ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿25¡æʱ£¬ÔÚ´×ËáºÍ´×ËáÄÆ»ìºÏÈÜÒºÖÐÓÐc(CH3COOH)+c(CH3COO¨D)=0.1mol/LÇÒc(CH3COOH)¡¢c(CH3COO¨D)ÓëpHµÄ¹ØϵÈçͼ¡£ÓйØÀë×ÓŨ¶ÈÐðÊöÕýÈ·µÄÊÇ
A.pH=3.5ÈÜÒºÖУºc(Na£«)+c(H£«)£c(OH¨D)+c(CH3COOH) =0.1mol/L
B.pH=5.5ÈÜÒºÖУºc(CH3COOH)£¾c(CH3COO¨D)£¾c(H£«)£¾c(OH¨D)
C.Wµã±íʾÈÜÒºÖУºc(Na£«)+c(H£«) =c(CH3COO¨D)+c(OH¨D)
D.ÏòWµãËù±íʾÈÜÒºÖÐͨÈë0.05molHClÆøÌå(ÈÜÒºÌå»ý±ä»¯¿ÉºöÂÔ)£ºc(H£«)=c(CH3COOH)+c(OH¨D)
¡¾´ð°¸¡¿AC
¡¾½âÎö¡¿
¸ù¾ÝͼÏóÖª£¬Ëæ×ÅÈÜÒºpHÔö´ó£¬ÔòÈÜÒºÖд×ËáŨ¶È½µµÍ¡¢´×Ëá¸ùÀë×ÓŨ¶ÈÔö´ó£¬ÔòʵÏßÊÇ´×Ëá¸ùÀë×ÓŨ¶È¡¢ÐéÏßÊÇ´×ËáŨ¶È±ä»¯¡£
A.pH=3.5µÄÈÜÒºÖдæÔÚµçºÉÊغ㣬¸ù¾ÝµçºÉÊغã¿ÉÖª£ºc(Na£«)+c(H£«)=c(OH¨D)+ c(CH3COO¨D)£¬ÔÙ¸ù¾ÝÒÑÖªÌõ¼þc(CH3COOH)+c(CH3COO¨D)=0.1mol/L£¬¿ÉÖªc(Na£«)+c(H£«)£c(OH¨D)+c(CH3COOH) =0.1mol/L£¬¹ÊAÕýÈ·£»
B.¸ù¾ÝͼÏñ¿ÉÖª£¬µ±pH=5.5ʱ£¬c£¨CH3COOH£©<c£¨CH3COO-£©£¬¹ÊB´íÎó£»
C.ÈÜÒºÖдæÔÚµçºÉÊغãc(Na£«)+c(H£«)=c(OH¨D)+ c(CH3COO¨D)£¬¹ÊCÕýÈ·£»
D.¸ù¾ÝÎïÁÏÊغãÓÐ c£¨CH3COOH£©+c£¨CH3COO-£©=0.1molL-1£¬ÓɵçºÉÊغãÓÐc£¨Na+£©+c£¨H+£©=c£¨CH3COO-£©+c£¨OH-£©+c£¨Cl-£©£¬¹ÊD´íÎó£»
´ð°¸£ºAC