏßÈçͼËùʾ¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
A£®aµã±íʾAg2SO4µÄ²»±¥ºÍÈÜÒº£¬¼ÓÈëNa2SO4¹ÌÌå²»ÄÜʹÈÜÒºÓÉaµã±äµ½bµã
B£®aµã±íʾAg2SO4µÄ²»±¥ºÍÈÜÒº£¬Õô·¢¿ÉÒÔʹÈÜÒºÓÉaµã±äµ½cµã
C£®0.04 mol¡¤L£1µÄAgNO3ÈÜÒºÓë0.2 mol¡¤L£1µÄNa2SO4ÈÜÒºµÈÌå»ý»ìºÏÓÐAg2SO4³ÁµíÉú³É
D£®Ag2SO4µÄÈܶȻý³£Êý(Ksp)Ϊ1¡Á10£3
¡¾´ð°¸¡¿C
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£ºA£®aµã±íʾµÄAg2SO4²»±¥ºÍÈÜÒº£¬µ±¼ÓÈëNa2SO4¹ÌÌåʹSO42£Å¨¶ÈÔö´ó£¬ÄÜʹÈÜÒºÓÉaµã±äµ½bµã£¬¹ÊA´íÎó£»B£®ÒòΪÔÚÕô·¢¹ý³ÌÈÜÒºÖÐÁ½ÖÖÀë×ÓµÄŨ¶È¶¼Ôö¼Ó£¬¹ÊÕô·¢²»ÄÜʹÈÜÒºÓÉaµã±äµ½cµã£¬¹ÊB´íÎó£»C£®0.04 mol¡¤L£1µÄAgNO3ÈÜÒºÓë0.2 mol¡¤L£1µÄNa2SO4ÈÜÒºµÈÌå»ý»ìºÏAg£«Å¨¶ÈΪ0.02mol¡¤L£1£¬SO42£Å¨¶ÈΪ0.1mol¡¤L£1£¬ÔòQ=0.022¡Á0.1£½4¡Á10£5£¾Ksp £¬Òò´ËÓгÁµíÉú³É£¬¹ÊCÕýÈ·£»D£®ÓÉͼÏó¿ÉÖª£¬µ±c(SO42£)=5¡Á10-2mol/Lʱ£¬c(Ag£«)=2¡Á10-2mol/L£¬ÔòKsp=c2(Ag£«)¡Ác(SO42£)=2¡Á10-5£¬¹ÊD´íÎó£»¹ÊÑ¡C¡£