ÌâÄ¿ÄÚÈÝ

ijÈÜÒº¿ÉÄܺ¬ÓÐÏÂÁÐÀë×ÓÖеļ¸ÖÖ(²»¿¼ÂÇÈÜÒºÖÐ΢Á¿µÄH£«ºÍOH£­)£ºNa£«¡¢NH4+¡¢SO42¡ª¡¢CO32¡ª¡¢NO3¡ª¡£È¡200 mL¸ÃÈÜÒº£¬µÈÌå»ý·Ö³ÉÁ½·Ý£¬·Ö±ð×öÏÂÁÐʵÑé¡£
ʵÑéÒ»£ºµÚÒ»·Ý¼ÓÈë×ãÁ¿Éռ¼ÓÈÈ£¬²úÉúµÄÆøÌåÔÚ±ê×¼×´¿öÏÂΪ224 mL¡£
ʵÑé¶þ£ºµÚ¶þ·ÝÏȼÓÈë×ãÁ¿µÄÑÎËᣬÎÞÏÖÏó£¬ÔÙ¼ÓÈë×ãÁ¿BaCl2ÈÜÒº£¬µÃ³Áµí2.33 g¡£
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ(¡¡¡¡)
A£®¸ÃÈÜÒº¿ÉÄܺ¬ÓÐNa£«
B£®¸ÃÈÜÒºÒ»¶¨º¬ÓÐNH4+¡¢SO42¡ª¡¢CO32¡ª¡¢NO3¡ª
C£®¸ÃÈÜÒºÒ»¶¨²»º¬ÓÐNO3¡ª
D£®¸ÃÈÜÒºÒ»¶¨º¬ÓÐNa£«£¬ÇÒc(Na£«)¡Ý0.1 mol¡¤L£­1
¡¡D
¡¡ÊµÑéÒ»Ö¤Ã÷ÈÜÒºÖк¬ÓÐNH4+£¬ÇÒÎïÖʵÄÁ¿Îª0.01 mol£¬c(NH4+)£½0.1 mol¡¤L£­1£»ÊµÑé¶þ£ºµÚ¶þ·ÝÏȼÓÈë×ãÁ¿µÄÑÎËᣬÎÞÏÖÏó£¬ÔòÒ»¶¨²»º¬ÓÐCO32¡ª£¬ÔÙ¼Ó×ãÁ¿µÄBaCl2ÈÜÒº£¬µÃ¹ÌÌå2.33 g£¬Ö¤Ã÷Ò»¶¨º¬ÓÐSO42¡ª£¬ÇÒÎïÖʵÄÁ¿Îª0.01 mol£¬c(SO42¡ª)£½0.1 mol¡¤L£­1£»¸ù¾ÝÈÜÒº³ÊµçÖÐÐÔ£¬ÔòÒ»¶¨º¬ÓÐNa£«¡£ÊÇ·ñº¬ÓÐNO3¡ªÎÞ·¨Åжϣ¬c(Na£«)¡Ý0.1 mol¡¤L£­1£¬DÕýÈ·¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø