ÌâÄ¿ÄÚÈÝ

£¨12·Ö£©¹¤ÒµÉÏÉú²ú¸ßÂÈËᣨ·Ðµã£º90oC£©Ê±»¹Í¬Ê±Éú²úÁËÑÇÂÈËáÄÆ£¬Æä¹¤ÒÕÁ÷³ÌÈçÏ£º

£¨1£©ÀäÈ´¹ýÂ˵ÄÄ¿µÄÊǽµµÍNaHSO4µÄ          ²¢·ÖÀë³öNaHSO4¾§Ìå¡£
£¨2£©·´Ó¦Æ÷2Öз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                  ¡£SO2µÄ×÷ÓÃÊÇ×÷      ¼Á¡£
£¨3£©Ñ­»·Ê¹ÓõÄÎïÖÊÊÇ              ¡£
£¨4£©¿ÉÒÔͨ¹ýÕôÁóÂËÒºµÄ·½·¨µÃµ½¸ßÂÈËáµÄÔ­Òò¿ÉÄÜÊÇ                            ¡£
£¨5£©¹¤ÒµÉÏÓò¬×÷Ñô¼«¡¢Í­»òÒø×÷Òõ¼«µç½âÑÎËáÒ²¿ÉÖÆµÃ¸ßÂÈËᣬÔÚÑô¼«Çø¿ÉµÃµ½20%µÄ¸ßÂÈËᡣд³öÑô¼«µÄµç¼«·´Ó¦Ê½£¨ÆäÖÐÑÎËáÓë¸ßÂÈËáÒÔ»¯Ñ§Ê½³öÏÖ£©                            ¡£

£¨12·Ö£©£¨1£©Èܽâ¶È£¨2·Ö£©£¨2£©2ClO2£«SO2£«4OH£­£½2ClO2£­£«SO42£­£«2H2O£»£¨2·Ö£©»¹Ô­£¨2·Ö£©
£¨3£©H2SO4£¨2·Ö£©  £¨4£©¸ßÂÈËáµÄ·Ðµã±È½ÏµÍ£¬ÈÝÒ×´ÓÈÜÒºÖÐÒݳö£»£¨2·Ö£©
£¨5£©Ñô¼«·´Ó¦Ê½  HCl+ 4H2O -8e¡ª= HClO4 + 8H+¡££¨2·Ö£©

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø