ÌâÄ¿ÄÚÈÝ

˳¶¡Ï©¶þËá¶þ¼×õ¥ÊÇÒ»ÖÖÖØÒªµÄÓлú»¯¹¤Ô­ÁÏ£¬¹ã·ºÓ¦ÓÃÓÚÍ¿ÁÏ£¬ÓÍÆᣬɱ³æ¼ÁÓÈÆäÊÇÔÚË®´¦Àí¼ÁµÈ·½Ãæ¡£ÏÂÃæÊÇÀûÓÃʯÓͲúÆ·MºÏ³É˳¶¡Ï©¶þËá¶þ¼×õ¥µÄ²¿·Ö¹ý³Ì

Öмä²úÎïA                       Ë³¶¡Ï©¶þËá¶þ¼×õ¥

 

£¨1£©ÒÑÖªÌþMµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª78£¬·Ö×ÓÄÚº¬Ì¼Á¿Îª92.3£¥£¬ËùÓÐC¡ªH¼üºÍ̼̼¼üÀàÐÍÏàͬ£¬»¯ºÏÎïMµÄ»¯Ñ§Ê½Îª                                                                    
£¨2£©¼ìÑéÖмä²úÎïAº¬ÓеĹÙÄÜÍÅΪ                                                (ÌîÃû³Æ)    
£¨3£©ÔÚÉÏÊöÉú²úµÄ²úÆ·Öеõ½ÊÇ˳¶¡Ï©¶þËá¶þ¼×õ¥´ÖÆ·£¨´¿¶È¡Ü90%£©£¬¼ìÑé˳¶¡Ï©¶þËá¶þ¼×õ¥»¯Ñ§´¿£¨´¿¶È¡Ý98.5%£©ºÍ´Ö²úÆ·µÄ·½·¨                                                  
(4)д³öÓÉÖмä²úÎïAºÏ³É˳¶¡Ï©¶þËá¶þ¼×õ¥µÄ·½³Ìʽ                                         
£¨5£©Öмä²úÎïAºÍ×ãÁ¿µÄH2·´Ó¦ºó£¬¿ÉµÃÓлúÎïB£¨C4H10O4£©£¬Ð´³öBÊôÓÚõ¥ÀàµÄ¿ÉÄܽṹ¼òʽ      
                                                           
(1)C6H6(2)̼̼˫¼ü õ¥»ù(3)·Ö±ðÈ¡ÉÙÁ¿´ÖÆ·ºÍ´¿Æ·ÓÚÊԹܣ¬·Ö±ð¼ÓÈëNaHCO3ÈÜÒº£¬ÈôÊÔ¹ÜÖÐÓÐÆøÅݲúÉú£¬ÔòÔ­ÊÔ¼ÁΪ´ÖÆ·¡£
(4)                                                     
(5)£»
±¾Ì⿼²éÓлúºÏ³É¡££¨1£©ÌþMÖÐ̼µÄÖÊÁ¿Îª78¡Á92.3£¥=72£¬Ì¼Ô­×Ó¸öÊýΪ=6£¬È»ºóͨʽCxHyÇó³öÇâÔ­×Ó¸öÊýΪ6£¬MµÄ·Ö×ÓʽΪC6H6£»£¨3£©ÒÀ¾ÝÌâÒâ¿ÉÖª£¬´ÖÆ·ºÍ´¿Æ·µÄÇø±ðÔÚÓÚ´ÖÆ·Öк¬ÓÐôÈ»ù£¬¶ø˳¶¡Ï©¶þËá¶þ¼×õ¥»¯Ñ§´¿ÖÐÖ»ÓÐõ¥»ù£¬ËùÒÔ¿ÉÒÔÀûÓÃôÈ»ùÓëNaHCO3·´Ó¦²úÉúÆøÌåÀ´¼ìÑ飻£¨4£©NΪ¼×´¼£¬¼´Îª¼×´¼ÓëÖмä²úÎïA·¢Éúõ¥»¯·´Ó¦£»£¨5£©
Öмä²úÎïAºÍ×ãÁ¿µÄH2·´Ó¦ºó£¬Éú³ÉB£¬BµÄ·Ö×ÓʽΪ£¬õ¥Àà½á¹¹¿ÉÄÜÓУºHCOOCH2CH2COOCH3¡¢CH3COOCH2COOCH3¡¢CH3CH2COOCOOCH3¡¢HCOOCH2COOCH2CH3¡¢CH3COOCOOCH2CH3µÈ¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
Ñо¿Ä³Ò»»¯Ñ§·´Ó¦µÄʵÑé×°ÖÃÈçÏÂͼËùʾ£º

A¡«FÊôÓÚÏÂÁÐÎïÖÊÖеÄÁùÖÖÎïÖÊ£ºÅ¨ÁòËᡢŨÑÎËᡢŨ°±Ë®¡¢Ï¡ÁòËᡢϡÑÎËᡢϡ·úË®¡¢Ë®¡¢Ð¿Á£¡¢Í­Æ¬¡¢Ê³ÑΡ¢¸ßÃÌËá¼Ø¡¢ÂÈ»¯¸Æ¡¢Ñõ»¯¸Æ¡¢ËÄÑõ»¯ÈýÌú¡¢Ñõ»¯Ìú¡¢Ñõ»¯Í­¡¢ÇâÆø¡¢¶þÑõ»¯Ì¼¡¢¶þÑõ»¯µª¡¢Ò»Ñõ»¯Ì¼¡¢ÂÈÆø¡¢ÂÈ»¯Çâ¡¢°±Æø¡¢µªÆø¡¢ÑõÆø¡£
ʵÑéÏÖÏó£»
£¨1£©DÎïÖÊÓɺÚÉ«±äΪºìÉ«
£¨2£©ÎÞË®ÁòËáÍ­·ÛÄ©·ÅÈëÎÞɫ͸Ã÷µÄEÖеõ½À¶É«ÈÜÒº
£¨3£©µãȼµÄþÌõÉìÈëÎÞÉ«ÎÞζµÄFÖУ®Ã¾Ìõ±íÃæÉú³ÉÒ»ÖÖ»Ò»ÆÉ«¹ÌÌåÎïÖÊ¡£½«¸Ã·¢»ÆÉ«ÎïÖÊ·ÅÈëË®ÖУ¬ÓÐÆøÌå·Å³ö£¬¸ÃÆøÌå¾ßÓд̼¤ÐÔÆøζ¡£²¢ÄÜʹÈóʪµÄºìɫʯÈïÊÔÖ½±äÀ¶¡£Í¨¹ý·ÖÎö»Ø´ð£º
l¡¢Ð´³öA¡«FµÄÎïÖÊÃû³Æ£º
A              £¬B              £¬C             £¬D              £¬E            £¬F             ¡£
2¡¢Ð´³öÓйصĻ¯Ñ§·½³Ìʽ£º
AÓëB                                       £»
CÓëD                                       £»
EÓëÎÞË®ÁòËáÍ­                              £»
FÓëMg                                                  £»
FÓëMgµÄ·´Ó¦²úÎïÓëË®                                               ¡£
¹ýÑõ»¯ÇâÊÇÒ»ÖÖÎÞɫ͸Ã÷µÄÎÞ¶¾ÒºÌ壬ÊÇÖØÒªÎÞ»ú»¯¹¤²úÆ·¡£ÊÔ̽¾¿ÏÂÁÐÎÊÌâ

£¨1£©¹ýÑõ»¯Çâ×îÊʺÏÌùÉϵÄÒ»¸ö±êÇ©ÊÇ             ¡£

   A               B               C                D

 

 
£¨2£©¹ýÑõ»¯ÇâµÄÖƱ¸·½·¨ºÜ¶à£¬ÏÂÁз½·¨ÖÐÔ­×ÓÀûÓÃÂÊ×î¸ßµÄÊÇ£º           ¡£
A£® BaO 2 + H2SO 4 ="==" BaSO4 ¡ý + H2O2
B£® 2NH4HSO4 (NH4)2S2O8 + H2¡ü£¬
È»ºóË®½â (NH4)2S2O8 + 2H2O =2NH4HSO4 + H2O2¡£
C£®CH3CHOHCH3+O2¡úCH3COCH3+H2O2
D£®ÒÒ»ùÝìõ«·¨£º
£¨3£©¼îÐÔÇâÑõȼÁϵç³Ø¹¤×÷ʱ¿É²úÉú¹ýÑõ»¯Ç⣨¼ûÏÂ×óͼ£©£¬Õý¼«º¬Ì¼£¨Carbon£©µÄÖÊÁ¿´óС¶Ô²úÉú¹ýÑõ»¯ÇâµÄŨ¶È£¨concentration£©ÓÐÓ°Ï죨ÆäÓ°ÏìÇúÏßÈçÏÂÓÒͼ£©¡£
     
ÏÂÁÐ˵·¨ÕýÈ·µÄÓР           ¡£
A£®¿ªÊ¼Ê±ËÙÂʾù½ÏÂý£¬ËµÃ÷µç¼«ÓÐÒ»¸ö»î»¯µÄ¹ý³Ì
B£®Ò»¶Îʱ¼äºó£¬ËÙÂÊÓÖÔÙ´Îƽ»º£¬ËµÃ÷Éú³ÉÓë·Ö½âÖð½¥Ç÷Ïòƽºâ
C£®Õý¼«ÊÒÁ÷³öÒº¾­Ëữºó¿É·ÖÀë³ö¹ýÑõ»¯Çâ
D£®Õý¼«º¬Ì¼µÄÖÊÁ¿ÒÔ0.2gÊÊÒË
£¨4£©¹ýÑõ»¯Çâ×÷ΪһÖÖÂÌÉ«Ñõ»¯¼ÁÓй㷺ӦÓã¬Çëд³öÏÂÁз´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
¢ÙÔÚ¹ýÑõ»¯Çâ×÷ÓÃÏ£¬Í­ÓëÏ¡ÁòËáÖÆÁòËáÍ­£º                      ¡£
¢ÚÓÃTi-Si·Ö×Óɸ×÷´ß»¯¼Á£¬¼×±½±»¹ýÑõ»¯ÇâÑõ»¯Îª¼ä-¼×±½·Ó£º           ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø